Category: Class 5

Students can Download Maths Chapter 3 Mental Arithmetic Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 3 Mental Arithmetic

KSEEB Class 5 Maths Mental Arithmetic Revision Exercise

I. Round off each of the following numbers to nearest thousands place:

1. 7,547

7,547 lie between 7000 and 8000
Replace by zero

2. 3,469
3,469 lie between 2000 and 3000
Replace by zero

3. 15,238
15,038
Replace by zero

4. 32,658
32,658
Replace by zero

II. Round off each of the following numbers to nearest ten thousands place:

1. 26,674
26,674
Replace to zero

2. 32,464
32,464
Replace to zero

3. 46,379
46,379
Replace to zero

4. 53,668
53,668
Replace to zero

III. Estimate sum of the following by rounding off to nearest thousands place:

1. 42,125 + 35,637
42,125 is rounded off to nearest thousand – 42,000
35,637 is rounded off to nearest thousand – 36,000

Estimate sum is 78,000
Verification by actual addition – 42125

2. 54,837 + 41,354
54,837 is rounded off to nearest thousand – 55,000
41,354 is rounded offto nearest thousand – 41,000

Estimate sum is 96,000
Verification by actual addition

3. 33,231 + 20,097
33,321 is rounded off to nearest thousand – 33,000
20,097 is rounded off to nearest thousand – 20,000

Estimate sum is 53,000
Verification by actual addition

4. 47,463 + 41,541
47,463 is rounded off to nearest thousand – 47,000
41,541 is rounded off to nearest thousand – 42,000

Estimate sum is 89,000
Verification by actual addition

IV. Estimate the sum of the following by rounding off to nearest ten thousands place:

1. 56,256 + 24,872
56,256 is rounded off to nearest ten thousand – 55,000
24,872 is rounded off to nearest ten thousand – 25,000

Estimate sum is 80,000
Verification by actual addition

2. 47,671 + 28,745
47,671 is rounded off to nearest ten thousand – 50,000
28,745 is rounded off to nearest ten thousand – 30,000

Estimate sum is 80,000
Verification by actual addition

3. 32,184 + 45,138
32,184 is rounded off to nearest ten thousand – 30,000
45,138 is rounded off to nearest ten thousand – 50,000

Estimate, sum is 80,000
Verification by actual addition

4. 15,025 + 40,165
15,025 is rounded off to nearest ten thousand – 20,000
40,165 is rounded off to nearest ten thousand – 40,000

Estimate sum is 60,000

V. Estimate the difference of the following by rounding off to nearest thousands place:

1. 65,487 – 46,502
65,487 is rounded off to nearest ten thousand – 64,000
46,502 is rounded off to nearest ten thousand – 46,000

Estimate sum is 18,000
Verification by actual substruction

2. 45,630 – 32,148
45,630 is rounded off to nearest ten thousand – 44,000
32,148 is rounded off to nearest ten thousand – 30,000

Estimate sum is 14,000
Verification by actual substruction

3. 57,146 – 25,472
57,146 is rounded off to nearest ten thousand – 56,000
25,472 is rounded off to nearest ten thousand – 24,000

Estimate sum is 32,000
Verification by actual substraction

4. 60,046 – 15,247
60,046 is rounded off to nearest ten thousand – 60,000
15,247 is rounded off to nearest ten thousand – 15,000

Estimate sum is 45,000
Verification by actual substraction

VI. Estimate the difference of thefolhming hy rounding off to nearest ten thousands place:

1. 51,689 – 34,685
51,689 is rounded off to nearest ten thousand – 50,000
34,685 is rounded off to nearest ten thousand – 30,000

Estimate sum is 20,000
Verification by actual substraction

2. 86,853 – 47,829
86,853 is rounded off to nearest ten thousand – 85,000
47,829 is rounded off to nearest ten thousand – 45,000

Estimate difference is 40,000
Verification by actual substraction

3. 80,808 – 55,055
80,808 is rounded off to nearest ten thousand – 80,000
55,055 is rounded off to nearest ten thousand – 50,000

Estimate difference is 30,000
Verification by actual substractiori

4. 77,777 – 44,444
77,777 is rounded off to nearest ten thousand – 70,000
44,444 is rounded off to nearest ten thousand – 40,000

Estimate difference is 30,000
Verification by actual substraction

VII. Estimate the product of each of the following hy rounding off to its highest place:

1. 428 × 54
428 is rounded off to nearest hundred as 400
54 is rounded off to nearest ten as 50

Estimate product is 20,000

2. 878 × 46
876 is rounded off to nearest hundred as 900
46 is rounded off to nearest ten as 50

Verification by actual multiplication

Verification by actual multiplication

3. 5,476 × 11
5,476 is rounded off to nearest hundred as 5000
11 is rounded off to nearest ten as 10

Verification by actual multiplication

Verification by actual multiplication

4. 2,645 × 18
2,645 is rounded off to nearest hundred as 3000
18 is rounded off to nearest ten as 20

Verification by actual multiplication

Verification by actual multiplication

VIII. Estimate the quotient of each of the following hy rounding off to its highest place.

1. 398 ÷ 82
398 is rounded off to nearest hundred aS 400
82 is rounded off to nearest ten as ÷ 80
Estimate quotient \(\frac{800}{40}\) = 5

2. 786 ÷ 22
786 is rounded off to nearest hundred as 800
22 is rounded off to nearest ten as ÷ 20
Estimate quotient \(\frac{800}{20}\) = 40

3. 3,265 ÷ 58
3,265 is rounded off to nearest hundred as 3000
58 is rounded off to nearest ten as ÷ 60
Estimate quotient \(\frac{3000}{60}\) = 50

4. 7,687 ÷ 43
7,687 is rounded off to nearest hundred as 8000
43 is rounded off to nearest ten as ÷ 40
Estimate quotient \(\frac{8000}{40}\) = 200

IX. Solve the following problems.

Question 1.
A garment company stitched 16,783 shirts and 12,438 pants in a month. Estimate the total number of dresses stitched to the nearest ten thousands place.
Answer:
A garment company stitched shirts – 16,783
A garment company stitched pants – 12,438.
(To the nearest ten thousand place) – 20,000
(To the nearest ten thousand place) – 10,000

Question 2.
A news paper agent sells 36,721 papers in first month and 24,172 papers in sec¬ond month. Estimate the decrease in sale of the newspaper in second month to the nearest ten thousands place.
Answer:
In first month a news paper agents sells – 36,721
In Second month a news paper agents sells – 24,172
(To the nearest ten thousand place)
first month – 40,000
Second month – 20,000

The estimated substraction of sale of the newspaper 20,000

Question 3.
A train can cover 225 km in one hour. Estimate the distance covered in a day to the highest place.
Answer:
A train can cover 225 Km in 1 hour
The distance covered in a day = 24 hours
(To the highest place) 200

Question 4.
A carpenter earned Rs. 18,634 during the month of November and Rs. 32,645 in December. Estimate how much more he earned in December to the nearest ten thousands place.
Answer:
A carpet earned in november – 18,634
A carpet earned in december – 32,645
(To the nearest ten thousand place)

Students can Download Maths Chapter 6 Angles Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 6 Angles

KSEEB Class 5 Maths Angles Ex 6.1

Question 1.
Observe your surrounding environment and list the situations where the angles are formed.
Answer:
Room, clock, pillars of a building, roof of a building, water tank, ball etc.

Question 2.
Observe the angles formed while doing the following yogasana postures. Certain angles are already marked to help you.

Answer:

Question 3.
Pranav has arranged sticks as shown in the figure. Observe the angles formed here and mark the angles by drawing lines.

Answer:

Question 4.
Name the angle, vertex and the sides in the following figures.
Answer:

KSEEB Class 5 Maths Angles Ex 6.2

Question 1.
Mark the right angle, acute angle and obtuse angle with different colours in the following figures.

Answer:
a)
RightAngel ∠EDF ∠CDE ∠CBA ∠BCD
∠ADF ∠ADC ∠DAB ∠COD
∠COB ∠AOD ∠AOB
Acute Angel ∠CBO ∠OCB ∠OBA ∠BAO
∠OAD ∠ODA

b)

RightAngel ∠BAC ∠BEP ∠CDS ∠PQR
∠QRS ∠RSP ∠SPQ ∠EBC ∠BCD
Acute Angel ∠ABC ∠ACB ∠EFG ∠DGF
ObtuseAngle: ∠BEF ∠CDG ∠FED ∠GDE

c)

Right Angel: ∠DEF ∠EDC ∠ADC ∠BCD
AcuteAngel: ∠FGC
Obtuse Angle: ∠DCG ∠EFG

d)

Right Angle – Blue colour
Obtuse Angle – Pink colour, Sky blue

e)

Right Angle: ∠ABC ∠ABD
Complete Angle: ∠A
ObtuseAngle: ∠BCL ∠CLM ∠HKN ∠IJO ∠PFE
Acute Angel: ∠DEF

Question 2.
Measure the following angles and write the measurement and type of each angle.
Answer:

Question 3.
Observe the acute angle, obtuse angle and right angles in your classroom and list them.
Answer:
Two edges of wall of a classroom – Right Angle
Two edges of a door – Right Angle
Two edges of a window – Right Angle

Question 4.
Write your name using English capital letters. List the number of acute angles, obtuse angles and right angles in them.
Answer:
Refer to Students

Question 5.
Draw any six angles using scale and measure them using a protractor.
Answer:

Question 6.
Write the measure of the angle between the two hands of the following docks and name them.

Answer:

Question 7.
Choose the right answer from the following.
a) Example for obtuse angle.
1) 90°
2) 53°
3) 178°
4) 180°
Answer:
3) 178° – Obtuse Angle

b) In the given figure, the number of right angles, acute angles and obtuse angles are
1) 15, 4, 10
2) 4, 15, 10
3) 10, 10, 4
4) 4, 5, 5
Answer:
2) 4, 15,10

Question 8.
Classify the measures of angles given below :
16°, 180°, 88°, 179°, 45°, 90°, 100°, 35°, 142°.

Answer:

Question 9.
Estimate the measure of the following angles.
Verify by measuring them. Name the type of angles.
Answer:

Question 10.
Measure the angles m me figures given below. Find the sum of the angles.

Answer:

Students can Download Maths Chapter 2 Division Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 2 Division

KSEEB Class 5 Maths Division Revision Exercise

I. Encircle the objects in as shown in the example and write answer in given box:

II. Divide the following using repeated substruction method:

a. 12 ÷ 4
12 – 4 = 8
8 – 4 = 4
4 – 4 = 0
Subtract is done 3 times
\(\frac{12}{4}\) = 3

b. 25 ÷ 5
25 – 5 = 20
20 – 5 = 15
15 – 5 = 10
10 – 5 = 5
5 – 5 = 0
Subtract is done 5 times
25 ÷ = 5

c. 42 ÷ 7
42 – 7 = 35
35 – 7 =28
28 – 7 = 21
21 – 7 = 14
14 – 7 = 7
7 – 7 = 0
Subtract is done 6 times

d. 30 ÷ 10
30 – 10 = 20
20 – 10 = 10
10 – 10 = 0
Subtract is done 3 times
30 ÷ 10 = 3

e. 75 ÷ 15
75 – 10 = 60
60 – 15 = 45
45 – 15 = 30
30 – 15 = 15
15 – 15 = 0
Subtract is done 5 times
5 ÷ 15 = 5

KSEEB Class 5 Maths Division Ex 2.1

I. Find the quotient and the remainder:

1. 48 ÷ 6

Quotient = 8
Remainder =0

2. 36 ÷ 3

Dividend = (divisor × quotient) + Remainder
36 = (3 × 12) +0
36 = 36 + 0
36 = 36
Quotient = 12
Remainder =0

3. 55 ÷ 4

Dividend = (divisor × quotient) + Remainder
55 = (4 × 13) + 3
55 = 52 + 3
55 = 55
quotient = 13
Remainder = 3

4. 72 ÷ 7

Dividend = (divisor × quotient) + Remainder
72 = (7 × 10) + 2
72 = 70 + 2
72 = 72
quotient = 10
Remainder = 02

II. Find the quotient and the remainder:

1. 232 ÷ 4

Dividend = (divisor × quotient) + Remainder
232 = (4 × 58) + 0
232 = 232 + 0
232 = 232
quotient = 58
Remainder = 3

2. 474 ÷ 6

Dividend = (divisor × quotient) + Remainder
474 = (6 × 79) + 0
474 = 474 + 0
474 = 474
quotient = 79 3
Remainder =0

3. 255 ÷ 11

Dividend = (divisor × quotient) + Remainder
255 = (11 × 23) + 2
255 = 253 + 2
255 = 255
quotient = 23
Remainder = 2

4. 527 ÷ 12

Dividend = (divisor × quotient) + Remainder
527 = (12 × 43) + 11
527 = 516 + 11
527 = 527
quotient = 43
Remainder = 11

III. Find the quotient and the remainder:

1. 1,653 ÷ 8

Dividend = (divisor × quotient) + Remainder
1653 = (8 × 206) + 5
1653 = 1648 + 5
1653 = 1653
quotient = 206
Remainder = 5

2. 1,325 ÷ 2

Dividend = (divisor × quotient) + Remainder
1325 = (2 × 662) + 1
1325 = 1324 + 1
1325 = 1325
quotient = 662
Remainder = 1

3. 1,435 ÷ 15

Dividend = (divisor × quotient) + Remainder
1435 = (15 × 95) + 10
1435 = 1425+10
1435 = 1435
quotient = 95
Remainder =10

4. 2,647 ÷ 13

Dividend = (divisor × quotient) + Remainder
2647 = (13 × 203) + 8
2647 = 2639 + 8
2647 = 2647
quotient = 203
Remainder = 8

IV. Find the quotient and the remainder:

1. 24,658 ÷ 2

Dividend = (divisor × quotient) + Remainder
24658 = (2 × 12329) + 0
24658 = 24658 + 0
24658 = 24658
quotient = 12329
Remainder = 0

2. 14,005 ÷ 7

Dividend = (divisor × quotient) + Remainder
14005 = (7 × 2000) + 5
14005 = 14000 + 5
14005 = 14005
quotient = 2000
Remainder = 5

3. 32,745 ÷ 10

Dividend = (divisor × quotient) + Remainder
32745 = (10 × 3274) + 5
32745 = 32740 + 5
32745 = 32745
quotient = 3274
Remainder =5

4. 12,056 ÷ 12

Dividend = (divisor × quotient) + Remainder
12056 = (12 × 1004) +8
12056 = 12048 + 8
12056 = 12056
quotient = 1004
Remainder = 8

V. Solve the following problems:

Question 1.
A tailor has 18 metres of cloth. He stitch 9 shirts from this cloth. Find the length of cloth required to stitch one shirt.
Answer:
A tailor has 18 meter of cloth
Tailor has stitch 9 shirts
The length of cloth required to stitch one shirt = \(\frac{18}{9}\) = 2 meter

Question 2.
A bike can cover 240 km with 5 litres of petrol. Find how many kilometres does it cover with 1 litre of petrol.
Answer:
A bike can cover 240 Km with 5 litres of petrol
In one litre of petrol, bike covers the distance = \(\frac{240}{5}\) = 48 km

Question 3.
25,004 bags of cement are loaded equally into 14 railway wagons. Find the number of bags in each wagon.
Answer:
25,004 bags of cement are loaded equally into 14 railway wagons
The number of bags
= \(\frac{25004}{14}\) = 1,786

Question 4.
Mr. Sridhar purchased 11 toys of same price for Rs. 946 from a toy shop. Find the cost of each toy.
Answer:
The cost of a toy =?
Mr. Sridhar purchase 11 toys of same price = Rs 946
The cost of each toy
= \(\frac{946}{11}\) = 86 Rs.

Question 5.
The annual income of a person is Rs.90,912. Find his monthly income.
Answer:
The Annual income of a peusen Rs 90,912
Monthly income = \(\frac{90912}{12}\) = 7,576 Rs

Question 6.
A car manufacturing company manufactures 14,820 cars in 13 months. Find the number of cars manufactured in one month.
Answer:
A car manufacturing company manufactures 14820 cars in 13 months. For one month, the number of cars = \(\frac{14820}{13}\) = 1,140

KSEEB Class 5 Maths Division Ex 2.2

I. Solve

Question 1.
An orange garden has 82 orange plants. A farmer plucks 60 oranges from each plant and packs 12 oranges in each box. Calculate the number of boxes required to pack all oranges.
Answer:
An orange garden has 82 oranges . A farmer plunks 60 oranges from each plant
The number of boxes = ?
The number of oranges in each box = 12
The number of oranges in an orange garden = 410

Question 2.
15 school children hire a cab for a day’s excursion at Rs. 9 per km. If they travel a distance of 325 km, find the amount to be shared by each one of them.
Answer:
A cab of charges Rs 9 Km
The childrens travel a distance 325Km
= 325 × 9
= 2925 Km
The amount shared by each student
= 2925 ÷ 15 = Rs 195

Question 3.
Anita has a cow which yields 8 litres of milk in a day. The selling price of one litre of milk is Rs. 18. She wants to divide the amount earned in one month (30days) among her 4 sons. What amount does each one get?
Answer:
One litre of milk = Rs 18
A cow which yields 8 litres of milk in a day for 30 days, the number of litres of milk
18 × 8 = Rs. 144
The amount of milk
144 × 30 = Rs. 4320
The amount of each son 1,080
4320 ÷ 4

Students can Download Maths Chapter 5 Fractions Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 5 Fractions

KSEEB Class 5 Maths Fractions Ex 5.1

Question 1.
Which of the following figures have been divided into parts of the same size?

Answer:
b & c.

Question 2.
Draw a line to divide each of these figures into the required number of equal parts.

Answer:

Question 3.
Write each of the following as a fraction
Answer:
a) Half –\(\frac{1}{2}\)
b) Two-third – \(\frac{2}{3}\)
c) Two-tenth – \(\frac{2}{10}\)
d) Five-seventh – \(\frac{5}{7}\)
e) Five-sixteenth – \(\frac{5}{16}\)
f) Five-twelveth – \(\frac{5}{12}\)
g) Eight-nineth – \(\frac{8}{9}\)
h) Four-nineth – \(\frac{4}{9}\)
i) Three-fourth – \(\frac{3}{4}\)
j) Two-fifth – \(\frac{2}{5}\)

Question 4.
Write each of the fraction in words
Answer:
a) \(\frac{2}{5}\) – two-fifth
b) \(\frac{3}{4}\) – three-fourth
c) \(\frac{7}{10}\) – seven-tenth
d) \(\frac{11}{12}\) – eleven-twelveth
e) \(\frac{2}{3}\) – two-third
f) \(\frac{4}{5}\) – four-fifth
g) \(\frac{5}{8}\) – five-eight
h) \(\frac{3}{7}\) – three-seventh
i) \(\frac{5}{6}\) – five-sixth
j) \(\frac{7}{9}\) – seven-nineth

Question 5.
What fraction of the figure is shaded?
Answer:
a) \(\frac{2}{3}\)

b) \(\frac{2}{4}\)

c) \(\frac{5}{8}\)

d) \(\frac{7}{12}\)

e) \(\frac{7}{15}\)

f) \(\frac{6}{18}\)

Question 6.
Fill in the blanks:
Answer:
a) The denominator of the fraction \(\frac{1}{8}\) is 8
b) The numerator of the fraction is \(\frac{2}{5}\) 2
c) 3 is the denominator of fraction \(\frac{1}{3}\)
d) 1 is the numerater of the fraction \(\frac{1}{5}\)
e) In a fraction, the denominator is written below the numerator separated by a line.

Question 7.
Write down the fraction of the coloured portions in these figures.
Answer:
a)
\(\frac{1}{5}\)

b)
\(\frac{2}{4}\)

c)
\(\frac{4}{12}\)

d)
\(\frac{3}{6}\)

e)
\(\frac{4}{9}\)

Question 8.
Write the fraction for the shaded part in each of the following figures.
Answer:
\(\frac{4}{7}\)

\(\frac{2}{9}\)

\(\frac{7}{10}\)

Question 9.
Colour the figures as instructed.
Answer:

Eg: \(\frac{7}{10}\)

\(\frac{1}{5}\)

\(\frac{2}{3}\)

\(\frac{2}{9}\)

Question 10.
Represent the given fraction by drawing a line.
Answer:
a) What is \(\frac{1}{3}\) of 12?

b) What is \(\frac{2}{5}\) of 15?

c) What is \(\frac{2}{7}\) of 21?

Question 11.
Shade the figures to show the fractions.
Answer:
a) \(\frac{6}{11}\)

b) \(\frac{7}{20}\)

c) \(\frac{8}{15}\)

Question 12.
Which of the following shaded figures represent \(\frac{4}{9}\) ?

Answer:

Question 13.
Which of the following shaded figure represents \(\frac{5}{12}\) and give reason.

Answer:
fig b&d, Reason: 5 objectives out of 12 are shaded

Question 14.
Represent the grouped parts as fractions:
Answer:
a)
\(\frac{4}{5}\)

b)
\(\frac{3}{7}\)

c)
\(\frac{5}{6}\)

KSEEB Class 5 Maths Fractions Ex 5.2

I. Fill in the gaps using > or < signs.

KSEEB Class 5 Maths Fractions Ex 5.3

I. Complete the series.

2 × 2 = 4
2 × 3 = 6

3 × 2 =6
3 × 3 = 9
3 × 4 = 12

5 × 2 = 10
7 × 2 = 14

5 × 3 = 15
7 × 3 = 21

5 × 6 = 30
7 × 6 = 42

II. Write the next three equivalent fractions.

2 × 3 = 6, 5 × 3 = 15
2 × 4 = 8, 5 × 4 = 20
2 × 5 = 10, 5 × 5 = 25

3 × 3 = 9
3 × 4 = 12
3 × 5 = 15

9 × 3 = 27, 11 × 3 = 33
9 × 4 = 36, 11 × 4 = 44
9 × 5 = 45, 11 × 5 = 55

III. Are the two fractions equivalent?

Question 1.
\(\frac{3}{5}\) and \(\frac{18}{30}\)
Answer:
Yes,Reason, \(\frac{3}{5} \times \frac{6}{6}=\frac{18}{30}\)

Question 2.
\(\frac{12}{17}\) and \(\frac{8}{20}\)
Answer:
No, Both terms are different

Question 3.
\(\frac{2}{7}\) and \(\frac{7}{21}\)”
Answer:
No, Both terms are different

Question 4.
\(\frac{5}{11}\) and \(\frac{25}{55}\)
Answer:
Yes,Reason, \(\frac{5 \times 5}{11 \times 5}=\frac{25}{55}\)

IV. Find an equivalent raction of \(\frac{4}{7}\) having:

1. 16 as numerator
\(\frac{4 \times 4}{7 \times 4}=\frac{16}{28}\)

2. 24 as numerator
\(\frac{4 \times 6}{7 \times 6}=\frac{24}{42}\)

3. 21 as denominator
\(\frac{4 \times 3}{7 \times 3}=\frac{12}{24}\)

4. 84 as denominator
\(\frac{4 \times 12}{7 \times 12}=\frac{48}{84}\)

KSEEB Class 5 Maths Fractions Ex 5.5

I. Reduce each of the following fractions into its lowest form. 

1. \(\frac{8}{16}=\frac{1}{2}\)
2. \(\frac{5}{10}=\frac{1}{2}\)
3. \(\frac{54}{108}=\frac{1}{2}\)
4. \(\frac{4}{20}=\frac{1}{5}\)
5. \(\frac{3}{15}=\frac{1}{5}\)
6. \(\frac{12}{16}=\frac{3}{4}\)
7. \(\frac{9}{27}=\frac{1}{3}\)
8. \(\frac{36}{48}=\frac{3}{4}\)
9. \(\frac{24}{56}=\frac{3}{7}\)
10. \(\frac{24}{72}=\frac{1}{3}\)

KSEEB Class 5 Maths Fractions Additional Questions

Question 1.
Estimate the degree of closeness of the fractions \(\frac{2}{7}, \frac{3}{7}\) and \(\frac{5}{7}\) and \(\frac{1}{4}, \frac{1}{2}\) and \(\frac{3}{4}\)

Answer:
\(\frac{2}{7}\) is closer to \(\frac{1}{4}, \frac{3}{7}\) is closer to \(\frac{1}{2}\)

\(\frac{5}{7}\) is closer to \(\frac{3}{4}\)

Question 2.
Estimate the degree of closeness of the fractions \(\frac{2}{9}, \frac{4}{9}, \frac{5}{9}\) and \(\frac{7}{9}\) to \(\frac{1}{4}, \frac{1}{2}\) and \(\frac{3}{4}\) .

Answer:
\(\frac{2}{9}\) is closer to \(\frac{1}{4}, \frac{4}{9}\) is closer to \(\frac{1}{2}\)

\(\frac{5}{9}\) is closer to \(\frac{1}{2}, \frac{7}{9}\) is closer to \(\frac{3}{4}\)

Students can Download Maths Chapter 1 Multiplication Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 1 Multiplication

KSEEB Class 5 Maths Multiplication Revision Exercise

I. Find the product of the following:

1. 35 × 0

2. 164 × 1

3. 100 × 0

4. 1 × 235

5. 0 × 1,001

6. 1 × 55

II. Find the product of the following:

1. 45 × 16

2. 63 × 31

3. 162 × 17

4. 18 × 42

5. 83 × 17

6. 234 × 22

III. Solve the following problems:

Question 1.
Cost of one notebook is Rs. 16, What is the cost of 12 notebooks?
Answer:
Cost of 1 notebook = Rs. 16
Cost of 12 notebooks = 16 × 12 = 192

Question 2.
The school fee of a fifth class student is Rs. 38. What is the total fee of 128 students?
Answer:
Fee of a 5th class student = Rs 38
The total fee of student = 128 × 38

total amount of 128 Rs.

Question 3.
63 students went on one-day excursion with their class teacher. The class teacher collected Rs. 150 from each student towards travel and lunch expenses. What is the total amount collected?
Answer:
The class teacher collects for each student Rs 150
The total number of students = 63 × 150

Question 4.
The cost of a bag containing 10 kg. rice is Rs. 285. Find the cost of 25 bags of rice.
Answer:
The cost of a bay containing 10 kg rice Rs 85
The cost of 25 bays of rice = 285 × 10 = 2850 Rs

Question 5.
The headmaster decides to give first and second prize for various competitions. 16 students got first prize and 16 students got second prize. If the cost of first and second prize is Rs. 11 and Rs. 9 respectively, find the total amound required by headmaster to buy the prizes.
Answer:
The cost of First prise = Rs 11
16 students got First Prize = 16 × 11 = 170
The cost of second prize = Rs 9
16 students got second prize = 16 × 9

The total amount required by headmaster to buy the prizes = 176 + 144 = Rs 320

KSEEB Class 5 Maths Multiplication Ex 1.1

I. Multiply:

1. 146 × 173

2. 178 × 142

3. 163 × 134

4. 183 × 208

5. 150 × 107

6. 248 × 212

7. 316 × 100

8. 100 × 523

II. Multiply:

1. 2,861 × 9

2. 3,947 × 7

3. 7,254 × 6

4. 6,041 × 5

5. 8,028 × 8

6. 4,395 × 9

III. Find the product:

1. 9,025 × 10

2. 2,549 × 20

3. 3,746 × 23

4. 4,756 × 19

5. 2,439 × 31

6. 1,258 × 13

7. 1,028 × 37

8. 2,375 × 16

v

IV. Multiply:

1. 21,497 × 3

2. 15,746 × 5

3. 11,048 × 7

4. 10,039 × 9

V. Solve the following problems:

Question 1.
Mr. Siddappa is a fruit selling agent who e×port oranges. One bo× contains 144 oranges. If he export 259 boxes of oranges, find the total number of oranges exported.
Answer:
A box contains 144 oranges Mr. siddappa export 259 boxes of oranges
The total number of oranges Export 144 × 259 = 37,296

Question 2.
In a protected forest area, 160 trees and planted in each row and 108 trees in each column. Find the total number of trees planted in the forest area.
Answer:
Trees are planted in each row 160
Trees are planted in each column 108
The total number of trees planted in the forest area = 160 × 108 = 17,280

Question 3.
A dealer buys 37 bicycles for his showroom: Cost of each bicycle is Rs.2,067. Find the amount paid by the dealer.
Answer:
The cost of each bicycle Rs 2067
A dealer buys 27 bicycles
The amount paid by the dealer = 2,067 × 27 = 55,809 Rs.

Question 4.
A farmer grew 23 quintals of wheat. He sold them for Rs. 1,935 per quintal. How much amount did the farmer get by selling wheat?
Answer:
One quintal of wheat = Rs 1,935
A farmer grew 23 quiltals of wheat = 23
The farmer get by selling wheat = 1,935 × 23 = Rs 44,505

Students can Download Maths Chapter 4 Factors and Multiples Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 4 Factors and Multiples

KSEEB Class 5 Maths Factors and Multiples Ex 4.1

Question 1.
Circle the multiples of 4 with blue colour, cross the multiples of 6 with red colour and underline the multiples of 9 with a pencil.
Answer:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96 & 100 → Multiples of 4
6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90 & 96 → Multiples of 6
9, 18, 27, 36, 45, 54, 63, 72, 81, 90 & 99 → Multiples of 9

Question 2.
Circle the multiples of 7 in the following numbers.
7, 13, 14, 21, 22, 35, 36, 42 and 45
Answer:
7, 14, 21, 35, 42

Question 3.
Circle the multiples of 12 in the following numbers.
6,12,18, 24, 30, 36, 42, 48, 54, 60, 66, 72
Answer:
12, 24, 36, 48, 60, 72

Question 4.
Write the multiples of 2 between the numbers 50 and 60.
Answer:
52, 54, 56, 58
G : 52/2 = 26

Question 5.
Write the multiples of 15 between the numbers 50 and 100.
Answer:
60, 75, 90
G : 15 × 4 = 60

Question 6.
Write five multiples of the following numbers.
Answer:
5 multiples of 15 are 15, 30, 45, 60 & 75.
5 multiples of 17 are 17, 34, 51, 68 & 85.
5 multiples of 19 are 19, 38, 57, 76 & 95
5 multiples of 23 are 23, 46, 69, 92 & 115.

Question 7.
Find which of the following numbers are factors of 24?
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 14, 16, 18, 20, 22 ಮತ್ತು 24
Answer:
24 – 1 × 24
24 – 4 × 6
24 – 2 × 12
24 – 3 × 8
1, 2, 3, 4, 6, 8, 12 & 24

Question 8.
Write any two factors of the following numbers.
6, 18, 28, 36, 42, 48
Answer:
Any two factors of 6 are 2 & 3
Any two factors of 28 are 2 & 14
Any two factors of 42 are 2 & 21
Any two factors of 18 are 2 & 9
Any two factors of 36 are 3 & 12
Any two factors of 48 are 2 & 24

Question 9.
Write all the factors of the following numbers.
9, 13, 20, 26, 40
Answer:
All the factors of 9 are 1,3 & 9 All the factors of 13 are 1 & 13 All the factors of 20 are 1, 2, 4, 5, 10 & 20
20 = 1 × 20
2 × 10 = 20
4 × 5 = 20
5 × 4 = 20
10 × 2 = 20
20 × 1 = 20
All the factors of 26 are 1 ,2, 13 & 26
All the factors of 40 are 1, 2, 4, 5, 8, 10, 20 & 40

Question 10.
Write the factor tree for the following numbers:
Answer:

Question 11.
Complete the following factor tree by writing missing numbers.

Answer:

(i)

(ii)

Students can Download Maths Chapter 3 Subtraction Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 3 Subtraction

KSEEB Class 5 Maths Subtraction Revision Exercise

I. Subtract the following numbers:

1) 4,528 – 3,214

2) 6,453 – 5,302

3) 3,759 – 2,156

II. Subtract the following numbers:

1) 6,123 – 3586

2) 8,000 – 4,617

3) 3,564 – 1,345

III. Solve the following problems:

Question 1.
A factory manufactured 8,534 boxes. Out of the 5,421 boxes were sold out. Find the remaining number of boxes.
Answer:
A factory manufactured boxes = 8,534
The boxes were sold out = -5,421
The Remainary number of boxes = 3,113

Question 2.
The total number of students of standard five in all the schools of a taluk is 5,728. If the number of girls is 3,572, find the number of boys in the schools.
Answer:
The total number of students of standard of five in all the schools of a taluk = 5,728
The number of girls of fifth standard = – 3,572
The number of boys in the schools = 2,156

Question 3.
Sanjeev has Rs. 8,524. He donated Rs. 2,937 to an orphanage charitable trust. How much amount is left with him?
Answer:
Sanjeev has – Rs 8,524
Sanjeev donate – Rs – 2,937
Sanjeev’s left amount – Rs 5,587

KSEEB Class 5 Maths Subtraction Ex 3.1

I. Find the difference of the following:

1. 59,842 – 34,532

2. 86,291 – 64,130

3. 41,297 – 16,025

4. 25,768 – 4,304

5. 17,094 – 3,043

II. Find the difference of the following:

1. 42,695 – 20,746

2. 50,625 – 36,178

3. 40,000 – 16,543

4. 25,307 – 6,419

5. 20,000 – 8,625

III. Subtract:

1. 16,486 from 26,475

2. 36,279 from 52,367

3. 10,000 from 31,579

4. 24,683 from 40,000

5. 4,297 from 11,035

IV. Solve the following problems:

Question 1.
What should be added to 37,946 to get 91,643?
Answer:

Question 2.
What should be subtracted from 67,215 to get 28,941?
Answer:

Question 3.
The sum of two numbers is 87,065. If one of the numbers is 49,726, find the other number.
Answer:
Let the No. be X another No. be Y sum of x + y = 87065
Y = 49,726
X = ?

The other number y = 37,339

Question 4.
A farmer yielded 38,462 coconuts from his field last year. This year he yielded 47,285 coconuts. Find how many more coconuts he yielded this year?
Answer:
A farmer yielded coconuts from his field last year = 38,462
A farmer yielded coconuts from his field this year = 47,285.

A farmer 8,823 coconuts yielded this year

Question 5.
In an assembly election, Mr. Suresh has got 42,618 votes. Mrs. Rohini got 54,951 votes and won. How many more votes did Mrs. Rohini get than Mr. Suresh?
Answer:
In an election, Mr. Suresh got 42,618 votes
Mr. Rohin’s got 54,951 votes

Mr. Rohin’s gets 12,333 votes than Mr. Suresh.

Question 6.
A garment factory produces 25,846 dresses for boys and 45,715 dresses for girls during a festive season. How many more dresses, did factory produce for girl than boys? (Additional Question)
Answer:
A government factory producers 25,846 dresses for boys
A government factory producers 45,715 dresses for girls

19,869 more dresses did factory produce for girls than boys.

Question 7.
A farmer bought a pair of bulls which cost Rs. 68,300 in the market. He had ” Rs.86,100 with him. What is the amount left with him after buying the bulls?
Answer:
Farmer had amount of Rs 86,100 (Additional Question)
Farmer bought a pair of Bulbs cost 68,300

Farmer’s had left amt Rs 17,800

KSEEB Class 5 Maths Subtraction Ex 3.2

I. Solve:

1. 54,398 + 24,897 – 39,486

2. 2. 43,618 + 6,382 – 29,467

3. 21,679 + 27,428 – 2,438

II. solve the following problems:

Question 1.
A mobile phone factory manufactures 23,715 mobiles in November and 34,160 mobiles in December. Out of them 42,534 mobiles were sold. Find how many mobiles are left unsold in the factory.
Answer:
A mobile phone factory manufactures 23,715 mobiles in November
A mobile phone factory manufactures 34,160 mobiles in December
By Adding

In mobile phone 57,875 mobiles were manufactured 42,534 mobile phones were sold out
By Subtracting

15,341 mobiles are left unsold in the factory.

Question 2.
Mr. Anand has Rs. 15,282 in his bank account. He deposits Rs. 25,718 on Wednesday. He withdraws Rs. 30,145 on Thursday. Find his balance after withdrawal.
Answer:
Mr. Anand has Rs 15,282 in his bank amount
Mr. Anand deposits Rs 25,718 on Wednesday
Mr. Anand withdraw Rs 30,145 on Thursday

Mr. Anand’s Bank amount – Rs 41,003

After withdrawing Mr.Anand’s bank balance – Rs 10,858

Question 3.
Mrs. Anita has Rs. 50,000 with her. She purchases a color T.V. for Rs. 13,538 and a refrigerator for Rs. 16,990. Find the amount left with her after the purchase.
Answer:
Mrs. Anitha’s Amount – Rs 50,000
Mrs. Anitha purchases a color T.V – Rs 13,538
A refrigerator – Rs 16,990
Total Amount of purchasing By Adding – Rs 30,528

The Amount Rs 19,472 left with Anitha

Question 4.
60,000 school uniforms are provided for school children of a district. 12,372 and 23,3 uniforms were distributed to schools of two talks of a district. Find how many uniforms are remaining.
Answer:
For a District 60,000 school uniforms provided for children.
12,372 & 23,003 uniforms were distributed to schools of two talk of the district

By Adding

By Subtracting

24,625 uniforms are remaining

Students can Download EVS Chapter 16 Our India – Political and Cultural Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 EVS helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Board Class 5 EVS Chapter 16 Our India – Political and Cultural

Class 5 EVS Our India – Political and Cultural Text Book Questions and Answers

Question 1.
I which part of India is Karnataka State located?
Answer:
South part of India is Karnataka state located.

Question 2.
How many districts are these in Kama taka state? List them?
Answer:

1. Bangalore
2. Belgaum
3. Mysore
4. Tumkur
5. Gulbarga
6. Bellary
7. Bijapur
8. Dakshina Kannada
9. Davanagere
10. Raichur
11. Bagalkot
12. Dharwad
13. Mandya
14. Hassan
15. Shimoga
16. Bidar
17. Chitradurga
18. Haveri
19. Kolar
20. Uttar Kannada.

Question 3.
Which are the neighboring states of Karnataka?
Answer:
Tamil nadu, Kerala, Andrapradesh, Maharastra.

Question 4.
Which is the official language of your neighboring states?
Answer:
Kannada

Question 5.
Which are the languages of your neighboring states?
Answer:
Tdugu, Tamil, Marati, Malayalam.

Question 6.
Which is the official language of India?
Answer:
Hindi.

Question 7.
Which is the capital city of Karnataka State?
Answer:
Bangalore.

Question 8.
Which are the Neighboring countries of India?
Answer:
Pakistan, China, Sri Lanka, Nepal, Bangladesh, Buttan and Myanmar (Burma).

Question 9.
What are the Islands of India?
Answer:
Andaman and Nicobar, Hanelock, Barren, Majuli, Diu Baratang, Katchal, Neil, Divar, EJephata

Question 10.
List of Union Territories of India?
Answer:

1. Andaman and Nicobar Islands.
2. Chandigarh
3. Dadra and Nagar Haveli
4. Daman & Diu.
5. Lakshadweep and
6. Puducherry

Question 11.
List the Northern & Southern State of India
Answer:

• Northern States: Jammu and Kashmir, Punjab, Himachal Pradesh, Rajasthan, Uttar Pradesh, Haryana.
• Southern States: kerala, karnataka, Tamilnadu, Andra pradesh.

Question 12.
Which is the smallest states of the Northeast of India?
Answer:
Mizoram.

Question 13.
Name the national festivals of India?
Answer:
Pongal Makar Sankranthi, Lohri, Onam, Baisakhi, Bhogdi bihu, Bihu dance, Basant Panchalli.

Question 14.
What are the colors of our National flog?
Answer:
Saffron, white and Green.

Question 15.
Write two names of each recipient of the following awards.
Answer:

1. Padmashree: Virat Kohi, Bharathi, Vishnuvardhan
2. Padmabhushana: Sirindhor, Cho Ramaswamy
3. Padma vibhushana: Jaggi Vasudev, Sharad Pawer,
4. Bharath Ratna: Mother Teresa, Abdul KalamAzad.

Question 16.
who is this? write 3 sentences about her.

Answer:
Saina Nehwal is a professional badminton singles player from India, Nehwal, the former world no. 1, has maintained her world ranking in the top ten since 2009. She has won over twenty international titles, which include then super series titles. She got a Padma Shree award.

Question 17.
Write 5 sentences about popular sprots
Answer:
The most popular sport in India is cricket. I mean a sport in which there are two batsmen on the creez and 9 fielders, one bowler, one wicketkeeper and two empires. The bowler bowls and the batsman by to defend himself and tries to hit the ball. But when it comes to India Cricket has manes various than you might think.

Question 18.
What are the public assets you see in your place?
Answer:
Roads, Buses, railway, electricity, post office.

Question 19.
What are the public facilities needed for your place?
Answer:
Water tank, library, sanitary, electricity, drinking water are the public facilities are needed in our place.

Question 20.
What are the historical buildings that are there in your place?
Answer:
Jaimatia palace Vidhamer Sandhur

Question 21.
Why should we preserve our public assets? Give reasons
Answer:
If public properties are damaged, they have to be replaced or repaired cost of all this is collected in the form of additional taxes, tax money will be vested it public property is all our aset.

Question 22.
What are the benefits from public assets?
Answer:
Government takes up many programmes for the benefit of the people: roads, hospitals, electricity, water and such other sevice programmes. It is our right to use these facilites and services to the best of our needs.

Question 23.
Public property is our own property why?
Answer:
Government property is every one’s property, Government collects money from us as taxes. It uses taxes to provide facilities like roads, railway, Airport etc.,

Question 24.
What are called public property?
Answer:
Many items of property like building, machines, equipments articles, furniture will be provided in public places for the benefit and use of the public such things are called public property.

Question 25.
What are called private properties?
Answer:

• Everyone wishes to possess a house, a garden, vehicle, ornament other objects. All these from part of our own properties.
• We use our assets and take care of them.
• Some work hard to own riches and leave them to their children and grand childern.

Question 26.
Who is a citizen?
Answer:
Permanent resident of a country.

Question 27.
Are you an Indian citizen? How?
Answer:
Yes, I am an Indian citizen by birth.

Question 28.
Mention a few qualities of good citizen.
Answer:

• helping the senior citizen
• Paying taxes regularly
• Obedience to the laws of the country.

Question 29.
Mention two methods of getting citizenship of a country.
Answer:

• There are two ways of getting the citizenship of a country.
• First a child bonr in a country will naurally become citizen of that country.
• Second a citizen can give up the citizenship of the country of his birth and become the citizen of another country.

Question 30.
How can you help senior citizens?
Answer:
I will help them to cross the road. I will give them seat in the bus.

Question 31.
What is citizenship?
Answer:
Membership of a country.

Question 32.
When does a citizen lose his citizenship
Answer:
If a citizen of a country takes up the citizenship of another country automatically he loses his previous citizenship one can not be the citizen of two countries at the same time.

Question 33.
Write any three duties of a citizen of India.
Answer:

• Honoring the national anthem and the National flag.
• Casting one’s vote in elections.
• Obedience to the laws of the country.

Question 34.
Who did the king bring to the throne?
Answer:
His first son

Question 35.
Who should naturally come to the throne after the King according to Indian tradition?
Answer:
The first son should naturally come to the throne after the king according to Indian tradition.

Question 36.
What happens if during the rule of the King there is a dispute for power?
Answer:
People are uncared for. They become unhappy with the king.

Question 37.
Do you like the hereditary(dynastic) rule?
Answer:
No.

Question 38.
What is democracy?
Answer:
Rule of a state by the elected representatives of the people is democracy.

Question 39.
What is the importance of democracy?
Answer:

• Government will be run by the representatives elected by the people.
• All people are equal before the law’
• Elections will be held regularly and new’ representatives come to power.
• Issues will be discussed and people-friendly decisions will be taken.

Question 40.
What is the lower age limit in India for voters?
Answer:
18 years.

Question 41.
Why is voting important?
Answer:
Voting is an important means of expression ofavoter’swill. It makes representation of all people possible. It is a citizen’s duty.

Question 42.
What is called secret ballot?
Answer:
People give their votes in a method is called secret ballot.

Question 43.
What is election?
Answer:
Choosing people’s representatives

Question 44.
Mention an important part of the election process?
Answer:
Polling.

Question 45.
Why is voting important?
Answer:
Voting is an important means of expression of a voter’s will. It makes representation of all people possible. It is a citizen’s duty.

Question 46.
Why did they given symbols to the candidates?
Answer:
Illiterates can vote with thehelp of the symbol to the canndidate of their choice.

Question 47.
Write the defects of democracy.
Answer:

• Money and muscles power may be used to get votes
• Caste, community, language, religion etc.., may influence voting. .
• Some times elected members resort to defection from one party to the other.

Question 48.
Explain the process of election.
Answer:

• Filling of nomination by the candidates.
• Canvassing by candidates and supporters
• Voting on a date already fixed.
• Announcement of results on a day fixed in calendar of events.
• Publication of the list of successful candidates.

Question 49.
What is the purpose of self – government?
Answer:
To establish self- Government in villages/towns

• The empowerment of SC, ST, and women by providing reservations of seats.
• To activate administration by delegation of power.

Question 50.
Who are the members of the gram – sabha?
Answer:
All those aged 18 years and above will be members of gram sabha.

Question 51.
What categories of people have reservations in Panchayat Institutions?
Answer:
SC, ST other backward communities and women have reservations of seats in Panchayat institution.

Question 52.
What are the sources of income for Panchayat Raj Institutions?
Answer:
Sources of income for a panchayat are the grants from government Zila panchayats, taxes and rent from the people of the locality.

Question 53.
Which cities in Karnataka have corporation?
Answer:
Bengaluru, Mysuru, Beigavi, Mangaluru, Gulbarga, Hubli-Dharwad and Bellary.

Question 54.
Mention the sources of income of City Corporations.
Answer:
Government gives gmats, Property tax is another major source of income, water cess, health cess, education cess, reading room cess, beggary cess, fire cess, and rents are the sources of income.

Question 55.
How many city corporation are there in Karnataka?
Answer:
Seven.

Question 56.
Expand C.E.O.
Answer:
Chief Executive Officer.

Question 57.
Who is the chief officer of Zilla Panchayat?
Answer:
Executive officer.

Question 58.
Name any two standing committees.
Answer:
Education and Health.

Question 59.
Write the main function of a panchayat.
Answer:
Main function of a panchayat is to take up development works in the area.

Question 60.
How many local bodies in urban areas? Name them.
Answer:
There are three local bodies for the urban areas, Town panchayat Nagara Palikes, Mahanagar palikes.

Question 61.
Explain the functions of the Zilla Panchayat.
Answer:

• Preparing annual plan for the development of Zilla Parishat area.
• Providing relief to victims of natural calamities.
• Monitoring of the comprehensive development programmes of the district.
• Monitoring of government schools in the Zilla Panchayat.

Class 5 EVS Our India – Political and Cultural Additional Questions and Answer

I. Multiple choice questions:

Question 1.
Give an example of public property,
a. House
b. Train
c. Computer
d. School
Answer:
b. Train

Question 2.
Give an example of private property,
a. House
b. Bus
c. Business
d. Vidhan Soudha
Answer:
a. House

Question 3.
What is on set?
a. Set up
b. Start
c. Business
d. Historical monuments.
Answer:
d. Historical monuments.

Question 4.
Public property is also known as
a. People’s property
b. Our property
c. Common property
d. Government property.
Answer:
d. Government property.

Question 5.
Tax means
a. Money collected compulsorily by government.
b. money is paid by the employees.
c. money is cut for the income tax.
d. money is paid as foreign duty.
Answer:
a. Money collected compulsorily by government.

Question 6.
Citizen is called
a. Foreigner
b. Stranger
c. Alien
d. Resident
Answer:
d. Resident

Question 7.
Chamundeswari temple is located in
a. Bangalore
b. Channapatana
c. Mandya
d. Mysore.
Answer:
d. Mysore.

Question 8.
Each candidate is given at the time of election
a. Car
b. Security
c. Symbol
d. Bungalow
Answer:
c. Symbol

Question 9.
Name and symbol of candidate is called as
a. Selection
b. Election
c. Voting
d. Counting
Answer:
a. Selection

Question 10.
The terms of the Panchayat is
a. 6
b. 5
c. 7
d. 10
Answer:
b. 5

Question 11.
Urban areas have the type of Panchayat is called
a. Village
b. Town
c. Grama
d. District
Answer:
b. Town

Question 12.
Gram sabha meets at least
a. 3
b. 4
c. 2
d. 1
Answer:
c. 2

Question 13.
The number of city corporations in Karnataka at present is
a. Seven
b. Five
c. Three
d.Ten.
Answer:
a. Seven

II. Fill in the blanks:

1. The official language of Goa is Marathi
2. The Capital city of Nagaland is Kohima
3. The name of the present chief minister of Jammu & Kashmir is Mehbooba Mufti
4. The present President of India is Pranab Mukherjee
5. The present Govemer of Karnataka is Vaiubhai Rudabai vala
6. Recently Andra pradesh was divided into Seemandra & Telangana
7. The present prime minister of India is Narendra Modi
8. The present chief minister of Karnataka is Siddaramaiah.
9. Roads, Railways are examples of Public property.
10. When we damage public property we harm ourselves.
11. Historical monuments are a part of our country.
12. Our clothes, shoes, etc., are examples of personal property.
13. It is our duty to protect public property.
14. Tax money will be wasted if public property is destroyed.
15. Public property is all our assets.
16. Government and other organizations have built them for the use of all people.
17. Citizens ar the permanent residents of this country.
18. Membership of a country is citizenship
19. Foreigners are different from us in dress language etc.
20. Obedience is to the laws of the country.
21. Democracy is the political system
22. All people are equal before the law
23. Democracy is the popular system of government.
24. If people are wise, democracy will survive otherwise it will be lost.
25. Each candidate is given a symbol
26. We should form a queue at the bus stop.
27. Urban areas have town panchayat.
28. Terms of the Panchyat are five years.
29. Gram sabha forms the first step of the Panchayat system
30. Zilla panchayat will have many committees
31. Executive officer is appointed by the state government.
32. Municipality will be administered by the chief officer.
33. Commissioner will be the chief officer for . corporation.
34. Gram sabha meets at least two times in a year.

III. Match the following:

1.

A	B
1. City corporation	a. Taluk level
2. Taluk panchayat	b. District level
3. Grama Panchayat	c. Term will be for 5 years.
4. Zilla panchayt	d. Mahanagar palike
5. Corporators	e. Village level

Answer:

1. d
2. a
3. e
4. b
5. c

2.

A	B
1. Polling booth	a. Name and symbol of candidate.
2. Ballot paper	b. Political system
3. Hereditary	c. Votes
4. democracy	d. Prince
5. Yuvaraja	e. Dynasty

Answer:

1. c
2. a
3. e
4. b
5. d

3.

A	B
1. Queue	a. Membership of a country
2. Good citizen	b. Chamundeswari temple
3. Mysore	c. Good qualities
4. Citizenship	d. Tourist
5. Other country	e. Theatre citizen

Answer:

1. e
2. c
3. a
4. b
5. d

4.

A	B
1. Occupation	a. Public property
2. Ornaments	b. We use every day
3. Historical monuments	c. Private property
4. Household articles	d. Service
5. Facility	e. Business

Answer:

1. e
2. c
3. a
4. b
5. d

Students can Download Maths Chapter 2 Addition Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 2 Addition

KSEEB Class 5 Maths Addition Revision Exercise

I. Add the following numbers:

1) 4.368 + 2.521

2) 2.673 + 5.134

3) 3.653 + 4.213 + 1.156

4) 1.345 + 2.463 + 564

II. Solve the following problems:

1. Sanmati deposited Rs. 3,672 on Monday and Rs 4,678 on Tuesday in the bank. Find the amount deposited by her.

Sanmati deposit – Rs 3,672 on Monday
Sanmati deposit – Rs 4,678 on Tuesday
Total amount deposit by Sanmati – Rs 8,350

2. The population of a village is 3,389. The population of another village is 4,893. Find the total population of both the villages
The population of a village – 3,389
The population of Another village – 4,893
Total population of both villages – 8,282

3. The number of students of first standard in all the schools of a panchayat is 1,673, second standard is 1,845, third standard is 1,437 and the fourth standard is 1,547. Find the total number of students.

In a panchayat the member of students of 1st standard – 1,673
In a panchayat the member of students of 2nd standard – 1,845
In a panchayat the’member of students of 3rd standard – 1,437
In a panchayat the member of students of 4th standard -1,547
The total number of students – 6,502

KSEEB Class 5 Maths Addition Revision Ex 2.1

I. Find the sum of each of the following:

1) 36,417 + 32,532

2) 28,490 + 61,306

3) 12,973 + 46,016

4) 23462 + 52,304

5) 42,802 + 34,063

II. Find the sum of each of the following:

1. 36,907 + 53,613

2. 24,296 + 36,578

3. 43,374 + 36,654

4. 25,700 + 2,246 + 16,413

5. 25,236 + 34,051 + 8,368

III. Solve the following problems:

1. There were 26,759 trees in the protected area of a forest. 13,842 trees were planted during Vanamahostava. Find the total number of trees in the protected area of the forest.
There were trees in the protected area
Trees were planted – 26,759
During vanamahotsava – 13,842
The total number of trees in the protected area of the forest – 40,601

2. A co-operative milk dairy collects 15,209 liters of milk from farmers in a week and 16,826 liters of milk in the next week. How many liters of milk was collected from the farmers in two weeks?
A co-operative milk diary collect of milk from farmers in a week – 15,209
Milk from farmers in the next week – 16,826
The total liters of milk from farmers – 32,035

3. An Indian cricketer scored 14,025 runs in the test cricket matches and 15,759 runs in one-day cricket matches. How many runs did the cricketer score in all?
An Indian cricketer scored runs in the test cricket matches – 14,025
Runs scored in one-day matches – 15,759
The total runs scored in both matches – 29,784

4. A public library in a city has 17,943 books in Kannada, 14,635 books in Hindi and 10,284 books in English. How many books are there in the library altogether?
In a city, A public library books in Kannada – 17,943
In a city, A public library books in English – 10,284
In a city, A public library books in Hindi – 14,63 5
The total number of books in the library altogether – 42,862.

5. In an assembly election three candidates were polled 32,135 votes, 29,048 votes and 4,951 votes respectively. Find the total number of votes polled.
In a election three candidates were polled – 32,135 votes
The total number of votes polled – 66,134

6. The population of a town is 54,872 and another town is 45,127. Find the total population of both the towns. (Additional Question)
The population of a town – 54,872
The population of another town – 45,127
The total population of both the towns – 99,999.

7. During Dasara exhibition, 4,826 people visited agricultural stall, .15,468 people visited popcorn stall and 8,401 people visited handicraft stall. How many people visited these three stalls? (Additional Question)
During dasara Exhibition.
Agricultural stall – 04826 People
Popcorn stall – 15468 People
Handicraft stall – 08401 People
The total number of peoples in three stales – 28,695.

8. A Charitable trust distributes Rs. 9,275 as a scholarship to the students in the month of July and Rs. 10,325 in the month of August Find the total amount of scholarships distributed.
A charitable trust distributes (Additional Question)
Scholarships – 09,275
students in July Scholarships – 10,325
students in August. – 19,600
The total amount of scholarship – Rs 19,600.

Students can Download Maths Chapter 1 5-Digit Numbers Questions and Answers, Summary, Notes Pdf, KSEEB Solutions for Class 5 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

Karnataka State Syllabus Class 5 Maths Chapter 1 5-Digit Numbers

KSEEB Class 5 Maths 5-Digit Numbers Revision Exercise

I. Write the place value chart for the given numbers:

II. Write the following words:

1) 1,739: Thousand seven hundred and thirty-nine.
2) 3,007: Three thousand and seven.
3 ) 4,088: Four thousand and eighty-eight.
4) 11,900: Eleven thousand and Nine hundred only

III. Write in figures:

1. Nine thousand three hundred fifteen.
9,315

2. Two thousand four hundred.
2,400

3. Seven thousand thirty-six.
7,036

IV Answer the following:

1. Write the greatest 3-digit number.
999

2. Write the smallest 3-digit number.
100

3. Write the greatest and smallest 4-digit number.
9999, 1000

V. Compare the numbers and write = , > or < sign in between the numbers.

1. 3,567 < 4,567
2. 6.582 > 6,385
3. 7384 = 7,384

VI. Write the greatest and the smallest 4-digit numbers using the following, digits (without repeating the digits).

1) 1, 2, 3, 4
4321 – Greatest Number
1234- Smallest Number

2) 6, 3, 8, 0
8630 – Greatest Number
3680 – Smallest Number

3) 5, 2, 7, 4
7542 – Greatest Number
2457 – Smallest Number

VII. Write the following numbers in ascending order

1) 2,456 2,465 2,565 2,546
2,456, 2,465, 2,546, 2,565

2) 5,768 5,678 5,687 5,867
5,678, 5,687, 5,768, 5,867

3) 8,901 8,910 8,109 8,190
8,109, 8,190, 8,901, 8,910

VIII. Write the following numbers in descending order:

1) 2,947 3,038 2,930 3,830
3,830, 3,038, 2,947, 2,930.

2) 4,892 4,982 4,082 4,792
4,982, 4,892, 4,792, 4,082.

3) 5,678 5,778 5,878 5,978
5,978, 5,878, 5,778, 5,678.

KSEEB Class 5 Maths 5-Digit Numbers Ex 1.1

I. Insert commas at appropriate places in the following numbers. Write in words.

1) 32894
32,894

2) 18415
18,415

3) 99999
99,999

4) 40003
40,003

II. Write the following numbers in figures using commas.

1) Forty-five thousand six hundred eighteen.
45,618

2) Eighty-two thousand three.
82,003

3) Thirteen thousand seven hundred nine.
13,709

4) Ninety-four thousand three hundred fourteen.
94,314

III. Write the following numbers in the expanded form.

1) 19,203
1 × 10,000 + 9 × 1000 + 2 × 100 + 0 × 10 + 3 × 1

2) 77,777
7 × 10,000 + 7 × 1000 + 7 × 100 + 7 × 10 + 7 ×1

3) 38,294
3 × 10,000 + 8 × 1000 + 2 × 100 + 9 × 10 + 4 × 1

II. Write the following expanded form of 4 numbers in the standard form.
Example:

1) 6 × 10,000 + 1 × 1,000 + 7 × 100 + 9 × 10 + 5 × 1 = 61,795

2) 4 × 10,000 + 0 × 1,000 + 0 × 100 + 0 × 10 + 1 × 1
40,001

3) 9 × 10,000 + 0 × 1,000 + 6 × 100 + 0 × 10 + 9 × 1
90,609

4) 6 × ten thousand + 3 × thousand + 5 × hundred + 1 × ten + 7 × unit
63,517

5) 1 × ten thousand + 1 × thousand + 4 × hundred + 7 × ten + 4 × unit
11,474

V. form the greatest and the smallest 5-digit numbers using the following digits without repetition.

1) 3, 1, 4, 7, 9
97,431 – Greatest Number
13,479 – Smallest Number

2) 8, 1, 6, 2, 5
86,521 – Greatest Number
12,568 – Smallest Number

3) 7, 0, 6, 1, 3
76,310 – Greatest Number
10,367 – Smallest Number

4) 6, 4, 5, 7, 0
76,540 – Greatest Number
45,067 – Smallest Number

5) 2, 5, 7, 3, 4
75,432 – Greatest Number
23,457 – Smallest Number

VI. Complete the table:

S. NO	Proceeding number	Number	Succeeding number
1.	57,838	57,839	57,840
2.	18,375	18,376	18,377
3.	40,779	40,780	40,781
4.	88,889	88,890	88,891
5.	13,584	13,585	13,586

VII. Follow the pattern and complete the series:

1. 23,344, 23,444, 23,544, 23,644, 23,744
2. 15,790, 35,790, 55,790, 75,790, 95,790
3. 88,888, 78,888, 68,888, 58,888, 48,888
4. 30,453, 33,453, 36,453, 39,453, 42,453
5. 58,600, 62,600 66,600, 70,600, 74,600

VIII. Write the following numbers in increasing order (Ascending order):

1) 30,435, 70,533, 20,411 40,623
20,411, 30,435, 40,623. 70,533

2) 44,444, 44,044, 40,444, 40,044
40,044, 40,444, 40,044, 44,444

3) 63,841, 63,481, 63,148, 6,184
63,148, 63,184, 63,481, 63,841

4) 5o,060 5000, 55,000 50,006
50,006, 50,060, 50,500, 55,000

5) 20,325, 20,825, 20,302 20,413
20,302, 20325, 20,413, 20825

IX. Write the following numbers in a (Descending order)

1) 23,456, 34,567, 12,345, 45,678
45, 678, 34, 567, 23, 456, 12, 345

2) 40,564, 45,064, 45,604, 40,456
45, 604, 45, 064, 40, 564, 40, 456

3) 12,344, 12,340, 12,304, 13,244
13, 244, 12, 344, 12, 340, 12, 304

4) 77,770, 77,077, 77,777, 70,777
77, 777, 77, 770, 77, 077, 70, 777

5) 61, 234, 62, 134, 21, 364, 12, 364
62, 134, 61, 234, 21, 364, 12, 364.

X. Compare the following given numbers. Write =, > or < sign in the blanks:

1) 52,085 = 52,085
2) 46,431 > 43,613
3) 15,662 < 24,672
4) 74,312 < 76,312
5) 81,884 > 81,365