{"id":507,"date":"2023-11-01T06:23:58","date_gmt":"2023-11-01T00:53:58","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=507"},"modified":"2023-11-02T10:29:14","modified_gmt":"2023-11-02T04:59:14","slug":"kseeb-solutions-class-9-maths-chapter-4-ex-4-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-class-9-maths-chapter-4-ex-4-1\/","title":{"rendered":"KSEEB Solutions for Class 9 Maths Chapter 4 Polynomials Ex 4.1"},"content":{"rendered":"

KSEEB Solutions for Class 9 Maths Chapter 4 Polynomials Ex 4.1<\/strong> are part of KSEEB Solutions for Class 9 Maths<\/a>. Here we have given Karnataka Board Class 9 Maths Chapter 4 Polynomials Exercise 4.1.<\/p>\n

Karnataka Board Class 9 Maths Chapter 4 Polynomials Exercise 4.1<\/h2>\n

Question 1.
\nWhich of the following expressions are polynomials in one variable and which are not ? State reasons for your answer.
\ni) 4x2<\/sup> – 3x + 7
\nii) y2<\/sup> + \\(\\sqrt{2}\\)
\niii) \\(3 \\sqrt{t}+t \\sqrt{2}\\)
\niv) \\(\\mathrm{y}+\\frac{2}{\\mathrm{y}}\\)
\nv) x10<\/sup> + y3<\/sup> + t50<\/sup>
\nAnswer:
\ni) 4x2<\/sup> – 3x + 7
\nHere polynomial has one variable, i.e. x
\nii) y2<\/sup> + \\(\\sqrt{2}\\)
\nHere polynomial has one variable, i.e. y
\niii) \\(3 \\sqrt{t}+t \\sqrt{2}\\)
\nThis is polynmomial with one variable, because T is only one variable.
\niv) \\(\\mathrm{y}+\\frac{2}{\\mathrm{y}}\\)
\nHere polynomial has one variable, ie. y.
\nv) x10<\/sup> + y3<\/sup> + t50<\/sup>
\nThis polynomial is not having one variable because here 3 variables means ‘x’, y and ‘t’ are there.<\/p>\n

Question 2.
\nWrite the coefficients of x in each of the followng :
\ni) 2 + x2<\/sup> + x
\nii) 2 – x2<\/sup> + x3<\/sup>
\niii) \\(\\frac{\\pi}{2}\\)x2<\/sup> + x
\nv) \\(\\sqrt{2} \\mathrm{x}\\) – 1
\nAnswer:
\ni) 2 + x2<\/sup> + x
\nHere, coefficient of x2<\/sup> is 1.
\nii) 2 – x2<\/sup> + x3<\/sup>
\nHere coefficient of x2<\/sup> is -1
\niii) \\(\\frac{\\pi}{2}\\)x2<\/sup> + x
\nHere coefficient of x2<\/sup> is \\(\\frac{\\pi}{2}\\).
\niv) \\(\\sqrt{2} \\mathrm{x}\\) – 1
\nHere coefficint of x2<\/sup> is -1.<\/p>\n

Question 3.
\nGive one example each of a binomial of degree 35, and of a monomial of degree 100
\nAnswer:
\ni) A Bionomial of degree 35
\nE.g. f(x) = – x35<\/sup> + 10
\nii) A binomial of degree 100
\nE.g. f(y) = – y100<\/sup>.<\/p>\n

Question 4.
\nWrite the degree of each of the following polynomials :
\ni) 5x3<\/sup> + 4x2<\/sup> + 7x
\nii) 4 – y2<\/sup>
\niii) 5t – \\(\\sqrt{7}\\)
\niv) 3
\nAnswer:
\ni) 5x3<\/sup> + 4x2<\/sup> + 7x Highest power (degree) 3
\nii) 4 – y2<\/sup> Highest power degree) 2
\niii) 5t – \\(\\sqrt{7}\\) Highest power (degree) 1
\niv) 3 Highest power (degree) 0<\/p>\n

Question 5.
\nClassify the folloiwng as linear, quadratic and cubic polynomials :
\ni) x2<\/sup>\u00a0+ x
\nii) x – x3<\/sup>
\niii) y + y2<\/sup> + 4
\niv) 1 + x
\niii) 3t
\niv) r2<\/sup>
\nvii) 7x3<\/sup>
\nAnswer:<\/p>\n\n\n\n\n\n\n
Linear Polynomial<\/strong><\/td>\nQuadratic Polynomial<\/strong><\/td>\nCubic Polynomial<\/strong><\/td>\n<\/tr>\n
iv) 1 + x<\/td>\ni) x2<\/sup>\u00a0+ x<\/td>\niii) y + y2<\/sup> + 4<\/td>\n<\/tr>\n
<\/td>\n<\/td>\nii) x – x3<\/sup><\/td>\n<\/tr>\n
(v) 3t<\/td>\n(vi) r2<\/sup><\/td>\n(vii) 7x3<\/sup><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

We hope the KSEEB Solutions for Class 9 Maths Chapter 4 Polynomials Ex 4.1 help you. If you have any query regarding Karnataka Board Class 9 Maths Chapter 4 Polynomials Exercise 4.1, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"

KSEEB Solutions for Class 9 Maths Chapter 4 Polynomials Ex 4.1 are part of KSEEB Solutions for Class 9 Maths. Here we have given Karnataka Board Class 9 Maths Chapter 4 Polynomials Exercise 4.1. Karnataka Board Class 9 Maths Chapter 4 Polynomials Exercise 4.1 Question 1. Which of the following expressions are polynomials in one …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/507"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=507"}],"version-history":[{"count":1,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/507\/revisions"}],"predecessor-version":[{"id":90875,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/507\/revisions\/90875"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=507"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=507"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=507"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}