{"id":4677,"date":"2020-09-09T11:34:51","date_gmt":"2020-09-09T06:04:51","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=4677"},"modified":"2021-07-02T15:03:35","modified_gmt":"2021-07-02T09:33:35","slug":"kseeb-solutions-class-8-maths-chapter-16-ex-16-2","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-class-8-maths-chapter-16-ex-16-2\/","title":{"rendered":"KSEEB Solutions for Class 8 Maths Chapter 16 Mensuration Ex 16.2"},"content":{"rendered":"

Students can Download Maths Chapter 16 Mensuration Ex 16.2 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka Board Class 8 Maths Chapter 16 Mensuration Ex 16.2<\/h2>\n

Question 1.
\nFind the total surface area and volume of a cube whose length is 12 cm.
\nAnswer:
\nl = 12 cm
\nT.S.A of cube = 6 l\u00b2 = 6 x 12\u00b2 = 6 x 144 = 864 cm\u00b2
\nVolume of cube = P = (12)3<\/span><\/sup><\/span> = 1728 cm3<\/span><\/sup><\/span><\/p>\n

Question 2.
\nFind the volume of a cube whose surface area is 486 cm\u00b2.
\nAnswer:
\nT.S.A of a cube = 486 cm\u00b2
\n612<\/sup>\u00a0= 486
\nl\u00b2 = \\(\\frac{486}{6}\\)
\nl\u00b2 = 81
\n\u2234 l = \u221a81 = 9 cm
\nVolume = l3<\/sup>\u00a0= 93<\/sup>= 729 cm3<\/sup><\/p>\n

Question 3.
\nA tank, which is cuboidal in shape has a volume 6.4m3<\/span><\/sup><\/span>. The length and breadth of the base are 2m and 1.6m respectively. Find the depth of the tank.
\nAnswer:
\nV = 6.4 m3<\/sup>
\nl = 2 m
\nb = 1.6 m
\nh = ?
\nVolume of cuboid = 6.4 m3<\/sup>
\nl \u00d7 b \u00d7 h = 6.4
\n2 \u00d7 1.6 \u00d7 h = 6.4
\n3.2h = 6.4
\nh =\u00a0\\(\\frac{6.4}{3.2}\\)
\nh = 2m
\nh = 2m .
\n\u2234 The depth of the tank is 2 m.<\/p>\n

Question 4.
\nHow many m3<\/span><\/sup><\/span> of soil has to be excavated from a rectangular well 28cm deep and whose base dimensions are 10cm and 8m. Also, find the cost of plastering its vertical walls at the rate of Rs. 15\/m2.
\nAnswer:
\nl = 10 m
\nb = 8
\nh = 28 m
\nVolume of soil = volume of cuboid
\n= l \u00d7 b \u00d7 h = 10 \u00d7 8 \u00d7 28 = 2240 m3<\/sup>
\n2240 m3<\/sup>\u00a0of soil has to be excavated.
\nArea to be plastered = L.S.A of cuboid
\n= 2h(l + b)
\n= 2 \u00d7 28(10 + 8)
\n= 56 \u00d7 18
\n= 1008 m2<\/sup>
\nThe cost of plastering 1m\u00b2 = Rs. 15
\n\u2234 The cost of plastering = 15 \u00d7 1008 = Rs. 15,120<\/p>\n

Question 5.
\nA solid cubical box of fine wood costs Rs. 256 at the rate of Rs. 500\/m3. Find its volume and length of each side.
\nAnswer:
\nThe cost of Rs. 500 is for 1m3<\/span><\/sup><\/span>.
\nThe cost of Rs. 256 is for
\n\\(\\frac{256}{500}=\\frac{128}{250}=\\frac{64}{125} \\mathrm{m}^{3}\\)
\n\u2234 Volume of the wood = \\(\\frac{64}{125} \\mathrm{m}^{3}\\) = 0.512 m3<\/span><\/sup><\/span>
\nVolume = 0.512m
\nl3<\/span><\/sup><\/span> = 0.512
\n\\(l=\\sqrt[3]{0.512}\\)
\nl = 0.8 m\u00b2
\n= 0.8 \u00d7 100
\nLength of the side = 80cm, l= 80cm<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Maths Chapter 16 Mensuration Ex 16.2 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka Board Class 8 Maths Chapter 16 Mensuration Ex 16.2 Question 1. Find the total surface area and …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/4677"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=4677"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/4677\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=4677"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=4677"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=4677"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}