{"id":4451,"date":"2020-09-09T06:48:25","date_gmt":"2020-09-09T01:18:25","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=4451"},"modified":"2021-07-02T15:03:36","modified_gmt":"2021-07-02T09:33:36","slug":"kseeb-solutions-class-8-maths-chapter-11-ex-11-7","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-class-8-maths-chapter-11-ex-11-7\/","title":{"rendered":"KSEEB Solutions for Class 8 Maths Chapter 11 Congruency of Triangles Ex 11.7"},"content":{"rendered":"

Students can Download Maths Chapter 11 Congruency of Triangles Ex 11.7 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka Board Class 8 Maths Chapter 11 Congruency of Triangles Ex 11.7<\/h2>\n

Question 1.
\nIn a triangle ABC, \u2220B = 28\u00b0 and \u2220C= 56\u00b0. Find the largest and smallest side.
\nAnswer:
\n\"KSEEB
\n\u2220A + \u2220B + \u2220C = 180\u00b0
\n[Sum of the angles of a triangle]
\n\u2220A + 28 + 56 = 180\u00b0
\n\u2220A + 84\u00b0 = 180\u00b0
\n\u2220A = 180 – 84
\n\u2220A = 96\u00b0
\nBC is the largest side
\n[Opposite to largest angle \u2220A]
\nAC is the smallest side
\n[Opposite to smalles angle \u2220B]<\/p>\n

Question 2.
\nIn a triangle ABC, we have AB = 4cm, BC = 5.6 cm and CA = 7.6 cm. Write the angles of the triangle in ascending order
\nof measures.
\nAnswer:
\n\"KSEEB
\n\u2220C <\u2220A <\u2220B<\/p>\n

Question 3.
\nLet \u0394ABC be a triangle such that \u2220B = 70\u00b0 and\u2220C = 40\u00b0. suppose D is a point on BC such that AB = AD. Prove that AB > CD.
\n\"KSEEB
\nAnswer:
\nIn \u0394 ABD, AB = AD
\n\u2234 \u2220ABD = \u2220 APB = 70\u00b0 [Theorem]
\n\u2220APB +\u2220 ADC = 180\u00b0 [Linear pair]
\n70 + \u2220ADC = 180\u00b0
\n\u2220ADC = 180 – 70\u00b0
\n\u2220ADC = 110\u00b0
\nIn \u0394 ADC,
\n\u2220DAC = 180 – ( 110 + 40)
\n= 180 – 150
\n\u2220DAC = 30\u00b0
\nIn \u0394 ADC,
\n\u2220ACD > \u2220DAC
\nAD > CD
\nbut AB = AD
\n\u2234 AB > CD<\/p>\n

Question 4.
\nLet ABCD be a quadrilateral in which AD is the largest side and BC is the smallest side. Prove that|A <[C. [Hint: Join AC]
\n\"KSEEB
\nAnswer:
\nJoin AC
\nIn \u0394 ABC\u00a0 \u00a0AB > BC [BC is the smallest side]
\n\u2234 \u2220ACB > \u2220BAC \u2026(i)
\nIn \u0394 ADC, AD > DC [AD is the largest side]
\n\u2220ACD > \u2220PAC \u2026(ii)
\nBy adding (i) and (ii)
\n\u2220ACB + \u2220ACD > \u2220BAC + \u2220DAC
\n\u2220BCD > \u2220BAD or
\n\u2220BAD < \u2220BCD
\n\u2234\u2220A < \u2220C<\/p>\n

Question 5.
\nLet ABC be a triangle and P be an interior point, prove that AB + BC + CA < 2(PA + PB + PC).
\n\"KSEEB
\nAnswer:
\nIn \u0394PBA, AB < PA + PB \u2026.(i)
\nIn \u0394PBC, BC < PB + PC \u2026.(ii)
\nIn \u0394PCA, AC < PC + PA \u2026.(iii)
\nBy adding (i), (ii), and (iii)
\nAB + BC + AC < PA + PB + PB + PC + PC + PA > 2PA + 2PB + 2PC
\nAB + BC + AC < 2 (PA + PB + PC).<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Maths Chapter 11 Congruency of Triangles Ex 11.7 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka Board Class 8 Maths Chapter 11 Congruency of Triangles Ex 11.7 Question 1. In a …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[6],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/4451"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=4451"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/4451\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=4451"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=4451"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=4451"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}