{"id":27572,"date":"2020-07-04T17:43:24","date_gmt":"2020-07-04T12:13:24","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=27572"},"modified":"2021-07-02T15:07:07","modified_gmt":"2021-07-02T09:37:07","slug":"2nd-puc-physics-previous-year-question-paper-march-2018","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/2nd-puc-physics-previous-year-question-paper-march-2018\/","title":{"rendered":"2nd PUC Physics Previous Year Question Paper March 2018"},"content":{"rendered":"<p>Students can Download 2nd PUC Physics Previous Year Question Paper March 2018, Karnataka <a href=\"https:\/\/kseebsolutions.guru\/2nd-puc-physics-model-question-papers-with-answers\/\">2nd PUC Physics Model Question Papers with Answers<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n<h2>Karnataka 2nd PUC Physics Previous Year Question Paper March 2018<\/h2>\n<p>Time: 3 hrs 15 min<br \/>\nMax. Marks: 70<\/p>\n<p>Instructions<\/p>\n<ul>\n<li>All parts are compulsory.<\/li>\n<li>Answer without relevant diagram\/figure\/circuit wherever necessary will not carry any marks.<\/li>\n<li>Numerical problems solved without writing the relevant formulae carry no marks.<\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"color: #0000ff;\">Part &#8211; A<\/span><\/p>\n<p><span style=\"color: #0000ff;\">I. Answer all the following questions: (10 \u00d7 1 = 10)<\/span><\/p>\n<p>Question 1.<br \/>\nWhat is an equipotential surface?<br \/>\nAnswer:<br \/>\nA surface on which electric potential remains the same at all points is called an equipotential surface.<\/p>\n<p>Question 2.<br \/>\nDefine \u2018drift velocity\u2019 of free electrons.<br \/>\nAnswer:<br \/>\nAn average velocity with which an electron drift in a conductor in a direction opposite to the direction of applied electric field is called drift velocity.<\/p>\n<p>Question 3.<br \/>\nGive an application of cyclotron.<br \/>\nAnswer:<br \/>\nThe cyclotron is used to produce highly energetic charged particles or ions.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/11\/KSEEB-Solutions.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018\" width=\"172\" height=\"16\" \/><\/p>\n<p>Question 4.<br \/>\nState Faraday&#8217;s law of electromagnetic induction.<br \/>\nAnswer:<br \/>\nWhenever magnetic flux linked with the circuit changes, an emf is induced. The amount of emf induced is directly proportional to the time rate of change of magnetic flux linked with the circuit.<\/p>\n<p>Question 5.<br \/>\nIf the peak value of a.c. current is 4.24 A, what is its root mean square value?<br \/>\nAnswer:<br \/>\nI<sub>rms<\/sub> = \\(\\frac{I_{\\text {peak }}}{\\sqrt{2}}\\)<br \/>\n= 0.707 \u00d7 4.24<br \/>\n= 2.9977 A<br \/>\n= 3.0 A<\/p>\n<p>Question 6.<br \/>\nMention one power loss in a transformer.<br \/>\nAnswer:<br \/>\nCopper loss, (flux linkage loss, eddy current loss, hysteresis loss).<\/p>\n<p>Question 7.<br \/>\nTwo lenses of power +1.5D and -0.5D are kept in contact on their principal axis. What is the effective power of the combination?<br \/>\nAnswer:<br \/>\nEffective power P = P<sub>1<\/sub> + P<sub>2<\/sub> = 1.5 &#8211; 0.5 = 1.0D<\/p>\n<p>Question 8.<br \/>\nThe decay of proton to neutron is possible only inside the nucleus. Why?<br \/>\nAnswer:<br \/>\nUnlike neutron, a proton is highly stable. Moreover, the rest mass energy of the proton is less than that of the neutron.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/11\/KSEEB-Solutions.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018\" width=\"172\" height=\"16\" \/><\/p>\n<p>Question 9.<br \/>\nWhat is \u2018depletion region\u2019 in a semiconductor diode?<br \/>\nAnswer:<br \/>\nA small region around the junction free from mobile charge carriers is called depletion region.<\/p>\n<p>Question 10.<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64070\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q10.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q10\" width=\"237\" height=\"135\" \/><br \/>\nWhat is the output of this combination?<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64069\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q10.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q10.1\" width=\"274\" height=\"137\" \/><br \/>\nOutput is &#8216;one&#8217; or &#8216;high state&#8217;.<\/p>\n<p style=\"text-align: center;\"><span style=\"color: #0000ff;\">Part &#8211; B<\/span><\/p>\n<p><span style=\"color: #0000ff;\">II. Answer any five of the following questions: (5 \u00d7 2 = 10)<\/span><\/p>\n<p>Question 11.<br \/>\nMention any two factors on which the capacitance of a parallel plate capacitor depends.<br \/>\nAnswer:<br \/>\nThe ratio of electric charge on the conductor to its electric potential is known as the electrical capacitance of the conductor.<\/p>\n<p>Question 12.<br \/>\nState Kirchhoff&#8217;s laws of the electrical network.<br \/>\nAnswer:<br \/>\nKirchoff&#8217;s law<\/p>\n<ol>\n<li>Loop Law: The algebraic sum of the voltage drop across each component is equal to the supplied voltage by the source.<\/li>\n<li>Junction Law: The net (incoming + outgoing) current at each junction should be zero.<br \/>\nIn the case of the Wheatstone bridge, we know that the current through the galvanometer should be zero. i.e I<sub>g<\/sub> = 0<\/li>\n<\/ol>\n<p>Question 13.<br \/>\nDefine magnetic \u2018declination\u2019 and \u2018dip\u2019 at a place.<br \/>\nAnswer:<br \/>\nNorth magnetic pole and south magnetic pole respectively.<br \/>\nA vertical plane containing the longitude circle and the axis of rotatio\u00f1 of the earth is called a geographic meridian.<\/p>\n<p><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/11\/KSEEB-Solutions.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018\" width=\"172\" height=\"16\" \/><\/p>\n<p>Question 14.<br \/>\nWrite an expression for the magnetic potential energy of a magnetic dipole kept in a uniform magnetic field and explain the terms.<br \/>\nAnswer:<br \/>\nMagnetic potential energy<br \/>\nU = \\(\\overrightarrow{\\mathrm{M}} \\cdot \\overrightarrow{\\mathrm{B}}\\)<br \/>\nm \u2192 magnetic moment of dipole<br \/>\nB \u2192 uniform magnetic field<\/p>\n<p>Question 15.<br \/>\nGive any two applications of X-rays.<br \/>\nAnswer:<br \/>\nBroken bones. Today, x-rays are an integral part of contemporary hospitals and medical centres.<br \/>\nRadiation therapy. X-rays play an important role in the fight against cancer, with high energy radiation used to kill cancer cells and shrink tumours.<\/p>\n<p>Question 16.<br \/>\nWhat is \u2018myopia\u2019? How to rectify it?<br \/>\nAnswer:<br \/>\nNearsightedness or myopia is the inability of the eye to focus on distant objects. The nearsighted eye has no difficulty viewing nearby objects. But the ability to view distant objects requires that the light be refracted less.<br \/>\nCorrection: The cure for the nearsighted eye is to equip it with a diverging lens. Since the light is focused in front of the retina, a diverging lens will serve to diverge light before it reaches the eye. This light will then be converted by the cornea and lens to produce an image on the retina.<\/p>\n<p>Question 17.<br \/>\nDraw the diagram representing the schematic arrangement of Geiger-Marsden experimental set up for the alpha particle scattering.<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64071\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q17.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q17\" width=\"620\" height=\"368\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q17.png 620w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q17-300x178.png 300w\" sizes=\"(max-width: 620px) 100vw, 620px\" \/><\/p>\n<p>Question 18.<br \/>\nWrite any two characteristics of nuclear forces.<br \/>\nAnswer:<\/p>\n<ul>\n<li>It is attractive in nature but with a repulsive core.<\/li>\n<li>The range of a nuclear force is very short.<\/li>\n<li>The nuclear force is identical for all nucleons.<\/li>\n<li>At a distance of less than 0.7 Fermi, this force becomes repulsive.<\/li>\n<\/ul>\n<p style=\"text-align: center;\"><span style=\"color: #0000ff;\">Part &#8211; C<\/span><\/p>\n<p><span style=\"color: #0000ff;\">III. Answer any five of the following questions. (5 \u00d7 3 = 15)<\/span><\/p>\n<p>Question 19.<br \/>\nGive three properties of electric charge.<br \/>\nAnswer:<\/p>\n<ul>\n<li>Charges are additive in nature<\/li>\n<li>A charge is a conserved quantity<\/li>\n<li>Quantization of charge<\/li>\n<\/ul>\n<p><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/11\/KSEEB-Solutions.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018\" width=\"172\" height=\"16\" \/><\/p>\n<p>Question 20.<br \/>\nState Ampere&#8217;s circuital law and arrive at the expression for the magnetic field near a straight infinite current-carrying wire.<br \/>\nAnswer:<br \/>\nThe integral of the products of the tangential component of the magnetic field and the element of length \u00a1n a closed loop is equal to \u00b50 times the total current passing through the surface.<br \/>\n\\(\\oint \\overrightarrow{\\mathrm{B}} \\cdot d \\vec{l}=\\mu_{0} \\mathrm{I}\\)<\/p>\n<p>Question 21.<br \/>\nWhat is hysteresis? Define the terms \u2018coercivity\u2019 and \u2018retentivity\u2019 of a ferromagnetic material.<br \/>\nAnswer:<br \/>\nHysteresis: The phenomenon in which the magnetic induction (\\(\\vec{B}\\)) lags behind with respect to the magnetizing field (\\(\\vec{H}\\)) is called hysteresis.<br \/>\nIt occurs when an external magnetic field is applied to a ferromagnet such as iron and the atomic dipoles align themselves with it. Even when the field is removed, part of the alignment will be retained: the material has become magnetized. Once magnetized, the magnet will stay magnetized indefinitely.<\/p>\n<p>Retentivity: The property of the magnetic material to retain magnetism even in the absence of the magnetizing field is known as retentivity or remanence.<\/p>\n<p>Coercivity: The magnetizing field (H) needed to demagnetize the magnetic material completely is known as its coercivity.<\/p>\n<p>Question 22.<br \/>\nArrive at Snell&#8217;s law of refraction, using Huygen&#8217;s principle for the refraction of a plane wave.<br \/>\nAnswer:<br \/>\nWe know that when light travels from one transparent medium to another transparent medium its path changes. So the laws of refraction state that the angle of incidence is the angle between the incident ray and the normal and the angle of refraction is the angle between the refracted ray and the normal.<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64072\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q22.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q22\" width=\"354\" height=\"250\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q22.png 354w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q22-300x212.png 300w\" sizes=\"(max-width: 354px) 100vw, 354px\" \/><br \/>\nThe incident ray, reflected ray and the normal, to the interface of any two given mediums all lie in the same plane. We also know that the ratio of the sine of the angle of incidence and sine of the angle of refraction is constant.<\/p>\n<p>Question 23.<br \/>\nWrite Bohr&#8217;s postulates for the hydrogen atom model.<br \/>\nAnswer:<\/p>\n<ul>\n<li>The atom model provided the basic foundation for the development of quantum mechanics.<\/li>\n<li>The value of Rydberg\u2019s constant R has arrived theoretically.<\/li>\n<li>The theory for the first time predicted the size of an atom in terms of absolute constants.<\/li>\n<li>This model made use of the principle of quantisation of angular momentum and energy states of hydrogen and hydrogenic atoms.<\/li>\n<\/ul>\n<p>Question 24.<br \/>\nDerive an expression for the half-life of a radioactive nuclide.<br \/>\nAnswer:<br \/>\nLet\u2019s find the relation between T\u00bd and the disintegration constant \u03bb. For this, let\u2019s input the following values in the equation<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64073\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q24.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q24\" width=\"233\" height=\"162\" \/><\/p>\n<p>Question 25.<br \/>\nWrite any three distinctions between p-type and n-type semiconductor.<br \/>\nAnswer:<br \/>\np-type Semiconductors<\/p>\n<ul>\n<li>Pure semiconductor \u00a1s doped with elements of III group (acceptors)<\/li>\n<li>Holes are majority charge carriers<\/li>\n<li>Energy levels of dopants are above the upper limit of the valence band.<\/li>\n<\/ul>\n<p>n-type Semiconductors<\/p>\n<ul>\n<li>A pure semiconductor is doped with elements of V group (donors)<\/li>\n<li>Electrons are majority charge carriers.<\/li>\n<li>Energy levels of dopants are below the lower limit of the conduction band.<\/li>\n<\/ul>\n<p><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/11\/KSEEB-Solutions.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018\" width=\"172\" height=\"16\" \/><\/p>\n<p>Question 26.<br \/>\nDraw the block diagram df a generalised communication system.<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64074\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q26.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q26\" width=\"616\" height=\"242\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q26.png 616w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q26-300x118.png 300w\" sizes=\"(max-width: 616px) 100vw, 616px\" \/><\/p>\n<p style=\"text-align: center;\"><span style=\"color: #0000ff;\">Part &#8211; D<\/span><\/p>\n<p><span style=\"color: #0000ff;\">IV. Answer any two of the following questions: (2 \u00d7 5 = 10)<\/span><\/p>\n<p>Question 27.<br \/>\nDefine electric potential due to a point charge and derive at the expression for the electric potential at a point due to a point charge.<br \/>\nAnswer:<br \/>\nConsider the electric potential due to a point charge q, As we move from point A, at distance rA from the charge q, to point B, at distance rB from the charge q, the change in electric potential is<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64077\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q27.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q27\" width=\"251\" height=\"104\" \/><br \/>\nOnly the radial distance r determines the work is done or the potential. We can move through any angle we like and, as long as the radial distance remains constant, no work is done or there is no change in the electric potential.<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64075\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q27.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q27.1\" width=\"372\" height=\"126\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q27.1.png 372w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q27.1-300x102.png 300w\" sizes=\"(max-width: 372px) 100vw, 372px\" \/><br \/>\nThis is the change in electric potential due to a point charge as we move from rA to rB.<br \/>\nWe could ask about the change in electric potential energy as we move a charge q&#8217; from radius rA to rB due to a point charge q<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64076\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q27.2.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q27.2\" width=\"192\" height=\"54\" \/><br \/>\nAs with gravitational potential energy, it is more convenient and, therefore, useful to talk about the electric potential energy or the electric potential relative to some reference point. We will choose that reference point to be infinity. That is, rA = \u221e<br \/>\nThat means we can then write the electric potential at some radius r as V = kq \\(\\frac{1}{r}\\)<br \/>\n\u200b<br \/>\nQuestion 28.<br \/>\nObtain an expression for the effective emf and the effective internal resistance of two cells connected in parallel such that the currents are flowing in the same direction.<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64081\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q28\" width=\"519\" height=\"304\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.png 519w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28-300x176.png 300w\" sizes=\"(max-width: 519px) 100vw, 519px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64078\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q28.1\" width=\"510\" height=\"481\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.1.png 510w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.1-300x283.png 300w\" sizes=\"(max-width: 510px) 100vw, 510px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64079\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.2.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q28.2\" width=\"464\" height=\"455\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.2.png 464w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.2-300x294.png 300w\" sizes=\"(max-width: 464px) 100vw, 464px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64080\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.3.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q28.3\" width=\"582\" height=\"250\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.3.png 582w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q28.3-300x129.png 300w\" sizes=\"(max-width: 582px) 100vw, 582px\" \/><\/p>\n<p>Question 29.<br \/>\nDerive an expression for the magnetic field on the axis of a circular current loop, using Biot-Savart&#8217;s law.<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64085\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q29\" width=\"408\" height=\"272\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.png 408w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29-300x200.png 300w\" sizes=\"(max-width: 408px) 100vw, 408px\" \/><br \/>\nLet R be the radius of a current loop, carrying current I. Let R be a point on the axis of a conductor. Let dB be a magnetic field at P, due to a current element &#8216;idl&#8217;.<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64082\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q29.1\" width=\"522\" height=\"473\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.1.png 522w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.1-300x272.png 300w\" sizes=\"(max-width: 522px) 100vw, 522px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64083\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.2.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q29.2\" width=\"566\" height=\"450\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.2.png 566w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.2-300x239.png 300w\" sizes=\"(max-width: 566px) 100vw, 566px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64084\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.3.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q29.3\" width=\"377\" height=\"238\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.3.png 377w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q29.3-300x189.png 300w\" sizes=\"(max-width: 377px) 100vw, 377px\" \/><\/p>\n<p><span style=\"color: #0000ff;\">V. Answer any two of the following questions: (2 \u00d7 5 = 10)<\/span><\/p>\n<p>Question 30.<br \/>\nArrive at an expression for the impedance of a series LCR circuit using phasor diagram method and hence write an expression for the current through the circuit.<br \/>\nAnswer:<br \/>\nConsider a resistance R, an inductor of self-inductance L and a capacitor of capacitance C connected in series across an AC source. The applied voltage is given by,<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64087\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q30.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q30\" width=\"689\" height=\"475\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q30.png 689w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q30-300x207.png 300w\" sizes=\"(max-width: 689px) 100vw, 689px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64086\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q30.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q30.1\" width=\"687\" height=\"469\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q30.1.png 687w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q30.1-300x205.png 300w\" sizes=\"(max-width: 687px) 100vw, 687px\" \/><\/p>\n<p>Question 31.<br \/>\nDeduce the relation between n, u, v and R for refraction at a spherical surface, where the symbols have their usual meaning.<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64090\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q31\" width=\"492\" height=\"431\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31.png 492w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31-300x263.png 300w\" sizes=\"(max-width: 492px) 100vw, 492px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64088\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q31.1\" width=\"373\" height=\"403\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31.1.png 373w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31.1-278x300.png 278w\" sizes=\"(max-width: 373px) 100vw, 373px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64089\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31.2.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q31.2\" width=\"481\" height=\"369\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31.2.png 481w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q31.2-300x230.png 300w\" sizes=\"(max-width: 481px) 100vw, 481px\" \/><\/p>\n<p>Question 32.<br \/>\nWhat is a rectifier? With suitable circuit describe the action of a full-wave rectifier by drawing input and output waveforms.<br \/>\nAnswer:<br \/>\nFull-wave rectification: The process in which both the halves of a.c. are rectified to obtain a pulsating direct current is known as full-wave rectification.<br \/>\nA transformer with a centre tap is used for full-wave rectification. The input contains ac. A minimum of two diodes are used at the secondary of the transformer. A load resistor is connected between the junction of the N-type semiconductor and the centre tap.<br \/>\nDuring the first half cycle, diode D<sub>1<\/sub> will be forward biased and D<sub>2<\/sub> will be reverse biased so that the current flows from B to centre tap.<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64092\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q32.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q32\" width=\"537\" height=\"225\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q32.png 537w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q32-300x126.png 300w\" sizes=\"(max-width: 537px) 100vw, 537px\" \/><br \/>\nDuring the second half cycle, diode, D<sub>2<\/sub> will be forward biased while D<sub>1<\/sub> will be reverse biased. The current once again takes the same direction from B to the centre tap. The I\/P and the O\/P waveforms are shown in fig.<br \/>\nThe average DC is \\(2\\left(\\frac{V_{p}}{\\pi}\\right)\\)<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64091\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q32.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q32.1\" width=\"636\" height=\"152\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q32.1.png 636w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q32.1-300x72.png 300w\" sizes=\"(max-width: 636px) 100vw, 636px\" \/><\/p>\n<p><span style=\"color: #0000ff;\">VI. Answer any three of the following questions: (3 \u00d7 5 = 15)<\/span><\/p>\n<p>Question 33.<br \/>\nThree charges each equal to +4nC are placed at the three corners of a square of side 2 cm. Find the electric field at the fourth corner.<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64095\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q33.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q33\" width=\"299\" height=\"292\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64093\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q33.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q33.1\" width=\"264\" height=\"159\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64094\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q33.2.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q33.2\" width=\"557\" height=\"459\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q33.2.png 557w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q33.2-300x247.png 300w\" sizes=\"(max-width: 557px) 100vw, 557px\" \/><\/p>\n<p>Question 34.<br \/>\n100 mg mass of nichrome metal is drawn into a wire of area of cross-section 0.05 mm<sup>2<\/sup>. Calculate the resistance of this wire. Given the density of nichrome 8.4 \u00d7 10<sup>3<\/sup> kgm<sup>-3<\/sup> and resistivity of the material as 1.2 \u00d7 10<sup>-6<\/sup> \u2126m<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64097\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q34.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q34\" width=\"389\" height=\"388\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q34.png 389w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q34-150x150.png 150w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q34-300x300.png 300w\" sizes=\"(max-width: 389px) 100vw, 389px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64096\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q34.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q34.1\" width=\"321\" height=\"194\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q34.1.png 321w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q34.1-300x181.png 300w\" sizes=\"(max-width: 321px) 100vw, 321px\" \/><\/p>\n<p>Question 35.<br \/>\nA circular coil of radius 10 cm and 25 turns is rotated about its vertical diameter with an angular speed of 40 rad s<sup>-1<\/sup>, in a uniform horizontal magnetic field of magnitude 5 \u00d7 10<sup>-2<\/sup> T. Calculate the maximum emf induced in the coil. Also, find the maximum current in the coil if the resistance of the coil is 15 \u2126.<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64098\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q35.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q35\" width=\"407\" height=\"394\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q35.png 407w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q35-300x290.png 300w\" sizes=\"(max-width: 407px) 100vw, 407px\" \/><\/p>\n<p><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/11\/KSEEB-Solutions.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018\" width=\"172\" height=\"16\" \/><\/p>\n<p>Question 36.<br \/>\nIn Young&#8217;s double-slit experiment the slits are separated by 0.28 mm and the screen is placed at a distance of 1.4 m away from the slits. The distance between the central bright fringe and the fifth dark fringe is measured to be 1.35 cm. Calculate the wavelength of the light used. Also find the fringe width if the screen is moved towards the slits, for the same experimental setup.<br \/>\nAnswer:<br \/>\nGiven d = 0.28 \u00d7 10<sup>-3<\/sup> m, D = 1.4 m<br \/>\nx = 1.35 \u00d7 10<sup>-2<\/sup> m.<br \/>\n\u03b2&#8217; = ?, D&#8217; = 1.4 &#8211; 0.4 = 1.0 m<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64099\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q36.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q36\" width=\"373\" height=\"368\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q36.png 373w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q36-300x296.png 300w\" sizes=\"(max-width: 373px) 100vw, 373px\" \/><\/p>\n<p>Question 37.<br \/>\nLight of frequency 8.41 \u00d7 10<sup>14<\/sup> Hz is incident on a metal surface. Electrons with their maximum speed of 7.5 \u00d7 10<sup>5<\/sup> ms<sup>-1<\/sup> are ejected from the surface. Calculate the threshold frequency for photoemission of electrons. Also, find the work function of the metal in electron volt (eV). Given Planck&#8217;s constant (h) = 6.625 \u00d7 10<sup>-34<\/sup> Js and mass of the electron 9.1 \u00d7 10<sup>-31<\/sup>\u00a0kg.<br \/>\nAnswer:<br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64101\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q37.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q37\" width=\"416\" height=\"444\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q37.png 416w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q37-281x300.png 281w\" sizes=\"(max-width: 416px) 100vw, 416px\" \/><br \/>\n<img decoding=\"async\" loading=\"lazy\" class=\"alignnone size-full wp-image-64100\" src=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q37.1.png\" alt=\"2nd PUC Physics Previous Year Question Paper March 2018 Q37.1\" width=\"369\" height=\"320\" srcset=\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q37.1.png 369w, https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2020\/07\/2nd-PUC-Physics-Previous-Year-Question-Paper-March-2018-Q37.1-300x260.png 300w\" sizes=\"(max-width: 369px) 100vw, 369px\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Students can Download 2nd PUC Physics Previous Year Question Paper March 2018, Karnataka 2nd PUC Physics Model Question Papers with Answers helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka 2nd PUC Physics Previous Year Question Paper March 2018 Time: 3 hrs 15 min Max. Marks: &hellip;<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[82],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/27572"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=27572"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/27572\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=27572"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=27572"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=27572"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}