{"id":27,"date":"2021-07-29T14:30:56","date_gmt":"2021-07-29T09:00:56","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=27"},"modified":"2021-07-29T15:10:58","modified_gmt":"2021-07-29T09:40:58","slug":"kseeb-sslc-class-10-science-solutions-chapter-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-sslc-class-10-science-solutions-chapter-1\/","title":{"rendered":"KSEEB SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations"},"content":{"rendered":"

KSEEB SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations<\/strong> are part of KSEEB SSLC Class 10 Science Solutions<\/a>. Here we have given Karnataka SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations.<\/p>\n

Karnataka SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations<\/h2>\n

KSEEB SSLC Class 10 Science Chapter 1 Intext Questions<\/h3>\n

Text Book Part I Page No. 6<\/p>\n

KSEEB Solutions For Class 10 Science Question 1.<\/strong>
\nWhy should a magnesium ribbon be cleaned before burning in air?
\nAnswer:
\nMagnesium metal is highly reactive. In stored conditions, it reacts with oxygen to form magnesium oxide over its outer layer. To remove this layer and to expose the underlying metal into air, the magnesium ribbon is cleaned by sandpaper.<\/p>\n

KSEEB Solutions For Class 10 Science Chapter 1 Question 2.<\/strong>
\nWrite the balanced equation for the following chemical reactions.
\ni) Hydrogen + Chlorine \u279d Hydrogen Chloride
\nAnswer:
\nH2<\/sub>(g) + Cl2<\/sub>(g) \u279d 2HCl(g)<\/p>\n

ii) Barium chloride + Aluminium sulphate \u279d Barium sulphate + Aluminium chloride
\nAnswer:
\n3BaCl2<\/sub>(s) + Al2<\/sub>(SO4<\/sub>)3<\/sub>(s) \u279d 3BaSO4<\/sub> + 2Al2<\/sub>Cl3<\/sub>(s)<\/p>\n

iii) Sodium + water \u279d Sodium hydroxide + Hydrogen
\nAnswer:
\n2Na(s) + 2H2<\/sub>O(l) \u279d 2NaOH(aq) + H2<\/sub>(g)<\/p>\n

Chemical Reactions And Equations Class 10 Notes KSEEB Question 3.<\/strong>
\nWrite a balanced chemical equation with state symbols for the following reactions.
\ni) Solutions of barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride.
\nAnswer:
\nBalanced chemical equations with state symbols for the required reactions are as follows:<\/p>\n

    \n
  1. BaCl2<\/sub>(aq) + Na2<\/sub>SO4<\/sub>(aq) \u2192 BaSO4<\/sub>(s) + 2NaCl(aq)<\/li>\n
  2. NaOH(aq) + HCl(aq) + NaCl(aq) + H2<\/sub>O(l)<\/li>\n<\/ol>\n

    Text Book Part I Page No. 10<\/p>\n

    KSEEB Solutions For Class 10th Science Question 1.<\/strong>
    \nA solution of a substance \u2018X\u2019 is used for whitewashing.
    \ni) Name the substance \u2018X\u2019 and write its formula.
    \nAnswer:
    \nThe substance X is calcium Hydroxide. Its formula is Ca(OH)2<\/sub><\/p>\n

    ii) Write the reaction of the substance ‘X\u2019 named in (i) above with water.
    \nAnswer:
    \nCao + H2<\/sub>O \u279d Ca(OH)2<\/sub><\/p>\n

    KSEEB Solutions Class 10 Science Question 2.<\/strong>
    \nWhy is the amount of gas collected in one of the test tubes in Activity
    \nAnswer:
    \n\"KSEEB<\/p>\n

    Water (H2<\/sub>O) contains two parts of hydrogen and one part of oxygen. The ratio of water components i.e., hydrogen and oxygen is 2:1. Therefore, the amount of hydrogen and oxygen produced after water electrolysis is in a ratio of 2:1. This is why during electrolysis the amount of gas collected in hydrogen’s test tubes is double the amount collected in the oxygen’s test tube.<\/p>\n

      \n
    1. Take a plastic mug. Drill two holes at its base and fit rubber stoppers in these holes. Insert carbon electrodes in these rubber stoppers as shown in Figure.<\/li>\n
    2. Connect these electrodes to a 6-volt battery.<\/li>\n
    3. Fill the mug with water such that the electrodes are immersed. Add a few drops of dilute sulphuric acid to the water.<\/li>\n
    4. Take two test tubes filled with water and invert them over the two carbon electrodes.<\/li>\n
    5. Switch on the current and leave the apparatus undisturbed for some time.<\/li>\n
    6. You will observe the formation of bubbles at both electrodes. These bubbles displace water in the test tubes.<\/li>\n
    7. Is the volume of the gas collected the same in both the test tubes?<\/li>\n
    8. Once the test tubes are filled with the respective gases. Remove them carefully.<\/li>\n
    9. Test these gases one by one by bringing a burning candle close to the mouth of the test tubes.<\/li>\n<\/ol>\n

      Caution:<\/p>\n

        \n
      1. This step must be performed carefully by the teacher.<\/li>\n
      2. What happens in each case?<\/li>\n
      3. Which gas is present in each test tube?<\/li>\n<\/ol>\n

        Text Book Part I Page No. 13<\/p>\n

        KSEEB 10th Science Solutions Question 1.<\/strong>
        \nWhy does the colour of copper sulphate solution change when an iron nail is dipped in it?
        \nAnswer:
        \nIron is more reactive than copper. When an iron nail is dipped in copper sulphate solution, iron forms its sulphate (iron sulphate) solution by displacing copper of copper sulphate. The colour of iron sulphate is green. So, colour change in solution appears.<\/p>\n

        KSEEB Solutions For Class 10 Science Textbook Question 2.<\/strong>
        \nGive an example of a double displacement reaction other than the one given in Activity 1.10.
        \nAnswer:
        \n2KBr(aq)+BaI2<\/sub>(aq) \u279d 2KI(aq) + BaBr2<\/sub> (aq)<\/p>\n

        KSEEB Solutions For 10th Science Question 3.<\/strong>
        \nIdentify the substances that are oxidised and the substances that are reduced in the following reactions.
        \ni) 4Na(s) + O2<\/sub>(g) \u279d 2Na2<\/sub>O(s) 4Na(s)
        \nAnswer:
        \nSodium is oxidized because it gets oxygen and forms sodium oxide.<\/p>\n

        ii) CuO(s) + H2<\/sub>(g) \u279d Cu(s) + H2<\/sub>O(l)
        \nAnswer:
        \nCopper oxide reduced to copper H2<\/sub> changes to water.<\/p>\n

        KSEEB SSLC Class 10 Science Chapter 1 Textbook Exercises<\/h3>\n

        KSEEB Solutions For Class 10 Science Pdf Download Question 1.<\/strong>
        \nWhich of the statements about the reaction below are incorrect?
        \n2PbO(s) + C(s) \u279d 2Pb(s) + CO2<\/sub>(g)
        \na) Lead is getting reduced.
        \nb) Carbon dioxide is getting oxidised.
        \nc) Carbon is getting oxidised.
        \nd) Lead oxide is getting reduced.
        \ni) (a) and (b)
        \nii) (a) and (c)
        \niii) (a), (b) and (c)
        \niv) all
        \nAnswer:
        \n(i) (a) and (b).
        \nLead is getting reduced. & Carbon dioxide is getting oxidised.<\/p>\n

        Chemical Reactions And Equations Class 10 KSEEB Solutions Question 2.<\/strong>
        \nFe2<\/sub>O3<\/sub> + 2Al \u279d Al2<\/sub>O3<\/sub> + 2Fe
        \nThe above reaction is an example of a
        \na) combination reaction
        \nb) double displacement reaction.
        \nc) decompoistion reaction.
        \nd) displacement reaction.
        \nAnswer:
        \n(d) The reaction is an example of a displacement reaction<\/b>.<\/p>\n

        KSEEB Solutions For 10 Science Question 3.<\/strong>
        \nWhat happens when dilute hydrochloric acid is added to iron fillings? Tick the correct answer.
        \na) Hydrogen gas and iron chloride are produced.
        \nb) Chlorine gas and iron hydroxide are produced.
        \nc) No reaction takes place.
        \nd) Iron salt and water are produced.
        \nAnswer:
        \n(a) Hydrogen gas and iron chloride are produced.
        \nFe(s) + 2HCl(aq) \u279d FeCl2<\/sub>(aq) + H2<\/sub>l<\/p>\n

        KSEEB Science Solutions For Class 10 Question 4.<\/strong>
        \nWhat is a balanced chemical equation? Why should chemical eqations be balanced?
        \nAnswer:
        \nThe total mass of the elements present in the products of a chemical reaction has to be equal to the total mass of the elements present in the reactants. In other words, the number of atoms of each element remains the same, before and after a chemical reaction. This is called Balancing equation. We must balance the chemical equation, otherwise it becomes skeletal chemical equation.<\/p>\n

        KSEEB Solutions Science Class 10 Question 5.<\/strong>
        \nTranslate the following statements into chemical equations and then balance them.
        \n(a) Hydrogen gas combines with nitrogen to form ammonia.
        \n(b) Hydrogen sulphide gas burns in air to give water and sulphur dioxide.
        \n(c) Barium chloride reacts with aluminium sulphate to give aluminium chloride and a precipitate of barium sulphate.
        \n(d) Potassium metal reacts with water to give potassium hydroxide and hydrogen gas.
        \nAnswer;
        \n(a) 3H2<\/sub>(g) + N2<\/sub>(g) \u2192 2NH3<\/sub>(g).
        \n(b) 2H2<\/sub>S(g) + 3O2<\/sub>(g) \u2192 2H2<\/sub>O(l) + 2SO2<\/sub>(g).
        \n(c) 3BaCl2<\/sub>(aq) + Al2<\/sub>(SO4<\/sub>)3<\/sub>(aq) \u2192 2AlCl3<\/sub>(aq) + 3BaSO4<\/sub>(s).
        \n(d) 2K(s) + 2H2<\/sub>O(l) \u2192 2KOH(aq) + H2<\/sub>(g).<\/p>\n

        KSEEB Class 10 Science Solutions Question 6.<\/strong>
        \nBalance the following chemical equations.
        \na) HNO3<\/sub> + Ca(OH)2<\/sub> \u279d Ca(NO3<\/sub>)2<\/sub> + H2<\/sub>O
        \nb) NaOH + H2<\/sub>SO4<\/sub> \u279d Na2<\/sub>SO4<\/sub> + H2<\/sub>O
        \nc) NaCl + AgNO3<\/sub> \u279d AgCl + NaNO3<\/sub>
        \nd) BaCl2<\/sub> + H2<\/sub>SO4<\/sub> \u279d BaSO4<\/sub> + HCl
        \nAnswer:
        \na) 2HNO3<\/sub> + Ca(OH)2<\/sub> \u279d Ca(NO3<\/sub>)2<\/sub> + 2H2<\/sub>O
        \nb) 2NaOH + H2<\/sub>SO4<\/sub> \u279d Na2<\/sub>SO4<\/sub> + 2H2<\/sub>O
        \nc) NaCl + AgNO3<\/sub> \u279d AgCl + NaNO3<\/sub>
        \nd) BaCl2<\/sub> + H2<\/sub>SO4<\/sub> \u279d BaSO4<\/sub> + 2HCl<\/p>\n

        10th Science Kannada Medium Question Answer Question 7.<\/strong>
        \nWrite the balanced chemical equations for the following reactions.
        \na) Calcium hydroxide + Carbon dioxide \u279d Calcium carbonate + Water
        \nb) Zinc + Silver nitrate \u279d Zinc nitrate + Silver
        \nc) Aluminium + Copper chloride \u279d Aluminium chloride + Copper
        \nd) Barium chloride + Potassium sulphate \u279d Barium sulphate + Potassium chloride
        \nAnswer:
        \na) Ca(OH)2<\/sub> + CO2<\/sub> \u279d CaCO3<\/sub> + H2<\/sub>O
        \nb) Zn + 2AgNO3<\/sub> \u279d Zn(NO3<\/sub>)2<\/sub> + 2Ag
        \nc) 2Al + 3CuCl2<\/sub> \u279d AlCl3<\/sub> + 3Cu
        \nd) BaCl2<\/sub> + K2<\/sub>SO4<\/sub> \u279d BaSO4<\/sub> + KCl<\/p>\n

        10th Science KSEEB Solutions Question 8.<\/strong>
        \nWrite the balanced chemical equation for the following and identify the type of reaction in each case.
        \na) Potassium bromide(aq) + Barium iodide(aq) \u279d Potassium iodide (aq) + Barium bromide(s)
        \nb) Zinc carbonate(s) \u279d Zinc oxide(s) + Carbon dioxide(g)
        \nc) Hydrogen(g) + Chlorine(g) \u279d Hydrogen chloride(g)
        \nd) Magnesium(s) + Hydrocholoric acid(aq) \u279d Magnesium chloride(aq) + Hydrogen(g)
        \nAnswer:
        \na) 2KBr(aq) + Bal2(aq) \u279d 2KI(aq) + BaBr2<\/sub>(s) \u279d double displacement reaction.
        \nb) ZnCO3<\/sub>(s) \u279d ZnO(s) + CO2<\/sub>(g) \u279d decompoistion reaction.
        \nc) H2<\/sub>(g) + Cl2<\/sub>(q) \u279d 2HCl(g) \u279d combination reaction
        \nd) Mg(s) + 2HCl(aq) \u2014> MgCl2<\/sub>(aq) + H2<\/sub>(g) \u279d displacement reaction.<\/p>\n

        KSEEB 10 Science Solutions Question 9.<\/strong>
        \nWhat does one mean by exothermic and endothermic reactions? Give examples.
        \nAnswer:<\/p>\n

          \n
        1. \u00a0Reactions in which heat is released along with the formation of products are called exothermic chemical reactions.
          \nEg: CH4<\/sub>(g)+2O2<\/sub>(g) \u279d CO2<\/sub>(g) + 2H2<\/sub>O(g)<\/li>\n
        2. \u00a0Reactions in which energy is absorbed are known as endothermic reactions.
          \n6CO2<\/sub> + 6H2<\/sub>O(l) \u279d C6<\/sub>H12<\/sub>O6<\/sub>(aq) + 6O2<\/sub>(g)<\/li>\n<\/ol>\n

          KSEEB Solutions 10th Science Question 10.<\/strong>
          \nWhy is respiration considered an exothermic reaction? Explain.
          \nAnswer:
          \nWe get from the food we eat. During digestion complex molecules of food are broken into simpler molecule such as glucose. This glucose combines with oxygen in the cells of our body and provides energy. Therefore respiration is considered an exothermic reaction.<\/p>\n

          10th Science Solutions KSEEB Question 11.<\/strong>
          \nWhy are decomposition reactions called the opposite of combination reactions? Write equations for these reactions.
          \nAnswer:
          \nDecomposition reactions involve breaking down of compounds to form two or more substances. These reactions require energy to proceed. Thus, they are the exact opposite of combination reactions in which two or more substances combine to give a new substance.<\/p>\n

          Examples:<\/p>\n

            \n
          1. ZnCO3<\/sub>(s) \u2192 ZnO(s) + CO2<\/sub>(g); Decomposition reaction.<\/li>\n
          2. H2<\/sub>(g) + Cl2<\/sub>(g) \u2192 2HCl(g); Combination reaction.<\/li>\n<\/ol>\n

            In the first equation, since ZnCO3<\/sub>\u00a0is broken down into ZnO and CO2<\/sub>\u00a0it is a decomposition reaction. In the second equation, H2<\/sub>\u00a0and Cl2<\/sub> combine to give a new substance HCl. Therefore, it is a combination reaction.<\/p>\n

            Science KSEEB Solutions For Class 10 Question 12.<\/strong>
            \nWrite one equation each for decomposition reactions where energy is supplied in the form of heat, light or electricity.
            \nAns:
            \na) Thermal decomposition
            \n\"KSEEB
            \nb) Decomposition by light
            \n\"KSEEB
            \nc) Decomposition by electricity
            \n\"KSEEB<\/p>\n

            10th Science Notes In Kannada Question 13.<\/strong>
            \nWhat is the difference between displacement and double displacement reactions Write equations for these reactions.
            \nAnswer:
            \nIn a displacement reaction, a more reactive element displaces a less reactive element from a compound.<\/p>\n

            A + BX \u2192 AX + B; where A is more reactive than B.
            \nIn a double displacement reaction, two atoms or a group of atoms switch places to form new compounds.
            \nAB + CD \u2192 AD + CB
            \nFor example:
            \nDisplacement reaction:
            \nCuSO4<\/sub>(aq) + Zn(s) \u2192 ZnSO4<\/sub>(aq) + Cu(s)<\/p>\n

            Double displacement reaction:
            \nNa2<\/sub>SO4<\/sub>(aq) + BaCl2<\/sub>\u00a0(aq) \u2192 BaSO4<\/sub>(s) + 2NaCl(aq)<\/p>\n

            KSEEB Solutions For Science Class 10 Question 14.<\/strong>
            \nIn the refining of silver, the recovery of silver from silver nitrate solution involved displacement by copper metal. Write down the reactions involved.
            \nAnswer:
            \n\"KSEEB<\/p>\n

            Science Notes For Class 10 State Syllabus Question 15.<\/strong>
            \nWhat do you mean by a precipitation reaction? Explain by giving examples.
            \nAnswer:
            \nAny reaction that produces a precipitate can be called a precipitation reaction.
            \nEg:
            \n\"KSEEB
            \nIn this reaction Barium chloride obtained as precipitate.
            \nThe white precipatate of BaSO4<\/sub> is formed by the reaction of SO4<\/sub>2-<\/sup> and Ba2+<\/sup>. The other product is formed is Sodium Chloride which remains in the solution.<\/p>\n

            Question 16.
            \nExplain the following in terms of gain or loss of oxygen with two examples each.
            \na) Oxidation (Gain of Oxygen)
            \nAnswer:
            \n\"KSEEB
            \nIn equation (i) From H2<\/sub>, H2<\/sub>O is oxidised. In eqn (ii) From Cu, CuO is oxidised
            \nb) Reduction is loss of Oxygen:
            \n\"KSEEB
            \nIn eqn (i) CO2<\/sub> is reduced to CO. in eqn (ii) CuO is reduced to Cu.<\/p>\n

            Question 17.
            \nA shiny brown coloured element \u2018X\u2019 on heating in air becomes black in colour. Name the element \u2018X\u2019 and the black coloured compound formed.
            \nAnswer:
            \n\u2018X\u2019 means copper (Cu) and black coloured compound copper oxide
            \n\"KSEEB<\/p>\n

            Question 18.
            \nWhy do we apply paint on iron articles?
            \nAnswer:
            \nIron articles are painted to prevent them from rusting. When painted, the contact of iron articles with atmospheric moisture and the air is cut off. Hence, rusting is prevented.<\/p>\n

            Question 19.
            \nOil and fat containing food items are flushed with nitrogen. Why?
            \nAnswer:<\/p>\n

            Oil and fat containing food items are flushed with nitrogen to prevent the items from getting oxidised which may result in rancidity of such products. When fats and oils are oxidised, they become rancid and their smell and taste change. Nitrogen provides an inert atmosphere for them.<\/p>\n

            Question 20.
            \nExplain the following terms with one example each.
            \na) Corrosion
            \nb) Rancidity
            \nAnswer:<\/p>\n

            (a) Corrosion:
            \nWhen a metal is attacked by substances around it such as moisture, acids etc. it gets corroded and the process is called corrosion. For example, rusting of iron products.<\/p>\n

            (b) Rancidity:
            \nThe Process in which fats and oils or food products made from fats or oils get oxidised resulting in a change of smell and the taste is called rancidity. For example, food items made from oil like chips becomes rancid if kept open for some time.<\/p>\n

            To prevent rancidity antioxidants (which prevent oxidation) are added to food containing fats and oils. Rancidity can also be prevented by flushing out oxygen with a gas like nitrogen. For example packets of food items like chips are flushed with nitrogen so that those can be used even after long duration.<\/p>\n

            KSEEB SSLC Class 10 Science Chapter 1 Additional Questions and Answers<\/h3>\n

            Question 1.
            \nHow do you determine whether a chemical reaction has taken place?
            \nAnswer:
            \nFollowing observations helps us to determine whether a chemical reaction has taken place<\/p>\n

              \n
            1. \u00a0Change in state<\/li>\n
            2. \u00a0Change in colour<\/li>\n
            3. \u00a0evolution of a gas<\/li>\n
            4. \u00a0Change in temperature.<\/li>\n<\/ol>\n

              Question 2.
              \nWrite the Balanced equation for the reaction of iron with steam.
              \nAnswer:
              \n3Fe(s) + 4H2<\/sub>O(g) \u279d Fe3<\/sub>O4<\/sub>(s) + 4H2<\/sub>(g)<\/p>\n

              Question 3.
              \nWhat is quicklime? Write one use of quicklime.
              \nAnswer:
              \nCalcium oxide is called lime or quicklime. It is used in the manufacture of cement.<\/p>\n

              Question 4.
              \nWhat are antioxidants?
              \nAnswer:
              \nThe substances which prevent oxidation are called antioxidants.<\/p>\n

              We hope the given KSEEB SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations will help you. If you have any query regarding Karnataka SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"

              KSEEB SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations are part of KSEEB SSLC Class 10 Science Solutions. Here we have given Karnataka SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations. Karnataka SSLC Class 10 Science Solutions Chapter 1 Chemical Reactions and Equations KSEEB SSLC Class 10 Science Chapter …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/27"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=27"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/27\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=27"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=27"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=27"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}