{"id":25440,"date":"2020-03-09T16:07:01","date_gmt":"2020-03-09T10:37:01","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=25440"},"modified":"2021-07-02T15:21:16","modified_gmt":"2021-07-02T09:51:16","slug":"kseeb-solutions-for-class-10-maths-chapter-3-additional-questions","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-10-maths-chapter-3-additional-questions\/","title":{"rendered":"KSEEB Solutions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Additional Questions"},"content":{"rendered":"

Students can Download Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Additional Questions Questions, Notes Pdf, KSEEB Solutions for Class 10 Maths<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your in examinations<\/p>\n

Karnataka State Syllabus Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Additional Questions<\/h2>\n

I. Multiple Choice Questions:<\/span><\/p>\n

Question 1.
\nWhich of the following is not a linear equation
\n(a) x + 3y = 8
\n(b) x = 2y
\n(c) x2<\/sup> + 5x + 8 = 0
\n(d) y = 0.
\nAnswer:
\n(c) x2<\/sup> + 5x + 8 = 0<\/p>\n

Question 2.
\nx = 1 and y = 3 is a solution of a linear equation.
\n(a) x – y = 4
\n(b) x + y = 4
\n(c) 2x + y = 8
\n(d) 2y + x = 9
\nAnswer:
\n(b) x + y = 4<\/p>\n

Question 3.
\nThe pair of co-ordinates satisfying 2x + y = 6 is
\n(a) (2, 2)
\n(b) (2, 3)
\n(c) (4, 1)
\n(d) (5, 1)
\nAnswer:
\n(a) (2, 2)<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nThe pair of equations x = 0 and y = 0 represents.
\n(a) Parallel lines
\n(b) Coincident lines
\n(c) non-intersecting lines
\n(d) Perpendicular intersecting lines
\nAnswer:
\n(d) Perpendicular intersecting lines<\/p>\n

Question 5.
\nIf the ten\u2019s and unit\u2019s digits of a two digit number are y and x respectively, then the number will be.
\n(a) 10y + x
\n(b) 10x + y
\n(c) 10xy
\n(d) y + x
\nAnswer:
\n(a) 10y + x<\/p>\n

Question 6.
\nIf the line y = px – 2 passes through the point (2, 2), then the value of P is
\n(a) 3
\n(b) 2
\n(c) 5
\n(d) 4
\nAnswer:
\n(b) 2<\/p>\n

Question 7.
\nThe coordinates of the origin are.
\n(a) (0, 1)
\n(b) (1, 0)
\n(c) (2, 2)
\n(d) (0, 0)
\nAnswer:
\n(d) (0, 0)<\/p>\n

Question 8.
\nThe point (-3, -4) lies in the Quadrant.
\n(a) I
\n(b) II
\n(c) III
\n(d) IV
\nAnswer:
\n(c) III<\/p>\n

Question 9.
\nThe point of intersection of the lines x – 2 – 0 and y + 6 = 0 is
\n(a) (0, 0)
\n(b) (0, -6)
\n(c) (0, 2)
\n(d) (2, -6)
\nAnswer:
\n(d) (2, -6)<\/p>\n

\"KSEEB<\/p>\n

Question 10.
\nThe pair of equations x = 4 and y = 3 graphically represents lines which are
\n(a) Parallel
\n(b) intersecting at (3, 4)
\n(c) Coincident
\n(d) intersecting at (4, 3)
\nAnswer:
\n(d) intersecting at (4, 3)<\/p>\n

Question 11.
\nTwo lines are given to be parallel the equation of one of the lines is 4x + 3y = 14. The equation of the second line can be.
\n(a) 3x + 4y =14
\n(b) 8x + 6y = 28
\n(c) – 12x = 9y
\n(d) 12x + 9y = 42
\nAnswer:
\n(c) – 12x = 9y<\/p>\n

Question 12.
\nThe pair of equations x + y = 0 and x + y = – 7 has
\n(a) one solution
\n(b) no solution
\n(c) two solutions
\n(d) infinitely many solutions
\nAnswer:
\n(b) no solution<\/p>\n

Question 13.
\nThe pair of linear equations 3x + 5y = 3 and 6x + Ky = 8 does not have a solution if.
\n(a) K = 5
\n(b) K \u2260 10
\n(c) K = 10
\n(d) K \u2260 5.
\nAnswer:
\n(c) K = 10<\/p>\n

Question 14.
\nIf y = 2x – 3 and y = 5 then the value of x is.
\n(a) 1
\n(b) 2
\n(c) 3
\n(d) 4
\nAnswer:
\n(d) 4<\/p>\n

\"KSEEB<\/p>\n

Question 15.
\nThe sum of two numbers is 8 and their difference is 2. Find the numbers.
\n(a) 5 and 3
\n(b) 6 and 4
\n(c) 4 and 2
\n(d) 4 and 4
\nAnswer:
\n(a) 5 and 3<\/p>\n

Question 16.
\nThe larger of two supplementary angles exceeds the smaller by 18 degrees. Find them.
\n(a) 98\u00b0, 82\u00b0
\n(b) 99\u00b0, 81\u00b0
\n(c) 118, 100\u00b0
\n(d) 80\u00b0, 100\u00b0
\nAnswer:
\n(b) 99\u00b0, 81\u00b0<\/p>\n

Question 17.
\nThe value of a so that the point (3, a) lies on the line represented by 2x – 3y = 5 is
\n(a) 1\/3
\n(b) – 1\/3
\n(c) 1
\n(d) 2\/3
\nAnswer:
\n(b) – 1\/3<\/p>\n

Question 18.
\nIf the pair of linear equations a1<\/sub> x + b, y + c, = 0 and a2<\/sup>x + b2<\/sup>y + c2<\/sup> = 0 has a unique solution, then.
\n\"KSEEB
\nAnswer:
\n\"KSEEB<\/p>\n

Question 19.
\nThe solution of the pair of equations x – y = 0, 2x – y = 0 is
\n(a) x = 3, y = 5
\n(b) x = 3, y = 2
\n(c) x = 2, y = 2
\n(d) x = 5, y = 5
\nAnswer:
\n(c) x = 2, y = 2<\/p>\n

\"KSEEB<\/p>\n

Question 20.
\nThe value of x if y = 1\/2x and 3x + 4y = 20 is
\n(a) 3
\n(b) 5
\n(c) 6
\n(d) 4
\nAnswer:
\n(d) 4<\/p>\n

II. Very Short Answer Questions:<\/span><\/p>\n

Question 1.
\nFind the coordinate where the line x – y = 8 will intersect the y-axis.
\nAnswer:
\nThe given line will intersect y-axis when x = 0 \u2234 0 – y = 8
\ny = – 8<\/p>\n

Question 2.
\nIf the lines given by 3x + 2ky = 2 and 2x + 5y + 1 = 0 are parallel, then find value of k.
\nAnswer:
\nSince given lines are parallel
\n\"KSEEB<\/p>\n

Question 3.
\nWrite the number of solutions of the following pair of linear equations.
\nAnswer:
\n\"KSEEB
\n\u2234 The given pair of linear equations has infinitely many solutions.<\/p>\n

Question 4.
\nFor all real values of c, the pair of equations x – 2y = 8, 5x + 10y = c have a unique solution. Justify true (or) false.
\nAnswer:
\n\"KSEEB
\n\u2234 Given pair of equations have unique solution.
\n\u2234 Given statement is true.<\/p>\n

\"KSEEB<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Additional Questions Questions, Notes Pdf, KSEEB Solutions for Class 10 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your in examinations Karnataka State Syllabus Class 10 Maths Chapter 3 Pair of Linear …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/25440"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=25440"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/25440\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=25440"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=25440"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=25440"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}