\nA matchbox measures 4 cm \u00d7 2.5 cm \u00d7 1.5 cm. What will be the volume of a packet containing 12 such boxes ?
\nSolution:
\nMatch box is in the form of cuboid.
\nIts length, l = 4 cm.
\nbreadth, b = 2.5 cm.
\nheight, h = 1.5 cm.
\n\u2234 Volume of Cuboid, V = l \u00d7 b \u00d7 h
\n= 4 \u00d7 2.5 \u00d7 1.5
\nV = 15 cm3<\/sup>.
\nVolume of 1 match box is 15 cm3<\/sup>.
\nVolume of 12 match boxes …?… .
\n= 15 \u00d7 12
\n= 180 cm3<\/sup>.<\/p>\n
Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Karnataka Board Class 9 Maths Chapter 13 Surface Area and Volumes Ex 13.5 Question 1. A matchbox measures 4 cm \u00d7 2.5 cm \u00d7 1.5 cm. What will be the volume of a packet containing 12 such boxes ? Solution: Match box is in the form of cuboid. Its length, l = 4 cm. breadth, …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/2533"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=2533"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/2533\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=2533"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=2533"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=2533"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nA cuboidal water tank is 6 m long, 5 m wide and 4.5 m deep. How many litres of water can it hold ? (1 m3<\/sup> = 1000 l)
\nSolution:
\nLength of cuboidal water tank, l = 6 m
\nbreadth b = 5 m
\nheight, h =4.5 m
\n\u2234 Volume of cuboidal water tank, V= l \u00d7 b \u00d7 h
\n= 6 \u00d7 5 \u00d7 4.5
\nV= 135 m3<\/sup>.
\n1 m3<\/sup> = 1000 l.
\n135 m3<\/sup> = ? = 135 \u00d7 1000
\n= 135000 lit.
\n\u2234 Number of litres of water tank = 1350000 litres.<\/p>\n
\nA cuboidal vessel is 10 m long and 8 m wide. How high must it be made to hold 380 cubic metres of a liquid ?
\nSolution:
\nVolume of cuboidal vessel, V = 380 m3<\/sup>.
\nlength, l = 10 m
\nbreadth, b = 8 m height, h = ?
\nVolume of vessel, V= l \u00d7 b \u00d7 h
\n380 = 10 \u00d7 8 \u00d7 h
\n380 = 80 h
\n![\"KSEEB](\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/05\/KSEEB-Solutions-for-Class-9-Maths-Chapter-13-Surface-Area-and-Volumes-Ex-13.5-Q-3.png\")
\n\u2234 h = 4.75 m.<\/p>\n
\nFind the cost of digging a cuboidal pit 8 m long, 6 m broad and 3 m deep at the rate of Rs. 30 per m3.
\nSolution:
\nLength of cuboidal pit, l = 8 m
\nbreadth, b = 6 m height, h = 3 m
\n\u2234 Volume of pit, V = l \u00d7 b \u00d7 h
\n= 8 \u00d7 6 \u00d7 3
\n= 144 m3<\/sup>.
\n\u2234 Cost of digging a cuboidal 1 m3<\/sup> is Rs. 30
\nCost of digging a cuboidal pit for 144 m3<\/sup> … ? …
\n= 144 \u00d7 30
\n= Rs. 4320.<\/p>\n
\nThe capacity of a cuboidal tank is 50000 litres of water. Find the breadth of the tank, if its length and depth are respectively 2.5 m and 10 m.
\nSolution:
\nVolume of cuboidal tank, V = 50000 lit.
\n1 c.c = 1000 litres
\n\u2234 Volume of tank = \\(\\frac{50000}{1000}\\) = 50 c.c
\nlength of tank, l = 2.5 m
\nheight, h = 10m
\nbreadth,b = ?
\nVolume of cuboid, V = l \u00d7 b \u00d7 h
\n![\"KSEEB](\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/05\/KSEEB-Solutions-for-Class-9-Maths-Chapter-13-Surface-Area-and-Volumes-Ex-13.5-Q-5.png\")
\n\u2234 b = 2m.<\/p>\n
\nA village, having a population of 4000, requires 150 litres of water per head per day. It has a tank measuring 20m \u00d7 15m \u00d7 6m. For how many days will the water of this tank last ?
\nSolution:
\nLength of cuboid water tank, l = 20 m
\nbreadth, b = 15 m
\nheight, h = 6 m
\nVolume, V = ?
\nVolume of water tank, V = l \u00d7 b \u00d7 h
\n= 20 \u00d7 15 \u00d7 6
\n= 1800 m3<\/sup>.
\n1m3<\/sup> = 1000 litres
\n\u2234 1800m3<\/sup> = 1800 x 1000
\n= 1800000 litres.
\nWater required daily per man= 150 litres
\n\u2234 Quantity of water required for 4000 men?
\n= 4000 \u00d7 150
\n= 600000 litres.
\nQuantity of water for 1 day = 600000
\nNumber of days for consuming 1800000 litres … ? …
\n![\"KSEEB](\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/05\/KSEEB-Solutions-for-Class-9-Maths-Chapter-13-Surface-Area-and-Volumes-Ex-13.5-Q-6.png\")
\n= 3 Days.<\/p>\n
\nA godown measures 40 m \u00d7 25 m \u00d7 15 m. Find the maximum number of wooden crates each measuring 1.5 m \u00d7 1.25 m \u00d7 0.5 m that can be stored in the godown
\nSolution:
\nLength of rectangular godown, l1<\/sub> = 40 m
\nbreadth, b1<\/sub> = 25 m
\nheight, h1<\/sub> = 10 m
\n\u2234 Volume of godown, V= l1<\/sub> \u00d7 b1<\/sub> \u00d7 h1<\/sub>
\n= 40 \u00d7 25 \u00d7 10
\n= 10000 m3<\/sup>.
\nLength of wooden crate, l2<\/sub> = 1.5 m
\nbreadth, b2<\/sub> = 1.25 m
\nheight, h2<\/sub> = 0.5 m
\n\u2234 Volume of wooden crate. V = l2<\/sub> \u00d7 b2<\/sub> x h2<\/sub>
\n= 1.5 \u00d7 1.25 \u00d7 0.5
\n= 0.9375 m3<\/sup>.
\nFor 0.9375 m3<\/sup>, 1 crate
\n![\"KSEEB](\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/05\/KSEEB-Solutions-for-Class-9-Maths-Chapter-13-Surface-Area-and-Volumes-Ex-13.5-Q-7.png\")
\n= 10666.66<\/p>\n
\nA solid cube of side 12 cm is cut into eight cubes of equal volume. What will be the side of the new cube? Also, find the ratio between their surface areas.
\nSolution:
\nEach side of a cube, a = 12 cm.
\n\u2234 Volume of cube, V = a3<\/sup>
\n= (12)3<\/sup>
\n= 1728 cm3<\/sup>.
\nSolid cube is cut into 8 cubes of equal volume.
\nVolume of each small cube,
\n![\"KSEEB](\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/05\/KSEEB-Solutions-for-Class-9-Maths-Chapter-13-Surface-Area-and-Volumes-Ex-13.5-Q-8.png\")
\n\u2234 l3<\/sup> = 216
\n\u2234 l = 6 cm.
\n\u2234 Each side of small cube is 6 cm.
\nRatio of outer area :
\n![\"KSEEB](\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/05\/KSEEB-Solutions-for-Class-9-Maths-Chapter-13-Surface-Area-and-Volumes-Ex-13.5-Q-8.1.png\")
<\/p>\n
\nA river 3 m deep and 40 m wide is flowing at the rate of 2 km per hour. How much water will fall into the sea in a minute?
\nSolution:
\nDepth of river, h = 3m
\nbreadth, b = 40 m
\n1 Km. = 1000 m
\n\u2234 2 Km. = 2000 m.
\nSpeed of the river per hour is 2 Km.
\nFor 60 minutes, 2000m
\nFor 1 minute …?… = \\(\\frac{2000}{60}\\)
\n![\"KSEEB](\"https:\/\/kseebsolutions.guru\/wp-content\/uploads\/2019\/05\/KSEEB-Solutions-for-Class-9-Maths-Chapter-13-Surface-Area-and-Volumes-Ex-13.5-Q-9.png\")
\n\u2234 Depth of river in 1 minute, l = \\(\\frac{100}{3}\\) m.
\nVolume of water flows in 1 minute,
\nV = l \u00d7 b \u00d7 h
\n= \\(\\frac{100}{3}\\) \u00d7 40 \u00d7 3
\n= 4000 m3<\/sup>
\n\u2234 In One minute, 4000 m3<\/sup> water reaches the sea.<\/p>\nKSEEB Solutions for Class 9 Maths<\/a><\/h5>\n","protected":false},"excerpt":{"rendered":"