{"id":24997,"date":"2020-03-03T17:36:21","date_gmt":"2020-03-03T12:06:21","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=24997"},"modified":"2021-07-02T15:21:21","modified_gmt":"2021-07-02T09:51:21","slug":"kseeb-solutions-for-class-10-maths-chapter-14-additional-questions","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-10-maths-chapter-14-additional-questions\/","title":{"rendered":"KSEEB Solutions for Class 10 Maths Chapter 14 Probability Additional Questions"},"content":{"rendered":"

Students can Download Class 10 Maths Chapter 14 Probability Additional Questions, Notes Pdf, KSEEB Solutions for Class 10 Maths<\/a>\u00a0helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 10 Maths Chapter 14 Probability Additional Questions<\/h2>\n

I. Multiple Choice Questions:<\/span><\/p>\n

Question 1.
\nHow many faces does a coin has
\na. 1
\nb. 2
\nc. 3
\nd. 4
\nAnswer:
\nb. 2<\/p>\n

\"KSEEB<\/p>\n

Question 2.
\nHow many faces does a die have
\na. 1
\nb. 2
\nc. 6
\nd. 4
\nAnswer:
\nc. 6<\/p>\n

Question 3.
\nWhat is the probability of getting a head on throwing an coin.
\na. 0
\nb. \\(\\frac{1}{3}\\)
\nc. \\(\\frac{1}{2}\\)
\nd. 1
\nAnswer:
\nc. \\(\\frac{1}{2}\\)<\/p>\n

Question 4.
\nWhich of the following cannot be the probability of an event.
\na. \\(\\frac{1}{2}\\)
\nb. 10%
\nc. 0.7
\nd. \\(\\frac{3}{2}\\)
\nAnswer:
\nb. 10%<\/p>\n

Question 5.
\nTwo coins are tossed simultaneously the probability of getting a head on only one of the two coins.
\na. \\(\\frac{1}{2}\\)
\nb. \\(\\frac{2}{3}\\)
\nc. \\(\\frac{1}{4}\\)
\nd. \\(\\frac{3}{4}\\)
\nAnswer:
\na. \\(\\frac{1}{2}\\)<\/p>\n

Question 6.
\nA die is thrown once the probability of getting an even prime number
\na. \\(\\frac{1}{2}\\)
\nb. \\(\\frac{1}{3}\\)
\nc. \\(\\frac{1}{6}\\)
\nd. \\(\\frac{1}{4}\\)
\nAnswer:
\nc. \\(\\frac{1}{6}\\)<\/p>\n

\"KSEEB<\/p>\n

Question 7.
\nA die is thrown once the probability of getting a number less than 3.
\na. \\(\\frac{1}{2}\\)
\nb. \\(\\frac{1}{3}\\)
\nc. \\(\\frac{1}{6}\\)
\nd. \\(\\frac{5}{6}\\)
\nAnswer:
\nb. \\(\\frac{1}{3}\\)<\/p>\n

Question 8.
\nTwo coins are tossed simultaneously. What is the number of all possible out comes
\na. 6
\nb. 2
\nc. 8
\nd. 4
\nAnswer:
\nd. 4<\/p>\n

Question 9.
\nThe probability of getting a perfect square number from the numbers 1 to 10 is.
\na. \\(\\frac{3}{10}\\)
\nb. \\(\\frac{1}{2}\\)
\nc. \\(\\frac{2}{5}\\)
\nd. \\(\\frac{1}{5}\\)
\nAnswer:
\na. \\(\\frac{3}{10}\\)<\/p>\n

Question 10.
\nThe probability of getting a rotten eggs in a lot of 400 eggs is 0.035 the number of rotten eggs in the lot is
\na. 7
\nb. 14
\nc. 21
\nd. 28
\nAnswer:
\nb. 14<\/p>\n

Question 11.
\nA die is thrown once the probability of getting a number 3 or 4 is
\na. \\(\\frac{1}{3}\\)
\nb. \\(\\frac{2}{3}\\)
\nc. 0
\nd. 1
\nAnswer:
\na. \\(\\frac{1}{3}\\)<\/p>\n

\"KSEEB<\/p>\n

Question 12.
\nIn a throw of a pair of dice, the probability of getting a doublet is
\na. \\(\\frac{1}{2}\\)
\nb. \\(\\frac{1}{3}\\)
\nc. \\(\\frac{1}{6}\\)
\nd. \\(\\frac{5}{12}\\)
\nAnswer:
\nc. \\(\\frac{1}{6}\\)<\/p>\n

Question 13.
\nA card is drawn from a well shuffled deck of playing cards. The probability of drawing a red face card is
\na. \\(\\frac{1}{26}\\)
\nb. \\(\\frac{3}{26}\\)
\nc. \\(\\frac{4}{26}\\)
\nd. \\(\\frac{1}{13}\\)
\nAnswer:
\nb. \\(\\frac{3}{26}\\)<\/p>\n

Question 14.
\nThe probability of getting 53 Sundays in a leap year is
\na. \\(\\frac{1}{7}\\)
\nb. \\(\\frac{2}{7}\\)
\nc. \\(\\frac{4}{7}\\)
\nd. \\(\\frac{5}{7}\\)
\nAnswer:
\nb. \\(\\frac{2}{7}\\)<\/p>\n

Question 15.
\nA letter of english alphabet is chosen at random. The probability that the letter is a consonant is
\na. \\(\\frac{5}{26}\\)
\nb. \\(\\frac{20}{26}\\)
\nc. \\(\\frac{21}{26}\\)
\nd. \\(\\frac{1}{26}\\)
\nAnswer:
\nc. \\(\\frac{21}{26}\\)<\/p>\n

Question 16.
\nA coin is tossed 1000 times and 560 times a “head” occurs the probability of occurence of a head in this case is
\na. 0.5
\nb. 0.56
\nc. 0.44
\nd. 0.056
\nAnswer:
\nb. 0.56<\/p>\n

Question 17.
\nA die is thrown once the probability of getting a even number
\na. \\(\\frac{2}{3}\\)
\nb. \\(\\frac{1}{2}\\)
\nc. \\(\\frac{2}{6}\\)
\nd. \\(\\frac{1}{2}\\)
\nAnswer:
\nd. \\(\\frac{1}{2}\\)<\/p>\n

\"KSEEB<\/p>\n

Question 18.
\nProbability of an a impossible event is
\na. 0
\nb. 1
\nc. \\(\\frac{1}{2}\\)
\nd. \\(\\frac{3}{2}\\)
\nAnswer:
\na. 0<\/p>\n

II. Short Answer Questions:<\/span><\/p>\n

Question 1.
\nWrite the probability of sure event (or) certain event
\nAnswer:
\n1 (one).<\/p>\n

Question 2.
\nWrite the probability of an impossible event.
\nAnswer:
\nzero (0).<\/p>\n

Question 3.
\nWrite the sum of the probabilities of all the elementary events of an experiment.
\nAnswer:
\none (1).<\/p>\n

Question 4.
\nDefine elementary event.
\nAnswer:
\nAn event having only one out comes of the experiment.<\/p>\n

Question 5.
\nProbability of an event lies between
\nAnswer:
\n0 and 1<\/p>\n

Question 6.
\nWrite the formula for calculating the probability of occurence of an event.
\nAnswer:
\n\"KSEEB<\/p>\n

\"KSEEB<\/p>\n

Question 7.
\nFrom a well shuffled pack of cards, a card is drawn at random. Find the probabilities of getting a black queen.
\nAnswer:
\nn(S) = 52, number of black queens = 2
\n\u2234 n(A) = 2
\n\"KSEEB<\/p>\n

Question 8.
\nIf P(E) = 0.05, what is the probability of ‘notE’
\nAnswer:
\nP(E) = 0.05, P(\\(\\overline{\\mathrm{E}}\\)) = ?
\nP(E) + P(not E) = 1
\nP(not E) = 1 – P(E) = 1 – 0.05 = 0.95<\/p>\n

Question 9.
\nWhat is the probability of getting no head when two coins are tossed simultaneously?
\nAnswer:
\nn(S) = {HH, TT, HT, TH} n(S) = 4 and n(A) = 1
\n\"KSEEB<\/p>\n

Question 10.
\nSomeone is asked to choose a number from 1 to 100. What is the probability of it being a prime number.
\nAnswer:
\nn(S) = 100, total prime number between 0 and 100 = 25 n(A) = 25
\n\"KSEEB<\/p>\n

Question 11.
\nA card is drawn at random from a well shuffled pack of 52 playing cards. Find the probability of getting neither a red card nor a queen.
\nAnswer:
\nn(S) = 52, Number of red cards and queen = 28
\nNumber of favourable out comes = 52 – 28 = 24
\nP (getting neither red card nor a queen)
\n= \\(\\frac{24}{56}=\\frac{6}{13}\\)<\/p>\n

\"KSEEB<\/p>\n

Question 12.
\n20 tickets on Which numbers 1 to 20 are written, are mixed throughly and then a ticket is drawn at random out of them. Find the probability that number on the drawn ticket is a multiple of 3 or 7.
\nAnswer:
\nn(S) = 20 multiple of 3 or 7 = {3, 6, 9, 12, 15, 18, 7, 14} n(A) = 8
\nP(ticket multiple 3 or 7)
\n\"KSEEB<\/p>\n

III. Long Answer Questions:<\/span><\/p>\n

Question 1.
\nA bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball from the bag is twice that of a red ball. Find the number of blue balls in the bag.
\nAnswer:
\nNumber of red balls = 6 and Let the number blue balls = x
\nTotal number of balls = x + 6
\n\"KSEEB
\nHence, number of blue balls is 12.<\/p>\n

Question 2.
\nThere are 30 boys and 25 girls in a class. A student is chosen at random. Find the probability that the chosen student is a
\n(i) boy
\n(ii) girl
\nAnswer:
\nTotal number of students = 30 + 25 = 55
\nn(S) = 55
\n(i) Let A be the event of choosing a boy, n(A) = 30
\n\"KSEEB<\/p>\n

(ii) Let B be the event of choosing a girl n(B) = 25
\n\"KSEEB<\/p>\n

Question 3.
\nA random experiment has only three pairs of mutually exclusive events among A, B and C. If P(A) = \\(\\frac{3}{2}\\) P(B) and P(C) = \\(\\frac{1}{2}\\) P(A) Find P(B).
\nAnswer:
\n\"KSEEB<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nIf A is an event of a random experiment such that P(A) : P(\\(\\overline{\\mathbf{A}}\\)) = 5 : 11, then find
\n(i) P(A) and P(\\(\\overline{\\mathbf{A}}\\))
\nAnswer:
\n\"KSEEB
\n11P(A) = 5 – 5 P(A)
\n11P(A) + 5 P(A) = 5
\n16P(A) = 5
\n\"KSEEB<\/p>\n

Question 5.
\nNine rotten mangoes are mixed with 30 good ones. One mango is chosen at random. What is the probability of choosing a (i) good mango (ii) rotten mango.
\nAnswer:
\nTotal number of mangoes = n(S)
\n= 30 + 9. \u2234 n(S) = 39
\n(i) Let ‘A’ be the event of good mangoes. n(A) = 30
\n\"KSEEB<\/p>\n

(ii) Let ‘B’ be the event of rotten mangoes. n(B) = 9.
\n\"KSEEB<\/p>\n

Question 6.
\nThe probability of picking non – defective item from a sample is \\(\\frac{7}{12}\\) . Find the probability of picking a defective item.
\nAnswer:
\n\"KSEEB
\n\"KSEEB<\/p>\n

\"KSEEB<\/p>\n

Question 7.
\nThere are 2 red and 2 yellow flowers in a basket. A child picks up at random three flowers, what is the probability of picking up both the yellow flowers.
\nAnswer:
\nTotal number of flowers = 2 Red + 2 Yellow = 4
\n3 flowers from out 4 flowers drawn
\n\"KSEEB<\/p>\n

Question 8.
\nThree cards are drawn at random from a pack of 52 cards. What is the probability that all the three cards are kings.
\nAnswer:
\nThere are 52 cards, three cards are drawn,
\n\"KSEEB
\nLet A be the event when all 3 cards chosen are kings
\n\"KSEEB<\/p>\n

Question 9.
\nOne card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the card drawn is
\n(i) an ace
\n(ii) either red or king
\n(iii) a face card.
\nAnswer:
\nTotal cards n(S) = 52.
\n(i) There are four ace cards in pack
\nn(A) = 4
\n\"KSEEB<\/p>\n

(ii) There are 26 red cards in a pack and two black king n(B) = 26 + 2 = 28.
\n\"KSEEB<\/p>\n

(iii) In a pack of 52 cards: Kings, queen and jacks are called face cards.
\nn(C) = 12.
\n\"KSEEB<\/p>\n

\"KSEEB<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Class 10 Maths Chapter 14 Probability Additional Questions, Notes Pdf, KSEEB Solutions for Class 10 Maths\u00a0helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 10 Maths Chapter 14 Probability Additional Questions I. Multiple Choice Questions: Question 1. How many faces …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/24997"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=24997"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/24997\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=24997"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=24997"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=24997"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}