{"id":24975,"date":"2020-09-15T15:19:54","date_gmt":"2020-09-15T09:49:54","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=24975"},"modified":"2021-07-02T15:01:49","modified_gmt":"2021-07-02T09:31:49","slug":"kseeb-solutions-for-class-10-maths-chapter-14-ex-14-2","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-10-maths-chapter-14-ex-14-2\/","title":{"rendered":"KSEEB Solutions for Class 10 Maths Chapter 14 Probability Ex 14.2"},"content":{"rendered":"

Students can Download Class 10 Maths Chapter 14 Probability Ex 14.2 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 10 Maths<\/a>\u00a0helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 10 Maths Chapter 14 Probability Ex 14.2<\/h2>\n

Question 1.
\nTwo customers Shyam and Ekta are visiting a particular shop in the same week (Tuesday to Saturday). Each is equally likely to visit the shop on any day as on another day. What is the probability that both will visit the shop on
\n(i) the same day?
\n(ii) consecutive days?
\n(iii) different days?
\nAnswer:
\nNumber of all possible out comes
\n= 5 \u00d7 5 = 25
\nn(S) = 25
\n(i) Let E1<\/sub> be a event favourable to visit same day for shop [Tue, Tue; Wed, Wed; Th, Thu; Fri, Fri; Sat, Sat]
\nn(E1<\/sub>) = 5
\nProbability of event both visit shop same day
\n\"KSEEB<\/p>\n

(ii) Let E2<\/sub> be a event favourable to visit shop both on consecutive days
\nE2<\/sub> = {T, W; W, T; W, Th; Th, W; Th, F; F, Th; F, S; S, F} n(E2<\/sub>) = 8
\nProbability of a event favourable to visit both consecutive days
\n\"KSEEB<\/p>\n

(iii) Probability of both will visit shop different days = 1 – Probability both visit shop same day
\n\"KSEEB<\/p>\n

\"KSEEB<\/p>\n

Question 2.
\nA die is numbered in such a way that its faces show the numbers 1, 2, 2, 3, 3, 6. It is thrown two times and the total score in two throws is noted. Complete the following table which gives a few values of the total score on the two throws:
\n\"KSEEB
\nWhat is the probability that the total score is
\nAnswer:
\n(i) even?
\n(ii) 6?
\n(iii) at least 6?
\n\"KSEEB
\nTotal number of possible out comes
\n\u2234 n(S) = 36<\/p>\n

(i) Let E1<\/sub> be a event of sum is an even number.
\n\u2234 E1<\/sub> = [2, 4, 4, 4, 4, 8, 4, 4, 8, 4, 6, 6, 4, 6, 6, 8, 8, 12] \u2234 n(E1<\/sub>) = 18
\nProbability of sum is even number
\n\"KSEEB<\/p>\n

(ii) Let E2<\/sub> be a event of sum is equal to 6. \u2234 n (E2<\/sub>) = 4
\nProbability of sum is equal to 6
\n\"KSEEB<\/p>\n

(iii) Let E3<\/sub> be a event of sum of out comes favourable to score atleast 6.
\nn (E3<\/sub>) = 15
\nProbability of sum atleast 6
\n\"KSEEB<\/p>\n

Question 3.
\nA bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of a red ball, determine the number of blue balls in the bag.
\nAnswer:
\nLet the number of blue balls = x.
\n\u2234 total number of balls = 5 + x.
\nP (drawing red ball) = \\(\\frac{5}{x+5}\\)
\nP (drawing blue ball) = \\(\\frac{x}{x+5}\\)
\n\"KSEEB
\nx = 2 \u00d7 5
\nx = 10
\nHence the number of blue balls in a bag is 10.<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nA box contains 12 balls out of which x are black. If one ball is drawn at random from the box, what is the probability that it will be a black ball? If 6 more black balls are put in the box, the probability of drawing a black ball is now double of what it was before. Find x.
\nAnswer:
\nTotal number of balls in box =12
\n\u2234 n(S) = 12, number of out comes favourable to event drawing black ball = n(E) = x
\nProbability of drawing black ball
\n\"KSEEB
\nIf 6 more balls put in a box then total number of balls = n(S) = 6 + 12 = 18
\n\u2234 n(S)=18
\nNumber of out comes favourable to event drawing black ball = n (E) = x + 6
\nProbability of drawing black ball
\n\"KSEEB
\nAccording to Question from (1) and (2)
\n\"KSEEB
\n6x + 36 = 18x
\n36 = 18x – 6x
\n12x = 36
\nx = \\(\\frac{36}{12}\\) = 3
\nx = 3<\/p>\n

Question 5.
\nA jar contains 24 marbles, some are green and others are blue. If a marble is drawn at random from the jar, the probability that it is green is \\(\\frac{2}{3}\\) Find the number of blue balls in the jar.
\nAnswer:
\nTotal number of marbles in the jar = 24
\nLet the number of blue marbles is x and the number of green marbles is 24 – x
\nProbability of marble drawn is green
\n\"KSEEB
\n24 – x = 16
\nx = 24 – 16
\nx = 8
\n\u2234 Number of blue marble is 8.<\/p>\n

\"KSEEB<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Class 10 Maths Chapter 14 Probability Ex 14.2 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 10 Maths\u00a0helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 10 Maths Chapter 14 Probability Ex 14.2 Question 1. Two customers Shyam and …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/24975"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=24975"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/24975\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=24975"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=24975"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=24975"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}