{"id":22441,"date":"2020-02-04T17:25:52","date_gmt":"2020-02-04T11:55:52","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=22441"},"modified":"2021-07-02T15:25:49","modified_gmt":"2021-07-02T09:55:49","slug":"1st-puc-basic-maths-question-bank-chapter-7","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/1st-puc-basic-maths-question-bank-chapter-7\/","title":{"rendered":"1st PUC Basic Maths Question Bank Chapter 7 Linear Inequalities"},"content":{"rendered":"

Students can Download Basic Maths Chapter 7 Linear Inequalities Questions and Answers, Notes Pdf, 1st PUC Basic Maths Question Bank with Answers<\/a>\u00a0helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka 1st PUC Basic Maths Question Bank Chapter 7 Linear Inequalities<\/h2>\n

Question 1.
\nSolve graphically 3x + 4y \u2264 60, x + 3y \u2264 30, x \u2265 0, y \u2265 0
\nAnswer:
\n3x + 4y = 60
\n\"1st<\/p>\n

x + 3y + 30
\n\"1st<\/p>\n

(0, 0) satisfies 3x + 4y \u2264 60 and x + 3 \u2264 30
\n\"1st<\/p>\n

Question 2.
\nSolve 2 (2x + 3) – 10 \u00a3 6(x – 2)
\nAnswer:
\nGiven 2 (2x + 3) – 10 \u00a3 6(x – 2)
\n\u21d2 4x + 6 – 10 \u2264 6x – 12 \u21d2 4x – 4 \u2264 6x – 12
\n\u21d2 4x – 6x \u2264 – 12 + 4 \u21d2 -2x \u2264 -8
\n\u21d2 x \u2265 \\(\\frac{8}{2}\\) \u21d2 x \u2208 [4, \u221e] is the solution
\n\"1st<\/p>\n

\"1st<\/p>\n

Question 3.
\nSolve the equation \\(\\left|\\frac{2}{x-4}\\right|>1\\),\u00a0 x \u2260 4.
\nAnswer:
\nwe have \\(\\left|\\frac{2}{x-4}\\right|>1\\),\u00a0 x \u2260 4
\n\u21d2 \\(\\frac{2}{|x-4|}>1\\) \u21d2 2 > |x – 4|
\n\u21d2 4 – 2 < x < 4 + 2
\n\u21d2 2 < x < 6. \u2234 x e (2, 6) But x 4<\/p>\n

Question 4.
\nFind all pairs of consecutive even positive integers both of which are larger than 8, such that their sum is less than 25.
\nAnswer:
\nLet x be the smaller of the two consecutive even positive integers, then the other even integer is x + 2.
\nGiven x > 8 and x + (x + 2) < 25.
\n\u21d2 x > 8, and 2x + 2 < 25.
\n\u21d2 x > 8, 2x < 23 \u21d2 x > 8, x < \\(\\frac{23}{2}\\)
\n\u21d2 8 < x < \u21d2 \\(\\frac{23}{2}\\) x = 10,
\n\u2234 the required parity even integers is (10, 12)<\/p>\n

Question 5.
\nIn the first four papers each of 100 marks, Ravi got 95, 72, 73, 83 marks. If he wants an average of greater than or equal to 75 marks and less than 80 marks, find the range of marks he should score in the fifth paper.
\nAnswer:
\nLet score be x in the fifth paper, then
\n\"1st
\nHence Ravi must score between 52 and 77 marks.<\/p>\n

\"1st<\/p>\n

Solve and represent the following in equalities graphically\u00a0<\/span><\/p>\n

Question 1.
\nx + y \u2265 4 : 2x – y > 0
\nAnswer:
\n\"1st<\/p>\n

Question 2.
\nx + y \u2264 9, y > x, x \u2265 0
\nAnswer:
\n\"1st<\/p>\n

\"1st<\/p>\n

Question 3.
\n2x – y > 1, x – 2y < – 1
\nAnswer:
\n\"1st<\/p>\n

Question 4.
\n5x + 4y \u2264 20, x \u2265 1, y \u2265 2
\nAnswer:
\n\"1st<\/p>\n

\"1st<\/p>\n

Question 5.
\n2x + y \u2265 4, x + y \u2264 3, 2x – y \u2264 6.
\nAnswer:
\n\"1st<\/p>\n

Question 6.
\nx – 2y \u2264 3, 3x + 4y \u2265 12, x \u2265 0, y \u2265 1
\nAnswer:
\n\"1st<\/p>\n

\"1st<\/p>\n

Question 7.
\n4x + 3y \u2264 60, y \u2265 2x, x \u2265 3, y \u2265 0
\nAnswer:
\n\"1st<\/p>\n

Question 8.
\nx + 2y \u2264 10, x + y \u2265 1, x – y \u2264 0, x \u2265 0, y \u2265 0
\nAnswer:
\n\"1st<\/p>\n

\"1st<\/p>\n

Question 9.
\nSolve the in equalities and represent the solutions graphically on number line.
\n\"1st
\nAnswer:
\n5(2x – 7) -3 (2x + 3) \u2264 0; 2x + 19 \u2264 6x + 47<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Basic Maths Chapter 7 Linear Inequalities Questions and Answers, Notes Pdf, 1st PUC Basic Maths Question Bank with Answers\u00a0helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka 1st PUC Basic Maths Question Bank Chapter 7 Linear Inequalities Question 1. Solve graphically 3x + …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[81],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/22441"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=22441"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/22441\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=22441"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=22441"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=22441"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}