{"id":22290,"date":"2020-02-04T09:33:42","date_gmt":"2020-02-04T04:03:42","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=22290"},"modified":"2021-07-02T15:25:52","modified_gmt":"2021-07-02T09:55:52","slug":"1st-puc-basic-maths-question-bank-chapter-4","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/1st-puc-basic-maths-question-bank-chapter-4\/","title":{"rendered":"1st PUC Basic Maths Question Bank Chapter 4 Logarithms"},"content":{"rendered":"

Students can Download Basic Maths Chapter 4 Logarithms Questions and Answers, Notes Pdf, 1st PUC Basic Maths Question Bank with Answers<\/a>\u00a0helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka 1st PUC Basic Maths Question Bank Chapter 4 Logarithms<\/h2>\n

Logarithms<\/p>\n

Question 1.
\n\\(\\log _{5} \\frac{\\sqrt[4]{25}}{625}\\)
\nAnswer:
\n\"1st<\/p>\n

Question 2.
\nFind x if logx<\/sup>0.4<\/sub> = -3
\nAnswer:
\n\"1st<\/p>\n

\"1st<\/p>\n

Question 3.
\nIf x = 27, b = log4<\/sup>3<\/sub> then flow that xb<\/sup> = 64
\nAnswer:
\nxb<\/sup> = 27log4<\/sup>3<\/sub>
\n= 33log4<\/sup>3<\/sub><\/sup> = 3log(4)3<\/sup>3<\/sub><\/sup>
\n= 3log64<\/sup>3<\/sub> = 64<\/sup><\/p>\n

Question 4.
\nIf log10<\/sub>\\(\\sqrt{1+x}+3\\) log10<\/sub> \\(\\sqrt{1-x}\\) = log10<\/sub> \\(\\sqrt{1-x^{2}}+2\\) . Find x.
\nAnswer:
\nlog10<\/sub> (x + 1)1\/2<\/sup> + log10<\/sub>(1 – x)3\/2<\/sup> = log10<\/sub>(1 – x2<\/sup>)1\/2<\/sup> + log100<\/sup>10<\/sub>
\n\u21d2 (x + 1)1\/2<\/sup> (1 – x)3\/2<\/sup> = (1 – x2<\/sup>)1\/2<\/sup> – 100
\n\u21d2 \\(\\sqrt{1-x^{2}}\\) (1 – x – 100) = 0
\n\u21d2 x = \u00b11. x = -99 But x \u2260 \u00b1 1, -99
\n\u2234 There is no value of x exists.<\/p>\n

Question 5.
\nIf x = loga<\/sup>2a<\/sub>, y = log2a<\/sup>3a<\/sub>, z = log3a<\/sup>4a<\/sub>. Show that xyz + 1 = 2yz.
\nAnswer:
\n\"1st
\n= 2log2a<\/sup>3a <\/sub>. log3a<\/sup>4a<\/sub> = 2yz = RHS<\/p>\n

\"1st<\/p>\n

Question 6.
\nIf a, b, c are GP. Prove that logn<\/sup>a<\/sub> logn<\/sup>6<\/sub> logn<\/sup>c<\/sub> are in HP.
\nAnswer:
\nGiven, a, b, c are in GP = b2<\/sup> = ac
\nTaking log on both sides
\n2 log 6 = log a + log c
\n\u21d2 loga<\/sup>n<\/sub> logb<\/sup>n<\/sub> logc<\/sup>n<\/sub> are inn AP
\n\u21d2 loga<\/sup>n<\/sub> logb<\/sup>n<\/sub> logc<\/sup>n<\/sub> are in HP.<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Basic Maths Chapter 4 Logarithms Questions and Answers, Notes Pdf, 1st PUC Basic Maths Question Bank with Answers\u00a0helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka 1st PUC Basic Maths Question Bank Chapter 4 Logarithms Logarithms Question 1. Answer: Question 2. Find x …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[81],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/22290"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=22290"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/22290\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=22290"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=22290"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=22290"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}