{"id":2157,"date":"2020-09-08T09:54:24","date_gmt":"2020-09-08T04:24:24","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=2157"},"modified":"2021-07-02T15:03:44","modified_gmt":"2021-07-02T09:33:44","slug":"kseeb-solutions-class-9-maths-chapter-10-ex-10-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-class-9-maths-chapter-10-ex-10-1\/","title":{"rendered":"KSEEB Solutions for Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1"},"content":{"rendered":"

KSEEB Solutions for Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1<\/strong>\u00a0are part of KSEEB Solutions for Class 9 Maths<\/a>. Here we have given Karnataka Board Class 9 Maths Chapter 10 Linear Equations in Two Variables Exercise 10.1.<\/p>\n

Karnataka Board Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1<\/h2>\n

Question 1.
\nThe cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement. (Take the cost of a notebook to be Rs. x and that of a pen to be Rs. y).
\nSolution:
\nLet the cost of pen b Rs. x
\nIf the cost of the Notebook is Rs. y.
\nCost of 1 notebook is twice the cost of a pen.
\n\u2234 y = 2x
\n-2x + y = 0
\nIf this is written in the form of
\nax + by + c = 0 it is
\n-2x + y + 0 = 0
\nHere, a = -2, b = 1, c = 0.<\/p>\n

Question 2.
\nExpress the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
\ni) 2x + 3y = \\(9 . \\overline{35}\\)
\nii) x – \\(\\frac{y}{5}\\) – 10 = 0
\niii) -2x + 3y = 6
\niv) x = 3y
\nv) 2x = -5y
\nvi) 3x + 2 = 0
\nvii) y – 2 = 0
\nviii) 5 = 2x
\nSolution:
\ni) 2x + 3y = \\(9 . \\overline{35}\\)
\nOR 2x + 3y – \\(9 . \\overline{35}\\) = 0
\nIf we compare this to ax + by + c = 0,
\nHere, a = 2, b = 3, c = \\(9 . \\overline{35}\\).<\/p>\n

ii) x – \\(\\frac{y}{5}\\) – 10 = 0
\nIf we compare this to ax + by + c = 0,
\nHere, a = 1, b = \\(\\frac{-1}{5}\\) , c=10.<\/p>\n

iii) -2x + 3y = 6
\nOR -2x + 3y – 6 = 0
\nIf we compare this to ax + by + c = 0,
\nHere, a = -2, b = 3, c = -6.<\/p>\n

iv) x = 3y
\nx – 3y = 0
\nx – 3y + 0 = 0
\nIf we compare this to ax + by + c = 0,
\nHere, a = 1, b = -3, c = 0.<\/p>\n

v) 2x = -5y
\n2x + 5y = 0
\n2x + 5y + 0 = 0
\nIf we compare this to ax + by + c = 0,
\nHere, a = 2, b = 5, c = 0.<\/p>\n

vi) 3x + 2 = 0
\n3x + 0y + 2 = 0
\nIf we compare this to ax + by + c = 0,
\nHere, a = 3, b = 0, c = 2.<\/p>\n

vii) y – 2 = 0
\n0x + 1y – 2 = 0
\nIf we compare this to ax + by + c = 0,
\nHere, a = 0, b = 1, c = -2.<\/p>\n

viii) 5 = 2x
\n-2x + 5 = 0
\n-2x + 0y + 5 = 0
\nIf we compare this to ax + by + c = 0,
\nHere, a = -2, b = 0, c = 5.<\/p>\n

We hope the KSEEB Solutions for Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1 help you. If you have any query regarding Karnataka Board Class 9 Maths Chapter 10 Linear Equations in Two Variables Exercise 10.1, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"

KSEEB Solutions for Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1\u00a0are part of KSEEB Solutions for Class 9 Maths. Here we have given Karnataka Board Class 9 Maths Chapter 10 Linear Equations in Two Variables Exercise 10.1. Karnataka Board Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1 …<\/p>\n","protected":false},"author":6,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/2157"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/6"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=2157"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/2157\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=2157"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=2157"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=2157"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}