{"id":2065,"date":"2020-09-08T07:13:26","date_gmt":"2020-09-08T01:43:26","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=2065"},"modified":"2021-07-02T15:03:44","modified_gmt":"2021-07-02T09:33:44","slug":"kseeb-solutions-class-9-maths-chapter-8-ex-8-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-class-9-maths-chapter-8-ex-8-1\/","title":{"rendered":"KSEEB Solutions for Class 9 Maths Chapter 8 Heron\u2019s Formula Ex 8.1"},"content":{"rendered":"

KSEEB Solutions for Class 9 Maths Chapter 8 Heron\u2019s Formula Ex 8.1<\/strong>\u00a0are part of KSEEB Solutions for Class 9 Maths<\/a>. Here we have given Karnataka Board Class 9 Maths Chapter 8 Heron\u2019s Formula Exercise 8.1.<\/p>\n

Karnataka Board Class 9 Maths Chapter 8 Heron\u2019s Formula Ex 8.1<\/h2>\n

Question 1.
\nA traffic signal board, indicating \u2018SCHOOL AHEAD\u2019, is an equilateral triangle with side ‘a’. Find the area of the signal board, using Heron’s formula. If its perimeter is 180 cm, what will be the area of the signal board ?
\nSolution:
\nLet each side of the signal board be ‘a’ unit.
\n\"KSEEB
\nIts\u2019 perimeter,
\nAB + BC + CA = 180 cm
\nArea = ?
\nPerimeter of \u2206ABC
\na + a + a = 180
\n\u2234 3a = 180
\n\u2234 a = \\(\\frac{180}{3}\\)
\n\u2234 a = 60 cm
\na = b = c = 60 cm
\n\\(s=\\frac{a+b+c}{2}=\\frac{180}{2}=90\\)
\nArea of \u2206ABC A,
\n\"KSEEB<\/p>\n

Question 2.
\nThe triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m. The advertisements yield an earning of Rs. 5000 per m2<\/sup> per year. A company hired one of its walls for 3 months. How much rent did it pay?
\n\"KSEEB
\nSolution:
\nSides of triangle, a = 122m, b = 22m, c = 120m.
\n\"KSEEB
\nRent for each year, each sq.m. = Rs. 5,000
\nRent for each month, each sq.m. = \\(\\frac{5000}{12}\\)
\nRent for each quarterly, each sq.m. = 3 \u00d7 \\(\\frac{5000}{12}\\)
\n= Rs. 1250
\n\u2234 Rent for 1320 sq.m.= 1250 \u00d7 1320 = Rs. 1650000
\n\u2234 Amount company has to pay is Rs. 1650000.<\/p>\n

Question 3.
\nThere is a slide in a park. One of its side walls has been painted in some colour with a message \u201cKEEP THE PARK GREEN AND CLEAN”. If the sides of the wall are 15m, 11m and 6 m, find,the area painted in colour.
\n\"KSEEB
\nSolution:
\nSides, a = 15 m, b = 11 m, c = 6 m.
\n\"KSEEB<\/p>\n

Question 4.
\nFind the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 cm.
\nSolution:
\nThree sides of triangle be
\nLet a = 18 cm, b = 10 cm, c = x cm.
\nPerimeter = 42 cm.
\na + b + c = 42
\n18 + 10 + x = 42
\n28 + x = 42
\n\u2234 x = 42 – 28
\n\u2234 x = 14 cm
\n\u2234 c = 14 cm
\n\"KSEEB<\/p>\n

Question 5.
\nSides of a triangle are in the ratio of 12: 17: 25 and its perimeter is 540 cm. Find its area.
\nSolution:
\nLet sides of triangle be
\na = 12x, b = 17x and c = 25x
\n\u2234 Perimeter = 12x + 17x + 25x = 540
\n54x = 540
\n\u2234 x = \\(\\frac{540}{54}\\)
\n\u2234 x = 10 cm.
\n\u2234 a = 12x = 12 \u00d7 10 = 120 cm.
\nb = 17x = 17 \u00d7 10 = 170 cm.
\nc = 25x = 25 \u00d7 10 = 250 cm.
\n\"KSEEB<\/p>\n

Question 6.
\nAn isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.
\nSolution:
\nLet the sides of isosceles triangle be a and b.
\n\u2234 a = b = 12 cm.
\nLet the third side be ‘c’.
\n\u2234 Perimeter = a + b + c = 30
\n= 12 + 12 + c = 30
\n24 + c = 30
\nc = 30 – 24
\nc = 6 cm.
\n\"KSEEB<\/p>\n

We hope the KSEEB Solutions for Class 9 Maths Chapter 8 Heron\u2019s Formula Ex 8.1 help you. If you have any query regarding Karnataka Board Class 9 Maths Chapter 8 Heron\u2019s Formula Exercise 8.1, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"

KSEEB Solutions for Class 9 Maths Chapter 8 Heron\u2019s Formula Ex 8.1\u00a0are part of KSEEB Solutions for Class 9 Maths. Here we have given Karnataka Board Class 9 Maths Chapter 8 Heron\u2019s Formula Exercise 8.1. Karnataka Board Class 9 Maths Chapter 8 Heron\u2019s Formula Ex 8.1 Question 1. A traffic signal board, indicating \u2018SCHOOL AHEAD\u2019, …<\/p>\n","protected":false},"author":6,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/2065"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/6"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=2065"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/2065\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=2065"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=2065"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=2065"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}