{"id":20501,"date":"2020-01-21T15:16:38","date_gmt":"2020-01-21T09:46:38","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=20501"},"modified":"2021-07-02T15:28:08","modified_gmt":"2021-07-02T09:58:08","slug":"2nd-puc-basic-maths-question-bank-chapter-10-ex-10-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/2nd-puc-basic-maths-question-bank-chapter-10-ex-10-1\/","title":{"rendered":"2nd PUC Basic Maths Question Bank Chapter 10 Learning Curve Ex 10.1"},"content":{"rendered":"

Students can Download Basic Maths Exercise 10.1 Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka 2nd PUC Basic Maths Question Bank Chapter 10 Learning Curve Ex 10.1<\/h2>\n

Part – A<\/span><\/p>\n

2nd PUC Basic Maths Learning Curve Ex 10.1 One Mark Questions with Answers\u00a0<\/strong><\/p>\n

Question 1
\nDefine learning curve.
\nAnswer:
\nLearning curve is defined as curvilinear relation between the decrease in average labour hours’ per unit with the increase in the total output.<\/p>\n

Question 2.
\nWrite what does it deals.
\nAnswer:
\nThe theory of learning curve deals with labour efficiency.<\/p>\n

Question 3.
\nWrite the learning curve ratio.
\nAnswer:
\n8th<\/sup> line LCR = Curve ratio<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nWrite the formula for learning index.
\nAnswer:
\n\"2nd<\/p>\n

Question 5.
\nWrite the learning curve equation.
\nAnswer:
\nY = axb<\/sup><\/p>\n

Question 6.
\nFind the index of learning for 70% learning effect?
\nAnswer:
\n\"2nd<\/p>\n

Question 7.
\nFind the index of learning for 80% learning effect?
\nAnswer:
\n\"2nd<\/p>\n

Question 8.
\nWhat do you mean by 80% learning effect?
\nAnswer:
\n80% learning effect means that when the cumulative output is doubled the cumulative average labour hours per unit will be 80% of the previous level.<\/p>\n

Question 9.
\nCalculate the index of learning for 90% L effect.
\nAnswer:
\n\"2nd<\/p>\n

Question 10.
\nThe average labour cost of 1st<\/sup>150 units of production by a factory is \u20b9 100, when the output was doubled
\nto 300 units, the ave labour cost was \u20b9 50. Find the L.C.R & the learning curve percent.
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Part – B<\/span><\/p>\n

2nd PUC Basic Maths Learning Curve Ex 10.1 Five Marks Questions with Answers\u00a0<\/strong><\/p>\n

Question 1.
\nAn engineering company has 80% learning effect and spends 1000 hours to produce 1 lot of the product. Estimate the labour cost of producing 8 lots of the product if the labour cost is \u20b9 40 per hour.
\nAnswer:
\n\"2nd
\nTotal time for lots = 4096 hours
\nTotal labour cost at \u20b9 40 per hour = 4096 \u00d7 40 = \u20b9 163840.<\/p>\n

Question 2.
\nABC company required 1000 hours to produce first 30 engines. If the learning effect is 90% find the total labour cost at 20 per hour to produce total of \u20b9 20 engines?
\nAnswer:
\nLet 30 Engines = 1 unit
\n\u2234 120 engines = units Units
\n\"2nd
\n\u2234 Total time required for 120 engines = 3240 hrs.
\nTotal labour cost at \u20b9 20 per hour = 3240 \u00d7 20 = \u20b9 648000<\/p>\n

Question 3.
\nThe production manager of a company obtained the following equation for the learning effect. Y = 1400 X-0.3<\/sup> This function is based on the company’s experience for assembling the first 50 units of the product. The company was asked to bid a new order of 100 additional units and the labour cost for producing an additional 100 units at the rate of \u20b9 20 per hour.
\nAnswer:
\nGiven a = 1400, 1 lot = 50 units = 2 lots = 100 units
\n\u2234 x = 2, y = 1400(2) -0.3<\/sup>
\nTaking logarithm both sides we get
\nLog Y = log(1400) – 0.3 log(2) = 3.1461 -0.3 \u00d7 0.3010
\nLog y = 3.1461 \u2013 0.0903 = 3.0558
\n\u2234 y = A . L (3.0558) = 1137.0 hrs per lot
\nTotal time required for 2 lots = 1137 \u00d7 2 = 2274.
\nLabour cost at for \u20b9 20 per hour = 2274 \u00d7 20 = \u20b9 45480.<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nAn aircraft manufacturer supplies aircraft engines to different airlines. They have just completed an initial order for 30 engines involving a total of 6000 direct labour hours at \u20b9 20 per hour. They have been asked to bid for a prospective contract for a supply of 90 engines. It is expected that there will be 80% learning effect. Estimate the labour cost for the new order.
\nAnswer:
\nLet 30 engines = 1 unit, 120 engines = 4 units.
\n\"2nd
\n\u2234 Total hours for 90 engines = Total hours for 120 engines – Total hours for 30 engines = 15360 – 6000 = 9360.
\nThe total labour cost for 90 engines at 20 per hour = 9360 \u00d7 20 = 1,87,000<\/p>\n

Question 5.
\nA first sample batch of 50 units of product A took 80 hours to make. The company now wishes to estimate | the average time per unit will be if the total output of product A is 200 units and 80% learning rate
\napplies. Answer: Let 50 units = 1 lot \u21d2 200 units = 4lots
\n\"2nd
\n\u2234 Total hours for 200 units (4 lots) = 204.8 hours and average time per 4 lots
\n= 51.2 hours<\/p>\n

Some Important Questions from Previous Question Papers<\/p>\n

Part – C<\/span><\/p>\n

2nd PUC Basic Maths Learning Curve Ex 10.1 Five Marks Questions with Answers\u00a0<\/strong><\/p>\n

Question 1.
\nThe time required to produce the first unit of a product is 1000 hours. If the manufacturers experiences 80% learning effect calculate the average time pr unit & the time taken to produce altogether 8 units. Also find the total labour charges for the production of 8 units at the rate of \u20b9 12.50 per hour.
\nAnswer:
\nI. Table method
\n\"2nd
\nTotal time to produce 8 units = 4096 hrs.
\nGiven labour charges for 1 hour = \u20b9 12.50
\n\u2234Labour charges for 4096 hours = 4096 x 12.50 = \u20b9 51,200<\/p>\n

II. Formula Method:
\nGiven a = 1000, x = 8 units
\n\"2nd
\ny = axb<\/sup>
\nlog y = loga + b log x = log1000 + (-0.3219) log 8
\n= 3.000 – 0.3219 x 0.9031 = 3.000 – 0.2907
\nlog y = 2.7093
\ny = AL (2.7093) = 512 hrs. per unit
\n\u2234 Total time for 8 units = 512 x 8 = 4,096 hrs.
\nLabour charges per hour = \u20b9 12.50.
\n\u2234 Labour charges for 4,096 hrs. = 4,096 x 12.50 = 51,200<\/p>\n

Question 2.
\nAn engineering company has won the contract for supplying aircraft engines of a new type. The prototype constructed to win the contract took 500 hours. It is expected that these will have 90% learning effect. Estimate the labour cost of producing 8 engines of new orders. If the labour cost is \u20b9 40 per hour.
\nAnswer:
\nTable Method
\n\"2nd
\nTotal time to produce 8 units = 2916
\nGiven labour charges per hour = \u20b9 40
\n:: Labour charges for 2916 hrs. = 2916 ~ 40 = \u20b9 1,16,640
\nFormula Method
\nGiven a = 500 hrs. x = 8,
\n\"2nd
\ny = axb<\/sup>
\nlog y = log a + b log x
\n= log 500 \u2013 0.1521 log 8
\n= 2.6990 – 0.1521 x 0.9031
\n= 2.6990 – 0.1374
\ny = AL (2.5616)
\n= 364.43
\n\u2234 Ave time \/unit = 364.43
\nTotal time to produce 8 units = 364.43 \u00d7 8 = 2915.452 = 2916
\nGiven labour charges 1hr. = \u20b9 40
\n\u2234Labour charges for 2916 hrs. = 2916 \u00d7 40 = 1,16,640.<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\nThe manager of a company obtained the following equation for the learning effect Y= 1450 X-0.2512<\/sup>. The function is based for assembling the first 50 units of the product find the total labour hours required to assemble 100 units.
\nAnswer:
\nGiven the total time for producing a lot of 50 units of a product.
\n\u2234 100 units would constitute 2 lots of 50 units. Each :: 1 = 1450, x = 2, b = -0.2512.
\ny = axb<\/sup>
\nlog y = log a + b log x
\n= log 1450 \u2013 0.2512 log2
\n= 3.1614 – 0.2512 \u00d7 0.3010 = 3.0858
\ny = A.L (3.0858) = 1216 hrs. per lot
\n\u2234 Total time required for 2 lots = 2 \u00d7 1216 = 2432 hrs.<\/p>\n

Question 4.
\nA manager of a company obtained the following equation for the learning effect y= 200 x-0.3219<\/sup>. The first unit of product requires 200 labour hours. If the company is planning to assemble 100 units of the product find the total labour hours required.
\nAnswer:
\nGiven y = 200 x X-0.3219<\/sup> Where x = 100 units
\nY = 200 \u00d7 x-0.3219<\/sup>
\nWhere x = 100 units
\ny = 200 \u00d7 (100)-0.3219<\/sup>
\nlog y = log 200 – 0.3219 log 100
\n= 2.3010 – 0.3219 \u00d7 2.0
\n= 2.3010 – 0.6438 = 1.6572
\ny = A.L (1.6572) = 45.41 per unit
\n\u2234 Total labour hours for 100 units = 45.41 \u00d7 100 = 4541 hours<\/p>\n

Question 5.
\nThe production manager of an electronic company obtained the following equation for the learning effect y = 1356 x -0.3219<\/sup>. The function is based on the company experience for assembling the first 50 units of the product. The company was asked to bid a new order of 100 additional units. Find the labour hours
\nrequired to assemble 100 units.
\nAnswer:
\nGiven y = 1356 x-0.3219<\/sup>
\nLet 50 units = 1 lot
\ny = 1356(2)-0.3219<\/sup>
\n\u2234 100 units = 2 lots = x
\nlog y = log 1356 -0.3219 log 2
\n= 3.1322 – 0.3219 (0.3010) = 3.1322 – 0.0969 = 3.0353.
\ny = A.L (3.0353) = 1085.00 hours \/lot
\n\u2234 The total no. of labour hours required to assemble 2 lots (100 units) = 1085 2
\n= 2170 hours.<\/p>\n

Question 6.
\nAn aircraft manufacturer supplies aircraft engines to different Airlines. They have just completed an
\ninitial trial order for 30 engines involving a total of 6000 direct labour hours at \u20b9 20 per hour. They have been asked to bid prospective contract for supply of 90 engines. It is expected that these will be 80% learning effect. Estimate the labour cost for the new order.
\nAnswer:
\nGiven
\na = 6000 hrs., 1 lot = 30 engines, x = 120 engines = 4 lots
\nTable method
\n\"2nd
\nTotal time taken to produce 120 engines = 15360
\nTime taken to produce 30 engines = 6000
\nTotal time taken to produce 90 engines = 15360 – 6000 = 9360
\nLabour cost at \u20b9 20 per hour = 9360 \u00d7 20 = 1,87,200
\nFormula Method
\na = 6000 hours, x = 4,
\n\"2nd
\ny = axb<\/sup>
\nlog y = log a + b log x
\n= log 6000 \u2013 0.3219 x log 4
\n= 3.7782 – 0.3219 \u00d7 0.6021 = 3.7782 – 0.1938 = 3.5844
\ny = A.L (3.5844) = 3841
\nTotal number of hours required to produce 4 lots (120 engines) = 3841 \u00d7 4 = 15364 hours.
\n\u2234 Total number of hours required to produce 90 engines = 15364 – 6000 = 9364 hrs.
\nLabour cost at \u20b9 20 per hour = 20 \u00d7 9364 = \u20b9 1,87,280<\/p>\n

\"KSEEB<\/p>\n

Question 7.
\nA company requires 253.5 hours to produce the 1st<\/sup> 30 units. If the learning effect is 80% Find the number of hours required to produce an additional number of 120 units. Also find the total labour cost at \u20b9 20\/hr.
\nAnswer:
\n1 lot = 30 units
\n120 units = 4 lots
\n\"2nd
\nTotal time required for 120 units = 648.96 hrs.
\nAdditional time taken for 30 units = 253.5 hrs.
\n\u2234 Total time required to complete 150 units = 648.96 +253.5 = 902.46
\n\u2234 Total labour cost at 20\u20b9 \/hour = 902.46 \u00d7 20 = 18049.2<\/p>\n

Question 8.
\nA company requires 2134.2 hours to produce the first 40 machines. If the learning effect is 80%. Find the number of hours required to produce next 120 machines.
\nAnswer:
\nLet 40 units = 1 lot
\n120 units = 3 lots
\n\"2nd
\nTotal time required for 4 lots (160 machines) = 5463.55
\n\u2234 Total time for 3 lots (120 machines) = 5463.55 – 2134.20 = 3329.35<\/p>\n

Question 9.
\nThe first unit of a product took 80 hours to manufacture. If the workers show 80% learning effect find the
\ntotal time taken to produce 6th, 7th & 8th units.
\nAnswer:
\n\"2nd
\nTotal time taken to produce 5 units = Time taken to produce
\n= 4 units + 1 unit = 204.8 + 80 = 284.8
\n\u2234 The total time taken to produce 6th, 7th & gth units.
\n= Time taken to produce 8 units – Time taken to produces 5 units
\n= 327.68 – 284.8 = 42.88.<\/p>\n

Question 10.
\nA company requires 100 hrs. to produce the fst ten units at 15\/per hour. If the learning effect is 80%. Find the total number of hours required to produce 160 units & also the total cost to produce 160 units.
\nAnswer:
\nGiven
\na = 100 hrs. 10 units = 1 lot
\n\u2234 160 units = 16 lots
\n\"2nd
\ny = axb<\/sup>
\nlog y = log a + b log x
\n= log 100 \u2013 0.3219 log 16
\n= 2 – 0.3219 1.2041 = 2 – 0.3875 = 1.625
\ny = A(1.6125) = 40.98 hours\/unit
\n\u2234 Total time required for 160 units or 16 lots = 40.98 16 = 655.68 hrs.
\n\u2234 Total cost to produce 16 units at \u20b9 15\/hr. = 655.68 \u00d7 15 = \u20b9 9835.20
\nTable method
\n\"2nd
\nTotal time for 16 lots = 655.36 hrs.
\n\u2234 Total cost to produce 16 lots at \u20b9 15\/hr. = 655.36 \u00d7 15 = \u20b9 19830.4.<\/p>\n

\"KSEEB<\/p>\n

Question 11.
\nABC company Ltd., has observed that a 90% learning effect applies to all labour related costs whenever a new product is taken up for production. The anticipated production is 320 units for the coming year. The production is done in lots of 10 units each & each lot requires 1000 labour hours at \u20b916 per hour. You are required to compute the total labour hours & labour costs to manufacture 320 units.
\nAnswer:
\n10 units = 1lot 320 units = 32 lots
\n\"2nd
\nTotal labour hours for 32 lots = 18,895.9 hours
\nLabour cost at 16\u20b9 per hour = 18,895.9 \u00d7 16 = \u20b9 3,02,334.<\/p>\n

Question 12.
\nA company requires 200 hrs. to produce the first ten units at \u20b9 10 per hour. If the learning effect is expected is 90%. Find the total no. of hours required to produce 320 units & also the total cost to produce 320 units.
\nAnswer:
\n10 units = 1 lot
\n320 units = 32 lots
\n\"2nd
\nTotal number of hours to produce 320 units = 3778.88
\n\u2234 Total cost at \u20b9 10 per hour = 37762.88 \u00d7 10 = 37788.8<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Basic Maths Exercise 10.1 Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka 2nd PUC Basic Maths Question Bank Chapter 10 Learning Curve Ex 10.1 Part – A 2nd PUC …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[82],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/20501"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=20501"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/20501\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=20501"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=20501"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=20501"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}