{"id":20451,"date":"2020-01-21T12:54:25","date_gmt":"2020-01-21T07:24:25","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=20451"},"modified":"2021-07-02T15:28:10","modified_gmt":"2021-07-02T09:58:10","slug":"2nd-puc-basic-maths-question-bank-chapter-9-ex-9-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/2nd-puc-basic-maths-question-bank-chapter-9-ex-9-1\/","title":{"rendered":"2nd PUC Basic Maths Question Bank Chapter 9 Stocks and Shares Ex 9.1"},"content":{"rendered":"

Students can Download Basic Maths Exercise 9.1 Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka 2nd PUC Basic Maths Question Bank Chapter 9 Stocks and Shares Ex 9.1<\/h2>\n

Part – A<\/span><\/p>\n

2nd PUC Basic Maths Stocks and Shares Ex 9.1 One Mark Questions with Answers ( 1 \u00d7 \u00a010 = 10 )<\/strong><\/p>\n

Question 1.
\nFind the income obtained by investing 3600 in 5% stock at 90.
\nAnswer:
\n\"2nd<\/p>\n

Question 2.
\nHow much stock at \u20b9 75 can be bought for \u20b9 3375.
\nAnswer:
\nAmount 75 – Stock 100
\nAmount 3375 \u2192 \\(\\frac{3,375 \\times 100}{75}\\) = 4,500
\n\u2234 Stock = \u20b9 4,500<\/p>\n

Question 3.
\n6% stock is being sold at 15 discount. How much money is required to buy \u20b9 6000 stock.
\nAnswer:
\nAmount 85 – Stock 100
\nAmount? Stock 6,000
\n\u2234 Amount = \\(\\frac{6,000 \\times 85}{100}\\) = 5,100<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nDefine yield.
\nAnswer:
\nYield is defined as nominal interest divided by Amount invested<\/p>\n

Question 5.
\nWhat is the yield obtained when \u20b9 5000, 3% stock is purchased at 125.
\nAnswer:
\n\"2nd<\/p>\n

Question 6.
\nWhat income can be obtained from an investment of \u20b9 10,725 in 6.5% stock at 143. What is the amount of stock purchased?
\nAnswer:
\n\"2nd<\/p>\n

Question 7.
\n10% stock is quoted at \u20b9 120. Find the rate of interest.
\n[Hint: here rate of interest means yield]
\nAnswer:
\nHere rate of interest means yield]
\nInterest = \\(=\\frac{D}{A}\\) X 100
\n= \\(=\\frac{10}{120}\\) x 100 = 8.33%<\/p>\n

\"KSEEB<\/p>\n

Question 8.
\nHow much of 8% stock at 96 can be purchased for \u20b9 4800? Also find the income obtained?
\nAnswer:
\nIncome = \\(=\\frac{D}{A}\\) X Cash
\nIncome = \\(=\\frac{8}{96}\\) X 4800
\nIncome = \u20b9 400<\/p>\n

Question 9.
\nHow much money will a man get by selling \u20b9 6000 at 5% stock at 20 premium?
\nAnswer:
\nStock 100 \u2013 Amount 120
\nStock 6000 – ?
\nAmount = \\(\\frac{6,000 \\times 120}{100}\\) = \u20b9 7,200<\/p>\n

Question 10.
\nAbhi purchased 850 shares of a company the nominal value being 10 each. Company declared an annual
\ndividend of 12%. How much dividend did abhi receive?
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Part – B<\/span><\/p>\n

2nd PUC Basic Maths Stocks and Shares Ex 9.1 Three or Four Marks Questions with Answers<\/strong><\/p>\n

Question 1.
\nRakshitha invests \u20b9 15000 in a company paying 7% per arum, when a share of value \u20b9 100 is selling for \u20b9 150. What is her annual income and what percentage does she get on her money?
\nAnswer:
\nIncome = \\(\\frac{\\text { Dividend }}{\\text { Amount }} \\times Cash\\)
\n= \\(\\frac{7}{150}\\)x 1500 = \u20b9 700<\/p>\n

Question 2.
\nWhich is a better investment?
\nAnswer:
\n(a) 8% stock at 110 = \\(\\frac{8}{110}\\) \u00d7 100 = 7.272%
\n9% stock at 98 = \\(\\frac{9}{98}\\) \u00d7 100 = 9.18%
\n98 9.18% > 7.272
\n\u2234 9% stock at 98 is a better investment<\/p>\n

(b) 6 \\(\\frac{1}{2}\\) % stock at 84 \\(\\frac{\\frac{13}{2}}{\\frac{84}{84}}\\) \u00d7 100 = 5.9%
\n4% stock at 102 = \\(\\frac{4}{102}\\) \u00d7 100 = 3.92%
\n\u2234 6\\(\\frac{1}{2}\\) % stock at 84 is a better investment<\/p>\n

(C) 7% stock at 115 = \\(\\frac{7}{115}\\) \u00d7 100 = 6.08%
\n5% stock at 88 = \\(\\frac{5}{88}\\) \u00d7 100 = 5.68%
\nHere 7% stock at 115 is better investment<\/p>\n

(d) 4% stock at 118 =
\n\\(\\frac{4}{118}\\) \u00d7 100 = 3.38%
\n6% stock at 124 = \\(\\frac{6}{124}\\) \u00d7 100 = 6.83%
\n\u2234 6% stock at 124 is better investment<\/p>\n

Question 3.
\nA man invests equal sums of money in 4%, 5% and 6% stock, each stock being at par. If the total income of the man is 23,600. Find his total investment.
\nAnswer:
\nLet the amount invested be x
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nWhat is the market value of 9.5% stock when an investment of \u20b9 12,400 produces an income of \u20b91472.5?
\nAnswer:
\nIncome = \\(\\frac{\\text { Dividend }}{\\text { Amount pershare }} \\times cash\\)
\n1472.5 = \\(\\frac{9.5}{\\mathrm{A}}\\) \u00d7 12,400
\n\u21d2 A = \\(\\frac{9.5 \\times 12,400}{1972.5}\\) = \u20b9 80
\nMarket value per share = \u20b9 80<\/p>\n

Question 5.
\nWhat is the quoted value of 12% stock if it earns an interest of 8% after deducting the income tax of 8%.
\nAnswer:
\nNet income 92 – open income is 100
\nNet income 8 \u2013 ? \\(\\frac{100 \\times 8}{92}\\) , Dividend = 12
\nIncome = \\(\\frac{D}{A}\\) x cash
\n\"2nd<\/p>\n

Question 6.
\nVenu invested \u20b9 5,02,950 in Infosys when price of \u20b95 shares was 3353. He sold shares worth \u20b9 500 when the price went upto 3583 and the remaining he sold when the price was \u20b9 3253. How much did Venu gain.
\nAnswer:
\nNumber of shares = \\(\\frac{50,2950}{3,353}\\) = 150
\n\u2234 Stock = 5 x 150 = 750
\nStock work 500 means 100 shares
\nPrice of 1 share is 3,585
\nPrice of 100 shares = 3,58,300
\nRemaining shares = 50
\nPrice of 1 share is 3,253
\nPrice of 50 shares = 1,62,650
\n\u2234Total amount received after selling the share’s is 3,58,300 + 1,62,650 = \u20b9 5,20,950
\nHence venu gaind 5,20,950 – 5,02,950 = \u20b9 18,000<\/p>\n

\"KSEEB<\/p>\n

Question 7.
\nRamesh has invested \u20b9 4,300 partly in 4.5% stock at \u20b9 72 and partly in 5% stock at \u20b9 95. If the total income
\nfrom both is \u20b9 250, find the investment in both the types of stock.
\nAnswer:
\nLet the amount invested in 4.5% stock be x
\nLet the amount invested in 5% stock be 4,300 – x
\n45 Income obtained from 4.5% stock is \\(\\frac{4.5}{72}\\) \u00d7 x
\nIncome obtained from 5% stock is \\(\\frac{5}{95}\\) \u00d7 (4,300 – x)
\nTotal interest income from both = 250
\n\"2nd
\n19x + 16 (4,300 – x) = 250 R 16 \u00d7 19
\n3x = 16 (4,750 – 4,300) \u21d2 3x = 16 \u00d7 450 \u21d2 x = 2,400
\nThe amount invested in 4.5% stock is \u20b9 2,400
\nThe amount invested in 5% stock is \u20b9 1,900<\/p>\n

Question 8.
\nRamesh holds \u20b9 2,100 of 3% stock. He sells at
\n\u20b9 121 and invests the proceeds in 5% stock. Thereby his income increases by 14. Find the market price of 5% stock.
\nAnswer:
\nStock 100 – amount 121
\nStock 2100 – ?
\nAmount = \\(\\frac{2,100 \\times 121}{100}\\) = 2,541
\nIncome = \\(\\frac{D}{A}\\) \u00d7 100
\n77 = \\(\\frac{8}{A}\\) x 2,541
\nAmount = \\(\\frac{5 \\times 2,541}{77}\\) = \u20b9 165
\nMarket price of 5% stock = \u20b9 165<\/p>\n

Question 9.
\nHow much must be invested in 14.25% stock at 98 to produce the same income as would be obtained by investing \u20b9 9,975 in 15% stock at 105.
\nAnswer:
\nLet the cash invested be x
\nIncome from 14.25% stock at 98 = \\(\\frac{14.25}{98}\\) x x
\nIncome from 15% stock at 105 by investing
\n\u20b9 9,975 = \\(\\frac{15}{105}\\) \u00d7 9,975
\nGiven both the incomes are equal
\n\"2nd
\n\u21d2 x = 9,800
\n\u2234 Amount to be invested = \u20b9 9800<\/p>\n

Question 10.
\nA stock yields 5% to an investor. A fall of 75 in its price causes it to yield 5 42%. What was its market value if the two income are equal.
\nAnswer:
\nLet dividend I = D1<\/sub> = 5,& D2<\/sub> = 5 \\(\\frac{1}{2}\\)
\n& Amount per share \u20b9 x & \u20b9 x-5
\nIncomes are equal i.e. \\(\\frac{D_{i}}{A_{1}}=\\frac{D_{2}}{A_{2}}\\)
\n\\(\\frac{5}{x-5}=\\frac{11}{2 x}\\)
\n10x = 11x – 55; 55 = 11x – 10x = x in
\n\u2234 its market value is 55.<\/p>\n

Question 11.
\nSanjana invests \u20b9 3240 in a stock at 108 and sells when the price falls to 104. How much stock at 130 can Sanjana now buy.
\nAnswer:
\n\"2nd<\/p>\n

Question 12.
\nA person invested 4200 partly in 5% stock at 125 and the remaining in 7.5% stock at 75. If income derived
\nfrom the two stocks is the same. Find the respective investments in each stock. Also find the total income
\nAnswer:
\nLet \u20b9 x be invested in 5 % stock at 125 & \u20b9(4,200 – x) will be invested in 7.5% at 75
\nI1<\/sub> = \\(\\frac{5}{125}\\) \u00d7 x
\nI2<\/sub> = \\(\\frac{7.5}{75}\\) \u00d7 (4,200 – x)
\nBoth incomes are equal
\n\"2nd
\n50x = 5,25,000 – 125x;
\n175x = 5,25,000 \u21d2 x= 3,000
\nAmount invested in 5% stock is \u20b9 3,000 & 7.5% is \u20b9 1,200
\nIncome from I stock = \\(\\frac{5}{125}\\) \u21d2 x 3,000 =120 & Total income \u21d2 120 + 120 = 240<\/p>\n

Question 13.
\nIf a person wishes to obtain 18% yield from his investment at what price should he buy 13.5% stock.
\nAnswer:
\nGiven yield = 18%, D = 13.5, A = ?
\nYield = \\(\\frac{\\mathrm{D}}{\\mathrm{A}}\\) \u00d7 100
\n18 = \\(\\frac{13.5}{A}\\) x 100 \u21d2 A = \\(\\frac{13.5 \\times 100}{18}\\) \u20b9 75<\/p>\n

\"KSEEB<\/p>\n

Question 14.
\n(a) A invests a sum of money in 5.5% stock at 90 and B and equal sum in 3.5% stock. If A’s income is
\n10% more than B’s find the price of 3.5% stock.
\n(b) How much money has to be invested in 11.5% stock at 73 to obtain an income of \u20b9 150 after a tax deduction at source of 20%.
\nAnswer:
\n(a) A9<\/sup> income = \\(\\frac{55}{90}\\) \u00d7 x
\nB9<\/sup> income = \\(\\frac{3.5}{y}\\) \u00d7 x
\nWhere x = investment
\ny = price of 3.5% stock
\nA9<\/sup> income: B19<\/sup> income :: 110 : 100
\n\"2nd
\n(b)
\nnet income is 150
\ntax deduction at 20%
\nNet income 80 – gross income 100
\nIf net income is 150 – ?
\n\"2nd<\/p>\n

Question 15.
\n(a) A person invests \u20b915000 partly in 3% stock at 75 and partly in 6% stock at 125. If the income from
\nboth is \u20b9 675 find his investment in the 2 types of stock.
\n(b) At what price a person has bought 25% shares with face value 100 which has give him 20% returns.
\nAnswer:
\n(a) Let x be invested in I stock & (15,000 – x) will be invested in II stock.
\nI1<\/sub> = Income obtained from Ist<\/sup> stock is \\(\\frac{3 x}{75}\\)
\nI2<\/sub> = Income obtained from 2nd stock = \\(\\frac{6}{125}\\) (15,000-x)
\nGiven Total income = I1<\/sub> + I2<\/sub> = 675
\n\\(\\frac{3 x}{75}\\) + \\(\\frac{6}{125}\\) (15,000-x) = 675
\n0.008 x = 45 \u21d2 x= 5,625
\n\u2234 Amount invested in 1st<\/sup> stock is \u20b9 5,625 and in 2nd stock is \u20b9 9,375<\/p>\n

(b) Yield = 20%, dividend = 25%
\nYield = \\(\\frac{\\mathrm{D}}{\\mathrm{A}}\\) = x 100
\n20 = \\(\\frac{25} {\\mathrm{A}}\\) \u00d7 100
\n\u0391 = \\(\\frac{25 \\times 100}{20}\\) = 125<\/p>\n

\"KSEEB<\/p>\n

Question 16.
\nRohan invested \u20b9 55000 partly in 8% stock at 80 and partly in 12% stock at 150 in such a way as to get a
\nreturn of 9% for his money. How much did Rohan invest in each.
\nAnswer:
\nLet \u20b9 x be invested in 8% stock at 80 & \u20b9 (55,000 – x) be invested in 12% stock at – 150.
\nTotal income = \\(\\frac{9}{100}\\) \u00d7 55,000 = 4,950
\nIncome in I stock = \\(\\frac{8}{800}\\) x
\nIncome in II stock = \\(\\frac{12}{150}\\) (55,000 – x)
\nTotal income = 4,950
\n\"2nd
\n12.5 x + 5,50,000 – 10x = 4,950 \u00d7 10 \u00d7 12.5
\n2.5x = 61,87,500 – 5,50,000
\n2.5x = 68,750 \u21d2 x= 27,500
\nRohan invests 27,500 in each<\/p>\n

Question 17.
\nPrathik sells out \u20b9 6000 of 7.5% stock at 108 and reinvests the proceeds in 9% stock. If Prathik’s income
\nincreases by 270. At what price did Prathik buy 9% stock.
\nAnswer:
\n\"2nd<\/p>\n

Question 18.
\nJane sells her \u20b9 12500, 4.5% stock at 94. How much of 9% stock at 125 can Jane purchase from the sale
\nproceeds of the former stock. What is the change in Jane’s income.
\nAnswer:
\nAmount obtained by selling 1,25,000 stock at 94 is \\(\\frac{12,500 \\times 94}{100}\\) = \u20b9 11.750
\n100 Jane 13 income from 4.5% stock is
\n= \\(\\frac{45}{100}\\) \u00d7 12,500 562.5
\n11,750 x 100 9% stock purchased at 125 is = \\(\\frac{11,750 \\times 100}{125}\\) = 9,400
\n125 Income from 9% stock is , \\(\\frac{9}{100}\\) \u00d7 9400 = 846
\n100 Change in income = 846 – 562.5 = \u20b9 283.5<\/p>\n

Question 19.
\nAman sells \u20b9 25000, 13.5% stock when the shares were selling at a premium of 20. He invests the proceeds
\npartly in 15% stock at 75 and partly in 16% stock at 128. Find how much he has invested in each stock if
\nhis income increases by \u20b9 1875.
\nAnswer:
\nAmount obtained by Selling 25,000
\nStock at \u20b9 120 is \\(\\frac{25,000 \\times 120}{100}\\) = 30.000
\n100 Let \u20b9 x be invested in 15% stock at 75
\n& \u20b9 (30,000 – x) invested in 16% stock at 128
\nIncome from 25,000 stock is \\(\\frac{13.5}{100}\\) \u00d7 25,000 = 3,375
\n100 New income = 3,375 + 1,875 = 5,250
\nIncome from 15% stock at 75 = \\(\\frac{15 x}{75}\\)
\nIncome from 16% stock at 128 = \\(\\frac{16}{128}\\) (30,000 – x)
\nTotal income = 5,250
\n\"2nd
\n8x + 1,50,000 – 5x = 5,250 \u00d7 40
\n3x = 60,000 \u21d2 x = 20,000
\n\u2234 He invested 20,000 at 15% & 10,000 at 16%<\/p>\n

\"KSEEB<\/p>\n

Question 20.
\nNihal has \u20b9 5 Maruthi shares worth \u20b9 1000. He sells 120 shares when the shares are selling at \u20b9 1400 and
\nthe remaining shares when the price goes upto \u20b9 1600. He invests the proceeds in \u20b9 10 Maruthi shares selling at \u20b9 1184 find the number of Maruthi shares purchased by Nihal.
\nAnswer:
\nNo. of Shares = \\(\\frac{1,000}{5}\\) = 200
\nAmount received by selling 120 shares at 1400 = 120 \u00d7 1,400 = 1,68,000
\nAmount received by selling 80 shares art 1,600 = 80 \u00d7 1,600 = 1,28,000
\n\u2234 Total amount = 1,68,000 + 1,28,000 = 2,96,000
\n\u2234 Number of shares purchased = \\(\\frac{29,6000}{1,184}\\) = 250<\/p>\n

Question 21.
\nA man owns 50 SBI shares which are now selling at the rate of 1800. He needs 50,000 for his daughter’s
\neducation. He decides to sell 25 SBI shares. The brokerage charged is 25%. How much more money does
\nhe need to arrange after selling the share.
\nAnswer:
\nAmount received after selling 25 shares at \u20b9 1800 = 45,000
\nBrokerage = \\(\\frac{25}{100}\\) \u00d7 45,000 = 112.5
\nMoney obtained = 45,000 – 112.5 = 4,4887.5
\nHe has to arrange for 50,000 – 4,4887.5 = 5112.5<\/p>\n

Question 22.
\nRakshith decides to invest in TCS shares which are selling at 2020 per share. How much money is required
\nto purchase 10 shares if the brokerage is 0.5%.
\nAnswer:
\nSelling price of 10 shares at 2020 per share = 20,200
\n0.5 Brokerage = \\(\\frac{0.5}{100}\\) \u00d7 20,200 = \u20b9 101
\n100 Amount required to purchase = 20,200 + 101 = 20,301<\/p>\n

Question 23.
\nRitu purchased 200 HDFC shares when the price was 625 and then sold all the shares when the price
\nwent upto 715. If the brokerage for each transaction was 1%. How much did Ritu gain.
\nAnswer:
\nSelling price of 200 shares at 625 = 1,25,000
\nBrokerage is \\(\\frac{1}{100}\\) \u00d7 1,25,000 = 1,250
\nAmount paid = 1,25,000 + 1,250 = 1,26,250.
\nSelling price of 200 shares at 715 = 1,43,000
\nBrokerage is \\(\\frac{1}{100}\\) \u00d7 1,43,000 = 1,430
\nAmount received = 1,43,000 – 1,430 = 1,41,570
\nRitu gained = 1,41,570 – 1,26,250 = \u20b9 15,320<\/p>\n

Question 24.
\nIf a client buys shares worth \u20b990,000 and sells shares worth \u20b9 1,10,000 through a stock broker calculate
\nthe brokerage payable to the stock broker if the brokerage rate is 0.5% each side.
\nAnswer:
\nBrokerage is \\(\\frac{0.5}{100}\\) \u00d7 (1,10,000 – 90,000) = \\(\\frac{0.5}{100}\\) \u00d7 20,000 = \u20b9 100<\/p>\n

Question 25.
\nVeena buys 100 shares of Karnataka bank at \u20b9 101 per share. She pays \u20b9 10,130.3 to her broker. What is
\nthe total brokerage she paid and calculate the percentage rate of brokerage.
\nAnswer:
\nSelling price of 100 shares at 101 = 10,100
\nAmount paid is 10130.3
\nBrokerage is 10130.3 – 10,100 = 30.3
\n100 x 30.3 Rate of brokerage is \\(\\frac{100 \\times 30.3}{10,100}\\) = 0.3%<\/p>\n

\"KSEEB<\/p>\n

Question 26.
\nMr. Ravi sold \u20b9 2,250 stock at 75 and bought stock at 88.5 with the proceeds. How much stock does he buy
\nif the brokerage is 2% for selling and 1.5% for buying.
\nAnswer:
\nMr. Ravi selling price of 2,250 stock at 75 is = \\(\\frac{2,250 \\times 75}{100}\\) = 1,687.5
\nBrokerage is \\(\\frac{2}{100}\\) \u00d7 1,687.5 = 33.75
\n100 Amount received = 1,687.5 \u2013 33.75 = 1,653.75
\nBrokerage for buying is 1.5%
\nBrokerage is on cash = \\(\\frac{1,653.75 \\times 1.5}{100}\\) = 24.81
\n100 Cash available for purchasing shares = 1,653.75 – 24.81 = 1,628.94
\nStock purchased at 88.5 = \\(\\frac{1,628.94 \\times 100}{88.5}\\) = 1,840.61<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Basic Maths Exercise 9.1 Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka 2nd PUC Basic Maths Question Bank Chapter 9 Stocks and Shares Ex 9.1 Part – A 2nd …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[82],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/20451"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=20451"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/20451\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=20451"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=20451"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=20451"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}