{"id":20192,"date":"2020-01-18T15:10:07","date_gmt":"2020-01-18T09:40:07","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=20192"},"modified":"2021-07-02T15:28:48","modified_gmt":"2021-07-02T09:58:48","slug":"2nd-puc-basic-maths-question-bank-chapter-17-ex-17-5","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/2nd-puc-basic-maths-question-bank-chapter-17-ex-17-5\/","title":{"rendered":"2nd PUC Basic Maths Question Bank Chapter 17 Limit and Continuity of a Function Ex 17.5"},"content":{"rendered":"

Students can Download Basic Maths Exercise 17.5 Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka 2nd PUC Basic Maths Question Bank Chapter 17 Limit and Continuity of a Function Ex 17.5<\/h2>\n

Part – A<\/span><\/p>\n

2nd PUC Basic Maths Limit and Continuity of a Function Ex 17.5 Two or Three Marks Questions and Answers<\/strong><\/p>\n

Question 1.
\n\"2nd
\nAnswer:
\nAlso f(x) at x = 5 is 10; i.e, f(5) = 10
\n\"2nd
\n\u2234 the function f(x) is continuous at x = 5<\/p>\n

Question 2.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\nDefine f(0) so that f(x) = \\(\\frac{x}{1-\\sqrt{1-x}}\\) become continuous at x = 0
\nAnswer:
\n\"2nd
\nAlso f(x) at x = 0 is 2
\ni.e f(x) = f(0) = 2
\nsince f is continuous at x = 0.<\/p>\n

Question 4.
\n\"2nd
\nAnswer:
\n\"2nd
\nAlso f(x) at x = 0 is e3<\/sup> i.e f(0) = e3<\/sup>
\n\"2nd
\n\u2234 f(x) is continuous at x = 0<\/p>\n

Question 5.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Question 6.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

Question 7.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

Question 8.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Question 9.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

Question 10.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Part – C<\/span><\/p>\n

2nd PUC Basic Maths Limit and Continuity of a Function Ex 17.5 Five Marks Questions and Answers<\/strong><\/p>\n

Question 1.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

Question 2.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

Question 4.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Question 5.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

Question 6.
\n\"2nd
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

part – B<\/span><\/p>\n

2nd PUC Basic Maths Limit and Continuity of a Function Ex 17.5 Six Marks Questions and Answers<\/strong><\/p>\n

Limits Theorems<\/p>\n

Question 1.
\nprove that \\(\\lim _{x \\rightarrow a} \\frac{x^{n}-a^{n}}{x-a}=n a^{n-1}\\) for all values of n
\nAnswer:
\nCase – 1 : Let n be a positive integer.
\nxn<\/sup> – an<\/sup> = (x – a)(xn -1<\/sup> + xn-2<\/sup> . a + xn-3<\/sup> . a2<\/sup> + ……. + an-1 <\/sup>
\n\"2nd<\/p>\n

Case – 2: Let n be a positive integer
\nPut n = -m, m > 0
\n\"2nd
\n\"2nd<\/p>\n

Case – 3: Let n = p\/q where p and q are integers and q \u2260 0
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Question 2.
\n\"2nd
\nAnswer:
\nLet ‘0’ the centre of unit circle, assume that \u03b8 is measured in positive radians
\n\"2nd
\nFromn the figure, we have area of \u2206AOB = area of sector AOB = area of \u2206AOD
\n\"2nd
\n\u2234 Area of sector = \\(\\frac { 1 }{ 2 }\\) (radius)2<\/sup> \u00d7 angle in radians
\nFrom the triangle DOA, tan \u03b8 = \\(\\frac{\\mathrm{DA}}{\\mathrm{OA}}\\) \u2234DA = rtan \u03b8
\nFrom the triangle BOC, sin \u03b8 = \\(\\frac{\\mathrm{BC}}{\\mathrm{OB}}\\) \u2234 BC = rsin \u03b8
\n(1) becomes
\n\u21d2 BC \u2264 \u03b8 \u2264 DA
\n\u21d2 sin \u03b8 \u2264 \u03b8 \u2264 tan \u03b8
\nDividing by sin \u03b8<\/p>\n

\"2nd
\n\"2nd
\n\"2nd<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Basic Maths Exercise 17.5 Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka 2nd PUC Basic Maths Question Bank Chapter 17 Limit and Continuity of a Function Ex 17.5 Part …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[82],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/20192"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=20192"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/20192\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=20192"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=20192"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=20192"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}