{"id":19774,"date":"2020-01-14T12:20:06","date_gmt":"2020-01-14T06:50:06","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=19774"},"modified":"2021-07-02T15:29:37","modified_gmt":"2021-07-02T09:59:37","slug":"2nd-puc-basic-maths-question-bank-chapter-7-ex-7-2","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/2nd-puc-basic-maths-question-bank-chapter-7-ex-7-2\/","title":{"rendered":"2nd PUC Basic Maths Question Bank Chapter 7 Ratios and Proportions Ex 7.2"},"content":{"rendered":"

Students can Download Basic Maths Exercise 7.2 Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka 2nd PUC Basic Maths Question Bank Chapter 7 Ratios and Proportions Ex 7.2<\/h2>\n

Part – A<\/span><\/p>\n

2nd PUC Basic Maths Ratios and Proportions Ex 7.2 One Mark Questions and Answers ( 1 \u00d7 4 = 4)<\/strong><\/p>\n

Question 1.
\nState which of the following are proportions.
\n(1) 2 : 3 :: 6 : 9
\n(ii) 1 : 3 :: 4 : 15
\n(iii) 3 : 5 :: 6 : 15
\n(iv) 7 : 9 :: 14 : 18
\nAnswers:
\n(i) 2 \u00d7<\/strong> 9 = 3 \u00d7<\/strong> 6
\n18 = 18 It is a proportion<\/p>\n

(ii) 1 \u00d7<\/strong> 15 \u2260 3 \u00d7<\/strong> 4
\nIt is not a proportion<\/p>\n

(iii) 3 \u00d7<\/strong> 15 \u2260 5 \u00d7<\/strong>\u00a06
\n\u2234not a proportion<\/p>\n

(iv) 7 \u00d7<\/strong> 18 = 9 \u00d7<\/strong> 14 ii
\n126 = 126 It is a proportion<\/p>\n

\"KSEEB<\/p>\n

Question 2.
\nFind the fourth proportional to each of the following.
\n(1) 4, 5, 24
\n(ii) 6, 12, 15
\n(ii) 1.5, 4.5, 3.5
\n(iv) \\(\\frac{1}{2}, \\frac{1}{3}, \\frac{1}{4}\\)
\nAnswer:
\nLet x be the fourth proportional
\n(i) 4 : 5 :: 24 : x
\n4x = 5 x 24 \u21d2 x = \\(\\frac{5 \\times 24}{4}\\) \u21d2 X=30<\/p>\n

(ii) 6 : 12 = 15 : x
\n\u21d2 x =\\( \\frac{12 \\times 15}{6}\\) = 30 \u21d2 x = 30<\/p>\n

(iii) 1.5 : 4.5 = 3.5 : x
\nx = \\(\\frac{4.5 \\times 3.5}{1.5}\\) = 10.5<\/p>\n

(iv)
\n\"2nd<\/p>\n

Question 3.
\nFind the mean proportional to each of the following.
\n(i) 1 and 9
\n(ii) 2 and 8
\n(iii) \\(\\frac{1}{16}\\) and \\(\\frac{1}{25}\\)
\n(iv) 0.8 and 1.8
\nAnswers:
\nLet x be the mean proportional<\/p>\n

(i) 1&9
\n1 : x= x : 9
\nx2<\/sup> = 9
\nx = 3<\/p>\n

(ii) 2 & 8
\n2 : x = x : 8
\nx2<\/sup> = 16
\nX = 4<\/p>\n

(iii)
\n\"2nd<\/p>\n

(iv) 0.8 and 1.8
\nx2<\/sup> = 0.8 x 1.8
\nx = 1.2<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nFind the third proportional to each of the following,
\n(i) 4, 6
\n(ii) 3,12
\n(iii) 2.4, 3.6
\n(iv) 2\\(\\frac{2}{3}\\) , 4
\nAnswers:
\nLet x be the third proportional
\n(i) 4,6
\n4:6 = 6 : x
\nx = \\(\\frac{36}{4}\\) = 9<\/p>\n

(ii) 3, 12
\n3 : 12 = 12 : x
\nx = \\(\\frac{12 \\times 12}{3}\\) = 48<\/p>\n

(iii) 2.4, 3.6
\n2.4:3.6 = 3.6 : x
\nx = \\(\\frac{3.6 \\times 3.6}{2.4}\\) = 5.4<\/p>\n

(iv) 2\\(\\frac{2}{3}\\) , 4
\n\\(\\frac{8}{3}\\):4 = 4 : x
\n2.4 : 3.6 = 3.6 : x
\nx = \\(\\frac{4 \\times 4}{\\frac{8}{3}}\\) = 6<\/p>\n

Part – B and C<\/span><\/p>\n

2nd PUC Basic Maths Ratios and Proportions Ex 7.2 Three Marks Questions and Answers ( 3 \u00d7 6 = 18)<\/strong><\/p>\n

Question 1.
\nIf \\(\\frac{a}{b}=\\frac{c}{d}\\) then prove that \\(\\frac{3 a+5 b}{3 c+5 d}=\\frac{3 a-5 b}{3 c-5 d}\\)
\nAnswer:
\n\"2nd<\/p>\n

Question 2.
\nIf \\(\\frac{\\sqrt{1+x}+\\sqrt{1-x}}{\\sqrt{1+x}-\\sqrt{1-x}}=\\frac{a}{b}\\)find x
\nAnswer:
\n\"2nd<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\nFind the numbers which added to the numerator and denominator of 25 : 37 make it 5 : 6.
\nAnswer:
\nLet x be added to numerator and denominator of 25 : 37.
\n\u2234 \\(\\frac{25+x}{37+x}=\\frac{5}{6}\\)
\n150 + 6x = 185 + 5x
\nx = 185 – 150 = 35
\n\u2234 x = 35.<\/p>\n

Question 4.
\nThe ages of a father and his for son in the ratio 6:1. After 14 years their age will be in the ratio 8:3 what are their present ages?
\nAnswer:
\nLet the father’s age be 6x and Son’s age be x
\nAfter 14 years father’s age is 6x + 14 and Son’s is x + 14
\nGiven \\(\\frac{6 x+14}{x+14}=\\frac{8}{3}\\)
\n18x + 42 = 8x + 112
\n10x = 70 \u21d2 x = 7
\n\u2234 father’s age is 6x = 6 x 7 = 42 years and son’s age = 7 years.<\/p>\n

Question 5.
\nFour numbers formed by adding 1, 5, 10 and 15 to a certain number are in proportion. Find the number?
\nAnswer:
\nLet the number be x
\n\u2234 1 + x, 5 + x, 10 + x, 15 + x are in proportion
\n\u2234 (5 + x) (10 + x) = (1 + x) (15 + x)
\n50 + 10x + 5x + x2<\/sup> = 15 + 15x + x + x2<\/sup>
\n\u21d2 x= 35<\/p>\n

\"KSEEB<\/p>\n

Question 6.
\nA concrete mixture was made of cement, chips and sand. The ratio of the cement and chip is the same as that of chips and the sand. If 144 bags of cement and 225 bags of sand were used is the mixture. Find the
\nnumber of bags of chips used in the mixture.
\nAnswer:
\nCement: Chip = Chip : Sand
\n\u2234 (Chip)2<\/sup> = Cement \u00d7<\/strong> Sand
\n\u2234 (Chip)2<\/sup> = 144 \u00d7<\/strong> 225
\nChip = 12\u00d7<\/strong> 15.= 180
\n\u2234 Number of bags of chips is 180.<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Basic Maths Exercise 7.2 Questions and Answers, Notes Pdf, 2nd PUC Basic Maths Question Bank with Answers helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka 2nd PUC Basic Maths Question Bank Chapter 7 Ratios and Proportions Ex 7.2 Part – A 2nd …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[82],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/19774"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=19774"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/19774\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=19774"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=19774"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=19774"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}