{"id":18217,"date":"2020-01-06T10:37:28","date_gmt":"2020-01-06T05:07:28","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=18217"},"modified":"2021-07-02T15:31:11","modified_gmt":"2021-07-02T10:01:11","slug":"kseeb-solutions-for-class-6-maths-chapter-11-ex-11-3","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-6-maths-chapter-11-ex-11-3\/","title":{"rendered":"KSEEB Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.3"},"content":{"rendered":"

Students can Download Chapter 11 Algebra Ex 11.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 6 Maths Chapter 11 Algebra Ex 11.3<\/h2>\n

Question 1.
\nMake up as many expressions with numbers ( no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multiplication.
\n(Hint: Three possible expressions are 5 + (8 – 7), 5 – (8 – 7),(5 \u00d7 8) + 7; make the other expressions.)
\nSolution:
\nMany expressions can be formed by using the 3 numbers 5, 7 and 8 Some of these are as follows 5 \u00d7 (8 – 7)
\n5 \u00d7 (8 + 7)
\n(8 + 5) \u00d7 7
\n(8 – 5) \u00d7 7
\n(7 + 5) \u00d7 8
\n(7 – 5) \u00d7 8<\/p>\n

Question 2.
\nWhich out of the following are expressions with numbers only?
\na) y + 3
\nb) (7 \u00d7 20) – 8z
\nc) 5(21 – 7) + 7 \u00d7 2
\nd) 5
\ne) 3x
\nf) 5 – 5n
\ng) (7 \u00d7 20) – (5 \u00d7 10) – 45 + p
\nSolution:
\nIt can be observed that the expressions in alternatives (c) and (d) are formed by using numbers only.<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\nIdentify the operations(addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed.
\na) z + 1, z – 1, y + 17, y – 17
\nSolution:
\nAddition as 1 is added to z
\nSubtraction as 1 is subtracted from z
\nAddition as 17 is added to y
\nSubtraction as 17 is subtracted from y<\/p>\n

b) 17y, \\(\\frac{y}{17}\\), 5z
\nMultiplication as y is multiplied as y is multiplied with 17
\nDivision as y is divided by 17
\nMultiplication as z is multiplied with 5
\nMultiplication as z is multiplied with 5<\/p>\n

c) 2y + 17, 2y – 17
\nMultiplication and addition
\ny is multiplied with 2, and 17 is added to the result<\/p>\n

d) 7m, -7m + 3, -7m – 3
\nMultiplication with 2 and 17 is subtracted from the result
\nMultiplication and subtractions m is multiplied by 7 and 3 is subtracted from the result<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nGive expressions for the following cases.
\nSolution:
\na) 7 added to p
\nP + 7<\/p>\n

b) 7 subtracted from p
\nP – 7<\/p>\n

c) p multiplied by 7
\n7p<\/p>\n

d) p divided by 7
\nP<\/p>\n

e) 7 subtracted from -m
\n-m – 7<\/p>\n

f) -p multiplied by 5
\n– 5p<\/p>\n

g) -p divided by 5
\n\\(\\frac{-p}{5}\\)<\/p>\n

h) p multiplied by -5.
\n-5p<\/p>\n

Question 5.
\nGive expressions in the following cases.
\nSolution:
\na) 11 added to 2m
\n2m + 11<\/p>\n

b) 11 subtracted from 2m
\n2m – 11<\/p>\n

c) 5 times y to which 3 is added
\n5y + 3<\/p>\n

d) 5 times y from which 3 is subtracted
\n5y – 3<\/p>\n

e) y is multiplied by -8
\n-8y<\/p>\n

f) y is multiplied by -8 and then 5 is added to the result
\n-8y + 5<\/p>\n

g) y is multiplied by 5 and the result is subtracted from 16
\n16 – 5y<\/p>\n

h) y is multiplied by -5 and the result is added to 16
\n-5y + 16<\/p>\n

\"KSEEB<\/p>\n

Question 6.
\na) Form expressions using t and 4. Use not more than one number operation. Every expression must have t in it.
\nSolution:
\nt + 4, +t – 4, 4 +, \\(\\frac{t}{4}\\), \\(\\frac{4}{t}\\), -4 – t, 4 + t<\/p>\n

b) Form expressions using y, 2 and 7. Every expression must have y in it. Use only two number operations. These should be different.
\nSolution:
\n2y + 7, 2y – 7, 7y + 2….<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Chapter 11 Algebra Ex 11.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 6 Maths Chapter 11 Algebra Ex 11.3 Question 1. Make up as many expressions with …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[83],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/18217"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=18217"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/18217\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=18217"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=18217"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=18217"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}