{"id":18036,"date":"2020-01-04T15:31:32","date_gmt":"2020-01-04T10:01:32","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=18036"},"modified":"2021-07-02T15:31:15","modified_gmt":"2021-07-02T10:01:15","slug":"kseeb-solutions-for-class-6-maths-chapter-14-ex-14-4","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-6-maths-chapter-14-ex-14-4\/","title":{"rendered":"KSEEB Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4"},"content":{"rendered":"

Students can Download Chapter 14 Practical Geometry Ex 14.4 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 6 Maths Chapter 14 Practical Geometry Ex 14.4<\/h2>\n

Question 1.
\nDraw any line segment \\(\\overline{\\mathbf{A B}}\\). Mark any point M on it. Through M, draw a perpendicular to \\(\\overline{\\mathbf{A B}}\\). (use ruler and compasses)
\nSolution:
\n(1) Draw the given line segment \\(\\overline{\\mathbf{A B}}\\) and mark an point M on it.
\n(2) With M as centre and a convenient radius, construct an arc intersecting the line segment \\(\\overline{\\mathbf{A B}}\\) at two points C and D.
\n\"KSEEB
\n(3) With C and D as centres and a radius greater than CM, construct two arcs. Let these be intersecting each other at E.
\n(4) Join EM. \\(\\overline{\\mathrm{EM}}\\) is perpendicular to AB<\/p>\n

\"KSEEB<\/p>\n

Question 2.
\nDraw a line segment \\(\\overline{\\mathrm{AB}}\\) Take any point R not on it. Through R, draw a perpendicular to \\(\\overline{\\mathrm{AB}}\\). (use ruler and set-square)
\nSolution:
\n(1) Take the given line segment \\(\\overline{\\mathrm{PQ}}\\) and mark any point R outside \\(\\overline{\\mathrm{PQ}}\\).
\n(2) Place a set square on \\(\\overline{\\mathrm{PQ}}\\) such that one arm of its right angle aligns along \\(\\overline{\\mathrm{PQ}}\\).
\n\"KSEEB
\n(3) Place the ruler along the edge opposite to the right P angle of the set square.
\n(4) Hold the ruler fixed. Slide the set square along the ruler till the point R touches the other arm of the set square.
\n(5) Draw a line along this edge of the set square which will be passing through R. It is the required line, which is perpendicular to \\(\\overline{\\mathrm{PQ}}\\).<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\nDraw a line l and a point X on it. Through X, draw a line segment \\(\\overline{\\mathrm{XY}}\\) perpendicular to l.
\nNow draw a perpendicular to \\(\\overline{\\mathrm{XY}}\\) at Y. (use ruler and compasses)
\nSolution :
\n(1) Draw a line l and mark a point X on it.
\n(2) Taking X as centre and with a convenient radius, draw an arc intersecting line 1 at two points A and B.
\n(3) With A and B as centres and a radius more than AX, construct two arcs intersecting each other at Y.
\n\"KSEEB
\n(4) Join XY. \\(\\overline{\\mathrm{XY}}\\) is perpendicular to l.
\nSimilarly, a perpendicular to \\(\\overline{\\mathrm{XY}}\\) at point Y can be drawn. The line \\(\\overline{\\mathrm{ZY}}\\) is perpendicular t0 \\(\\overline{\\mathrm{XY}}\\) at Y.<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Chapter 14 Practical Geometry Ex 14.4 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 6 Maths Chapter 14 Practical Geometry Ex 14.4 Question 1. Draw any line segment …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[83],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/18036"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=18036"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/18036\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=18036"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=18036"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=18036"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}