{"id":16819,"date":"2019-12-31T12:16:05","date_gmt":"2019-12-31T06:46:05","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=16819"},"modified":"2021-07-02T15:33:07","modified_gmt":"2021-07-02T10:03:07","slug":"kseeb-solutions-for-class-6-maths-chapter-3-ex-3-6","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-6-maths-chapter-3-ex-3-6\/","title":{"rendered":"KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.6"},"content":{"rendered":"

Students can Download Chapter 3 Playing with Numbers Ex 3.6 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 6 Maths Chapter 3 Playing with Numbers Ex 3.6<\/h2>\n

Question 1.
\nFind the HCF of the following numbers:
\n(a) 18, 48
\n(b) 30,42
\n(c) 18, 60
\n(d) 27, 63
\n(e) 36, 84
\n(f) 34, 102
\n(g) 70, 105, 175
\n(h) 91, 112, 49
\n(i) 18, 54, 81
\n(j) 12, 45, 75
\nSolution:
\na) 18, 48
\n18 = 1, 2, 3, 6, 9, 18
\n48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
\nCommon factors = 1, 2, 3, 6
\nH.C.F of 18 & 48 = \\(\\boxed { 6 } \\)<\/p>\n

b) 30, 42
\n30 = 1, 2, 3, 5, 6, 10, 15, 30
\n42 = 1, 2, 3, 4, 6, 7, 14, 21, 42
\nCommon factors = 1, 2, 3, 6
\n\u2234 H.C.F. = \\(\\boxed { 6 } \\)
\n\u2234 H.C.F of 30 & 42 is \\(\\boxed { 6 } \\)<\/p>\n

\"KSEEB<\/p>\n

c) 18 & 60
\n18 = 1, 2, 3, 6, 9, 18
\n60 = 1, 2, 3, 4, 6, 10, 12, 15, 30, 60
\nCommon factors = 1, 2, 3, 6
\n\u2234 H.C.F. of 18 & 60 is \\(\\boxed { 6 } \\)<\/p>\n

d) 27 & 63
\n27 = 1, 3, 9, 27
\n63 = 1, 3, 7, 9, 21, 63
\n\u2234 Common factors = 1, 3, 9
\n\u2234 H.C.F. of 27 & 63 is = 9.<\/p>\n

e) 36 & 84
\n36 = 1, 2, 3, 4, 6, 9, 12, 18, 36
\n84 = 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84
\n\u2234 Common factors = 1, 2, 3, 4, 6, 12
\n\u2234 H.C.F. of 36 & 84 is 12.<\/p>\n

f) 34 & 102
\n34 = 1, 2, 17, 34
\n102 = 1, 2, 3, 6, 17, 34, 51, 102
\n\u2234 Common factors = 1, 2, 17, 34
\n\u2234 H.C.F. of 34 & 102 is 34.<\/p>\n

g) 70, 105, 175
\n70 = 1<\/u>, 2, 5<\/u>, 7, 10, 14, 35<\/u>, 70
\n105 = 1<\/u>, 3, 5<\/u>, 7<\/u>, 10, 14, 35<\/u>, 105
\n175 = 1<\/u>, 5<\/u>, 7<\/u>, 25, 35<\/u>, 175
\n\u2234 Common factors 1, 5, 7, 35
\n\u2234 H.C.F. of 70, 105, 175 is 35<\/p>\n

h) 91, 112, 49
\n91 = 1<\/u>, 7<\/u>, 13, 91
\n112 = 1<\/u>, 2, 4, 7<\/u>, 8, 14, 16, 28, 56, 112
\n49 = 1<\/u>, 7<\/u>, 49<\/u>
\n\u2234 Common factors = 1, 7
\n\u2234 H.C.F. of 91, 112, 49 is 7<\/p>\n

\"KSEEB<\/p>\n

i) 12, 45, 75
\n12 = 1<\/u>, 2, 3, 4, 6, 12
\n45 = 1<\/u>, 3, 5, 9, 15, 45
\n75 = 1<\/u>, 3, 5, 15, 26, 75
\n\u2234 Common factors 1, 3
\n\u2234 H.C.F of 12, 45, 75 is 3.<\/p>\n

Question 2.
\nWhat is the HCF of two consecutive
\n(a) numbers?
\n(b) even numbers?
\n(c) odd numbers?
\nFind the HCF of the following:
\n(i) 24 and 36
\n(ii) 15, 25 and 30
\n(iii) 8 and 12
\n(iv) 12, 16 and 28
\nSolution:
\n(i) 1 e.g., HCF of 2 and 3 is 1.
\n(ii) 2 e.g., HCF of 2 and 4 is 2.
\n(iii) 1 e.g., HCF of 3 and 5 is 1.<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\nHCF of co-prime numbers 4 and 15 was found as follows by factorisation:
\n4 = 2 \u00d7 2 and 15 = 3 \u00d7 5 since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?
\nSolution:
\nNo. The answer is not correct. 1 is the correct HCF.<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Chapter 3 Playing with Numbers Ex 3.6 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 6 Maths Chapter 3 Playing with Numbers Ex 3.6 Question 1. Find the …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[83],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/16819"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=16819"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/16819\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=16819"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=16819"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=16819"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}