{"id":16694,"date":"2019-12-31T10:20:02","date_gmt":"2019-12-31T04:50:02","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=16694"},"modified":"2021-07-02T15:33:24","modified_gmt":"2021-07-02T10:03:24","slug":"kseeb-solutions-for-class-6-maths-chapter-3-ex-3-2","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-6-maths-chapter-3-ex-3-2\/","title":{"rendered":"KSEEB Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.2"},"content":{"rendered":"

Students can Download Chapter 3 Playing with Numbers Ex 3.2 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths<\/a> helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 6 Maths Chapter 3 Playing with Numbers Ex 3.2<\/h2>\n

Question 1.
\nWhat is the sum of any two
\na) odd numbers
\nb) Even numbers?
\nSolution:
\na) The sum of two odd numbers is even
\neg:- 1 + 5 = 6; 16 + 18 = 34
\nb) The sum of two even numbers is even
\neg:- 4 + 2 = 6; 10 + 18 = 28<\/p>\n

\"KSEEB<\/p>\n

Question 2.
\nState whether the following statements are True or False:
\nSolution:
\na) The sum of three odd numbers is even.
\nFalse 3 + 5 + 7 = 15. i,e. odd<\/p>\n

b) The sum of two odd numbers and one even number is even.
\nTrue 3 + 5 + 6 = 14 i,e = even<\/p>\n

c) The product of three odd numbers is odd.
\nTrue 3 \u00d7 5 \u00d7 7 = 105 i.e, odd.<\/p>\n

d) If an even number is divided by 2, the quotient is always odd.
\nFalse 4 \u00f7 2 = 2 i.e, even<\/p>\n

e) All prime numbers are odd.
\nFalse; 2 is even number.<\/p>\n

f) Prime numbers do not have any factors.
\nFalse; 1 and the numbers itself are factors of the number.<\/p>\n

g) Sum of two prime numbers is always even.
\nFalse 2 + 3 = 5 i,e odd<\/p>\n

\"KSEEB<\/p>\n

h) 2 is the only even prime number.
\nTrue<\/p>\n

i) All even numbers are composite numbers.
\nFalse, 2 is a prime numbers.<\/p>\n

j) The product of two even numbers is always even.
\nTrue; 2 \u00d7 4 = 8, i.e even<\/p>\n

Question 3.
\nThe numbers 13 and 31 are prime numbers. Both these numbers have same digits 1 and 3. Find such pairs of prime numbers upto 100.
\nSolution:
\na) 17, 71
\nb) 37, 73
\nc) 79, 97<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\nWrite down separately the prime and composite numbers less than 20.
\nSolution:
\nPrime numbers less than 20 are
\n2, 3, 5, 7, 11, 13, 17, 19
\nComposite numbers less than 20 are
\n4, 6, 8, 9, 10, 12, 14, 15, 16, 18<\/p>\n

Question 5.
\nWhat is the greatest prime number between 1 and 10.
\nSolution:
\nPrime numbers between 1 and 10 are 2, 3, 5, 7 among these numbers 7 is the greatest.<\/p>\n

Question 6.
\nExpress the following as the sum of two odd primes,
\na) 44
\nb) 36
\nc) 24
\nd) 18
\nSolution:
\na) 44 = 37 + 7 = 13 + 31
\nb) 36 = 31 + 5 = 17 + 19
\nc) 24 = 19 + 5 = 11 + 13
\nd) 18 = 5 + 13 = 7 + 11<\/p>\n

\"KSEEB<\/p>\n

Question 7.
\nGive three pairs of prime numbers whose difference is 2.
\n[Remark: Two prime numbers whose difference is 2 are called twin primes]
\nSolution:
\ni) 3 & 5
\nii) 5 & 7
\niii) 11 & 13
\niv) 17 & 19
\nv) 29 & 31 etc.<\/p>\n

\"KSEEB<\/p>\n

Question 8.
\nWhich of the following numbers are prime?
\na) 23
\nb) 51
\nc) 37
\nd) 26
\nSolution:
\na) 23 = 23 \u00d7 1 = 23; 23 = 1 \u00d7 23
\n23 has only two factors, 1 and 23 Therefore, it is a prime numbers<\/p>\n

b) 5 = 1 \u00d7 51 = 51; 51 = 17 \u00d7 3
\n51 has four factors, 1, 3, 17, 51. Therefore, it is not a prime number, it is a composite number.<\/p>\n

c) 37 It has only two factors 1 and 37.
\nIt is a prime number<\/p>\n

d) 26 26 has four factors (1, 2, 13, 26)
\nTherefore, it is not a prime number It is a composite number<\/p>\n

\"KSEEB<\/p>\n

Question 9.
\nWrite seven consecutive composite numbers less than 100 so that there is no prime number between them.
\nSolution:
\nBetween 89 and 97, both of which are prime numbers there are 7 composite numbers.
\nThey are 90, 91, 92, 93, 94, 95, 96, numbers factors
\n90 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90
\n91 = 1, 7, 13, 91
\n92 = 1, 2, 4, 23, 46, 92
\n93 = 1, 3, 31, 93
\n94 = 1, 2, 47, 94
\n95 = 1, 5, 19, 95
\n96 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96<\/p>\n

Question 10.
\nExpress each of the following numbers as the sum of three odd primes:
\na) 21
\nb) 31
\nc) 53
\nd) 61
\nSolution:
\na) 21 = 3 + 7 + 11
\nb) 31 = 5 + 7 + 19
\nc) 53 = 3 + 19 + 31
\nd) 61 = 11 + 19 + 31<\/p>\n

\"KSEEB<\/p>\n

Question 11.
\nWrite five pairs of prime numbers less than 20 Whose sum is divisible by 5. (Hint: 3 + 7 = 10)
\nSolution:
\nThe five pair of prime numbers less than 20 divisible by 5 are 2 + 3 = 5
\n2 + 13 = 15
\n3 + 17 = 20
\n7 + 13 = 20
\n19 + 11 = 30<\/p>\n

Question 12.
\nFill in the blanks:
\n1. A number which has only two factors is called a prime number<\/span>
\n2. A numbers Which has more than two factors is called a composite number<\/span>
\n3. 1 is neither prime number<\/span> nor composite number<\/span>
\n4. The smallest prime number is 2<\/span>
\n5. The smallest composite number is 4<\/span>
\n6. The smallest even number is 2<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Chapter 3 Playing with Numbers Ex 3.2 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 6 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 6 Maths Chapter 3 Playing with Numbers Ex 3.2 Question 1. What is …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[83],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/16694"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=16694"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/16694\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=16694"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=16694"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=16694"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}