{"id":16101,"date":"2020-09-10T10:26:45","date_gmt":"2020-09-10T04:56:45","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=16101"},"modified":"2021-07-02T15:01:53","modified_gmt":"2021-07-02T09:31:53","slug":"kseeb-solutions-for-class-7-maths-chapter-13-ex-13-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-7-maths-chapter-13-ex-13-1\/","title":{"rendered":"KSEEB Solutions for Class 7 Maths Chapter 13 Exponents and Powers Ex 13.1"},"content":{"rendered":"

Students can Download Chapter 13 Exponents and Powers Ex 13.1, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths<\/a>, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 7 Maths Chapter 13 Exponents and Powers Ex 13.1<\/h2>\n

Question 1.
\nFind the value of :
\n(i) 26<\/sup>
\n(ii) 93<\/sup>
\n(iii) 112<\/sup>
\n(iv) 54<\/sup>
\nSolution:
\ni) 26<\/sup>
\n26 <\/sup>= 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 = 64<\/p>\n

ii) 93<\/sup>
\n93 <\/sup>= 9 \u00d7 9 \u00d7 9 = 729<\/p>\n

iii) 112<\/sup>
\n112 <\/sup>= 11 \u00d7 11 = 121<\/p>\n

iv) 54<\/sup>
\n54 <\/sup>= 5 \u00d7 5 \u00d7 5 \u00d7 5 = 625.<\/p>\n

Question 2.
\nExpress the following in exponential form :
\n(i) 6 \u00d7 6 \u00d7 6 \u00d7 6
\n(ii) t \u00d7 t
\n(iii) b \u00d7 b \u00d7 b \u00d7 b
\n(iv) 5 \u00d7 5 \u00d7 7 \u00d7 7 \u00d7 7
\n(v) 2 \u00d7 2 \u00d7 a \u00d7 a
\n(vi) a \u00d7 a \u00d7 a \u00d7 c \u00d7 c \u00d7 c \u00d7 c \u00d7 d
\nSolution:
\ni) 6 \u00d7 6 \u00d7 6 \u00d7 6 = 64<\/sup><\/p>\n

ii) t \u00d7 t = t2<\/sup><\/p>\n

iii) b \u00d7 b \u00d7 b \u00d7 b = b4<\/sup><\/p>\n

iv) 5 \u00d7 5 \u00d7 7 \u00d7 7 \u00d7 7 = 52<\/sup> \u00d7 73<\/sup><\/p>\n

v) 2 \u00d7 2 \u00d7 a \u00d7 a = 22<\/sup> \u00d7 a2<\/sup><\/p>\n

vi) a \u00d7 a \u00d7 a \u00d7 c \u00d7 c \u00d7 c \u00d7 c \u00d7 d = a3<\/sup> \u00d7 c4<\/sup> \u00d7 d<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\nExpress each of the following numbers using exponential notation :
\n(i) 512
\n(ii) 343
\n(iii) 729
\n(iv) 3125
\nSolution:
\ni) 512 = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 = 29<\/sup>
\nThe exponential notation of 512 is 29<\/sup><\/p>\n

ii) 343 = 7 \u00d7 7 \u00d7 7 = 73<\/sup>
\n\u2234 The exponential notation of 343 is 73<\/sup><\/p>\n

iii) 729 = 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 = 36<\/sup>
\n\u2234 The exponential notation of 729 is 36<\/sup><\/p>\n

iv) 3125 = 5 \u00d7 5 \u00d7 5 \u00d7 5 \u00d7 5 = 55<\/sup>
\n\u2234 The exponential notation of 3125 is 55<\/sup><\/p>\n

Question 4.
\nIdentify the grater number, wherever possible, in each of the following ?
\nSolution:
\ni) 43<\/sup> or 34<\/sup>
\n43<\/sup> = 4 \u00d7 4 \u00d7 4 = 64
\n34<\/sup> = 3 \u00d7 3 \u00d7 3 \u00d7 3 = 81
\n\u2234 34<\/sup> > 43<\/sup><\/p>\n

ii) 53<\/sup> or 35<\/sup>
\n53<\/sup> = 5 \u00d7 5 \u00d7 5 = 125
\n35<\/sup> = 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 = 243
\n\u2234 35<\/sup> >53<\/sup><\/p>\n

iii) 28<\/sup> or 82<\/sup>
\n28<\/sup> = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 = 256
\n82<\/sup> = 8 \u00d7 8 = 64
\n\u2234 28<\/sup> > 82<\/sup><\/p>\n

iv) 1002<\/sup> or 2100<\/sup>
\n1002<\/sup> = 100 \u00d7 100= 10,000
\n28<\/sup> = (210<\/sup>)10<\/sup> = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2
\n\u00d7 2 \u00d7 2
\n= (1024)10<\/sup> = [(1024)2<\/sup>]5<\/sup> = [10,48,576]
\n= (10,48,476)5<\/sup> > 10,000
\n= 2100<\/sup> > 1002<\/sup><\/p>\n

\"KSEEB<\/p>\n

v) 210<\/sup> or 102<\/sup>
\n210<\/sup> = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 = 1024
\n102<\/sup> = 10 \u00d7 10 = 100
\n\u2234 210<\/sup> > 102<\/sup><\/p>\n

Question 5.
\nExpress each of the following as product of powers of their prime factors :
\nSolution:
\ni) 648
\n648 = 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3
\n= 23<\/sup> \u00d7 34<\/sup><\/p>\n

ii) 405
\n405 = 5 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3
\n= 5 \u00d7 34<\/sup><\/p>\n

iii) 540
\n540 = 2 \u00d7 2 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 5
\n= 22<\/sup> \u00d7 33<\/sup> \u00d7 5<\/p>\n

iv) 3,600
\n3,600 = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 3 \u00d7 5 \u00d7 5
\n= 24<\/sup> \u00d7 32<\/sup> \u00d7 52<\/sup><\/p>\n

Question 6.
\nSimplify :
\n(i) 2 \u00d7 103<\/sup>
\n(ii) 72<\/sup> \u00d7 22<\/sup>
\n(iii) 23<\/sup> \u00d7 5
\n(iv) 3 \u00d7 44<\/sup>
\n(v) 0 \u00d7 102<\/sup>
\n(vi) 52<\/sup> \u00d7 33<\/sup>
\n(vii) 24<\/sup> \u00d7 32<\/sup>
\n(viii) 32<\/sup> \u00d7 104<\/sup>
\nSolution:
\ni) 2 \u00d7 103<\/sup>
\n= 2 \u00d7 10 \u00d7 10 \u00d7 10 = 2,000<\/p>\n

ii) 72<\/sup> \u00d7 22<\/sup>
\n= 7 \u00d7 7 \u00d7 2 \u00d7 2
\n= 49 \u00d7 4 = 196<\/p>\n

\"KSEEB<\/p>\n

iii) 23<\/sup> \u00d7 5
\n= 2 \u00d7 2 \u00d7 2 \u00d7 5
\n= 8 \u00d7 5 = 40<\/p>\n

iv) 3 \u00d7 44<\/sup>
\n= 3 \u00d7 4 \u00d7 4 \u00d7 4 \u00d7 4
\n= 12 \u00d7 64 = 768<\/p>\n

v) 0 \u00d7 102<\/sup>
\n= 0 \u00d7 10 \u00d7 10 = 0<\/p>\n

vi) 52<\/sup> \u00d7 33<\/sup>
\n= 5 \u00d7 5 \u00d7 3 \u00d7 3 \u00d7 3
\n= 25 \u00d7 27 = 675<\/p>\n

vii) 24 \u00d7 32
\n=2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 3
\n= 16 \u00d7 9 = 144<\/p>\n

viii) 32 \u00d7 104<\/sup>
\n= 3 \u00d7 3 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10
\n= 90 \u00d7 1000 = 90,000<\/sup><\/p>\n

Question 7.
\nSimplify :
\nSolution:
\ni) (-4)3<\/sup>
\n(-4)3<\/sup> = (-4) \u00d7 (-4) \u00d7 (-4) = -64<\/p>\n

ii) (-3) \u00d7 (-2)3<\/sup>
\n= (-3) \u00d7 (-2) \u00d7 (-2) \u00d7 (-2) = (-3) \u00d7 (-8) = 24<\/p>\n

iii) (-3)2<\/sup> \u00d7 (-5)2<\/sup>
\n= (-3) \u00d7 (-3) \u00d7 (-5) \u00d7 (-5)
\n= 9 \u00d7 25 = 225<\/p>\n

iv) (-2)3<\/sup> \u00d7 (-10)3<\/sup>
\n= (-2) \u00d7 (-2) \u00d7 (-2) \u00d7 (-10) \u00d7 (-10) \u00d7 (-10)
\n= +4 \u00d7 -2 \u00d7 100 \u00d7 -10
\n= -8 \u00d7 -1000 = 8000<\/p>\n

\"KSEEB<\/p>\n

Question 8.
\nCompare the following numbers :
\nSolution:
\ni) 2 : 7 \u00d7 1012<\/sup> ; 1.5 \u00d7 108<\/sup>
\n= 2.7 \u00d7 1012<\/sup>
\n= 2.7 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10
\n= 2.70000000000000
\n= 27 \u00d7 1011<\/sup><\/p>\n

1.5 \u00d7 107<\/sup>
\n= 1.5 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10
\n= 1.5 \u00d7 107<\/sup>
\n\u2234 2.7 \u00d7 1012<\/sup> >1.5 \u00d7 108<\/sup><\/p>\n

ii) 4 \u00d7 1014<\/sup> ; 3 \u00d7 1017<\/sup>
\n=4 \u00d7 1014<\/sup> = 4 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10
\n= 4 \u00d7 1014<\/sup>
\n3 \u00d7 107<\/sup> = 3 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10
\n\u2234 3 \u00d7 1017<\/sup> > 4 \u00d7 1014<\/sup><\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Chapter 13 Exponents and Powers Ex 13.1, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 7 Maths Chapter 13 Exponents and Powers Ex 13.1 Question 1. Find the …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[84],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/16101"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=16101"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/16101\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=16101"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=16101"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=16101"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}