{"id":15887,"date":"2020-09-10T15:58:37","date_gmt":"2020-09-10T10:28:37","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=15887"},"modified":"2021-07-02T15:01:52","modified_gmt":"2021-07-02T09:31:52","slug":"kseeb-solutions-for-class-7-maths-chapter-12-ex-12-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-7-maths-chapter-12-ex-12-1\/","title":{"rendered":"KSEEB Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.1"},"content":{"rendered":"

Students can Download Chapter 12 Algebraic Expressions Ex 12.1, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths<\/a>, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.1<\/h2>\n

Question 1.
\nGet the algebraic expressions in the following cases using variables, constants and arithmetic operations.
\ni) Subtraction of z from y.
\nSolution:
\ny – z<\/p>\n

ii) One-half of the sum of numbers x and
\nSolution:
\n\"KSEEB<\/p>\n

iii) The number z multiplied by itself.
\nSolution:
\nZ \u00d7 Z = Z2<\/sup><\/p>\n

iv) One- fourth of the product of numbers p and q.
\nSolution:
\n\"KSEEB<\/p>\n

v) Numbers x and y both squared and added.
\nSolution:
\nx2<\/sup> + y2<\/sup><\/p>\n

vi) Number 5 added to three times the product of numbers m and n.
\nSolution:
\n3mn + 5<\/p>\n

vii) Product of numbers y and z subtracted from 10.
\nSolution:
\n10 – yz<\/p>\n

viii) Sum of numbers a and b subtracted from their product.
\nSolution:
\nab, – {a + b)<\/p>\n

\"KSEEB<\/p>\n

Question 2.
\ni) Identify the terms and their factors in the following expression show the terms and factors by tree diagrams.
\nSolution:
\n\"KSEEB<\/p>\n

c) y – y3<\/sup>
\nTerms: y; -y3<\/sup>
\n\"KSEEB
\nFactors : y ; -1, y,<\/p>\n

d) 5xy2<\/sup> + 7x2<\/sup>y
\nTerms : 5xy2<\/sup> ; 7x2<\/sup>y
\nFactors : 5, x, y, y; 7, x, x, y
\n\"KSEEB<\/p>\n

e) -ab + 2b2<\/sup> – 3a2<\/sup>
\nTerms : -ab ; 2b2<\/sup>; 3a2<\/sup>
\nFactors : 1, a, b ; 2, b, b ; -3, a, a
\n\"KSEEB<\/p>\n

ii) Identify terms and factors in the expressions given below :<\/p>\n

a) -4x + 5
\nTerms : -4x ; 5
\nFactors : -4, x; 5<\/p>\n

b) -4x + 5y
\nTerms : -4x ; 5y
\nFactors :-4, x; 5, y<\/p>\n

\"KSEEB<\/p>\n

c) 5y + 3y2<\/sup>
\nTerms : 5y ; 3y2<\/sup>
\nFactors : 5, y ; 3, y, y<\/p>\n

d) xy + 2x2<\/sup>y2<\/sup>
\nTerms : xy ; 2x2<\/sup>y2<\/sup>
\nFactors : x, y ; 2, x, x, y, y<\/p>\n

e) pq + q
\nTerms : pq ; q
\nFactors : p, q ; q<\/p>\n

f) 1.2 ab – 2.4b + 3.6a
\nTerms : 1.2 ab ; 2.4b ; 3.6a
\nFactors : 1.2, a, b ; -2.4, b ; 3.6, a<\/p>\n

g)
\n\"KSEEB
\nSolution:
\n\"KSEEB<\/p>\n

h) 0.1 p2<\/sup> + 0.2 q2<\/sup>
\nTerms : 0.1p2<\/sup>; 0.2q2<\/sup>
\nFactors : 0.1, p, p ; 0.2, q, q<\/p>\n

Question 3.
\nIdentify the numerical coefficients of terms (other than constants) in the following expressions :
\ni) 5 – 3t2<\/sup>
\nTerm other than constant = -3\/2
\nnumerical co-efficient = -3<\/p>\n

ii) 1 + t + t2<\/sup> + t3<\/sup>
\nTerm other than constant = t, t2<\/sup>, t3<\/sup>
\nNumerical co-efficients = 1, 1, 1.<\/p>\n

iii) x + 2xy + 3y
\nTerms other than constants = x, 2xy + 3y
\nNumerical co-efficients = 1, 2, 3<\/p>\n

iv) 100m + 1000n
\nTerms other than constants = 100m, 1000n
\nNumerical co-efficients = 100, 1000.<\/p>\n

\"KSEEB<\/p>\n

v) -p2<\/sup>q2<\/sup> + 7pq
\nTerms other than constants = -p2<\/sup> q2<\/sup>, 7 pq
\nNumerical co-efficients = -1, 7<\/p>\n

vi) 1.2a + 0.8b
\nTerms other than constants = 1.2a, 0.8b
\nNumerical co-efficients = 1.2, 0.8<\/p>\n

vii) 3.14 r2<\/sup>
\nTerms other than constants = 3.14r2<\/sup>
\nNumerical co-efficients = 3.14<\/p>\n

viii) 2 (l + b)
\nTerms other than constants = 2l, 2b
\n(\u2235 2(l + b) = 2l + 2b)
\nNumerical co-efficients = 2, 2<\/p>\n

ix) 0.1 y + 0.01 y2<\/sup>
\nTerms other than constants = 0.1 y, 0.01 y2<\/sup>
\nNumerical co-efficients = 0.1, 0.01<\/p>\n

\"KSEEB<\/p>\n

Question 4.
\na) Identify terms which contain x and give the coefficient of x.
\ni) y2<\/sup>x + y
\nTerms which contains x — y2<\/sup>
\nco-efficient of x — y2<\/sup><\/p>\n

ii) 13y2<\/sup> – 8yx
\nTerms which contains x — (x – 8yx)
\nco-efficient of x — (-8y)<\/p>\n

iii) x + y + 2
\nTerms which contains x —- x
\nco-efficient of x —- 1<\/p>\n

iv) 5 + z + zx
\nTerms which contains x — x
\nco-efficient of x — z<\/p>\n

v) 1 + x + xy
\nTerms which contains x — x and xy
\nco-efficient of x — 1 y<\/p>\n

vi) 12xy2<\/sup> + 25 — 12xy2<\/sup>
\nTerms which contains x
\nco-efficient of x — 12y2<\/sup><\/p>\n

vii) 7x + xy2<\/sup>
\n7x Terms which contains x
\nco-efficient of x —- 7
\nTerms which contains x — xy2<\/sup>
\ny2<\/sup> co-efficient of<\/p>\n

b) Identify terms which contain y2<\/sup> and give the coefficient of y\u2019.
\ni) 8 – xy2<\/sup>
\nTerms which contains y2<\/sup>
\nxy2<\/sup> co-efficient of y2<\/sup> — x<\/p>\n

ii) 5y2<\/sup> + 7x
\nTerms which contains y2<\/sup>
\nco-efficient of y2<\/sup> — 5<\/p>\n

iii) 2x2<\/sup> y – 15xy2<\/sup> + 7y2<\/sup>
\nTerms which contains y2<\/sup> — (-15xy2<\/sup>)
\nco-efficient of y2<\/sup> — (-15x)
\nTerms which contain y2<\/sup> — 7y2<\/sup>
\nco-efficient of y2<\/sup> —- 7<\/p>\n

\"KSEEB<\/p>\n

Question 5.
\nClassify into monomials, binomials and trinomials.
\ni) 4y – 7z
\nThis expression is binomial because it contains two terms. That is 4 y and -7z.
\nii) y2<\/sup>
\nThis is monomial expression because it contains only one term y2<\/sup>.
\niii) x + y – xy
\nThis is trinomial expression because it contains three terms x, y and -xy.
\niv) 100
\nThis is a monomial expression because it contains only one term 100.
\nv) ab – a – b
\nThis is trinomial expression because it contains 3 terms ab, -a and -b.
\nvi) 5 – 3t
\nThis is binomial expression because it contains 2 terms 5 and -3t.
\nvii) 4p2<\/sup>q – 4pq2<\/sup>
\nThis is binomial expression because it contains two terms 4p2<\/sup>q and – 4 pq2<\/sup>
\nviii) 7mn
\nThis is monomial expression because it contains only one term 7mn.
\nix) z2<\/sup> – 3z + 8
\nThis is trinomial expression because it contains three terms z2<\/sup>, -3z and 8.
\nx) a2<\/sup> + b2<\/sup>
\nThis is binomial expression because it contains two terms a2<\/sup> and b2<\/sup>.
\nxi) z2<\/sup> + z
\nThis is binomial expression because it contains 2 terms z2<\/sup> and z.
\nxii) 1 + x + x2<\/sup>
\nThis is trinomial expression because it contains 3 terms 1, x and x2<\/sup>.<\/p>\n

\"KSEEB<\/p>\n

Question 6.
\nState whether a given pair of terms is of like or unlike terms.
\ni) 1, 100
\nlike terms
\nii) \"KSEEB
\nlike terms
\niii) -29x, -29y
\nunlike terms
\niv) 14xy, 42yx
\nlike terms
\nv) 4m2<\/sup>p, 4mp2<\/sup>
\nunlike terms
\nvi) 12xz, 12x2<\/sup>z2<\/sup> unlike terms<\/p>\n

Question 7.
\nIdentify like terms in the following :
\na) -xy2<\/sup>, -4yx2<\/sup>, 8x2<\/sup>, 2xy2<\/sup>, 7y, – 11x2<\/sup>, 100x, – 11yx, 20x2<\/sup>y, -6x2<\/sup>, y, 2xy, 3x
\nSolutions:
\nLike terms are
\ni) -xy2<\/sup>, 2xy2<\/sup>
\nii) -4yx2<\/sup>, 20x2<\/sup>y
\niii) 8x2<\/sup>, -11x2<\/sup>, -6x2<\/sup>
\niv) 7y, y
\nv) -100x, 3x
\nvi) -11yx, 2xy<\/p>\n

b) 10pq, 7p, 8q, -p2<\/sup>q2<\/sup>, -7qp, – 100q, -23, 12q2<\/sup>p2<\/sup>, -5p2<\/sup>, 41, 2405p, 75qp, 13p2<\/sup>q, qp2<\/sup>, 701p2
\n<\/sup>Solution:
\nlike terms are
\ni) 10pq, – 7qp, 78qp,
\nii) 7p, 2405p,
\niii) 8q, -100q
\niv) -23, 41,
\nv) 12q2<\/sup>p2<\/sup>, -p2<\/sup>q2<\/sup>,
\nvi) -5p2<\/sup>, 701p2<\/sup>,
\nvii) 13p2<\/sup>q, qp2<\/sup><\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Chapter 12 Algebraic Expressions Ex 12.1, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.1 Question 1. Get the algebraic expressions …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[84],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/15887"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=15887"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/15887\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=15887"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=15887"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=15887"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}