{"id":15569,"date":"2020-09-10T16:23:22","date_gmt":"2020-09-10T10:53:22","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=15569"},"modified":"2021-07-02T15:01:52","modified_gmt":"2021-07-02T09:31:52","slug":"kseeb-solutions-for-class-7-maths-chapter-10-ex-10-5","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-7-maths-chapter-10-ex-10-5\/","title":{"rendered":"KSEEB Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5"},"content":{"rendered":"

Students can Download Chapter 10 Practical Geometry Ex 10.5, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths<\/a>, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 7 Maths Chapter 10 Practical Geometry Ex 10.5<\/h2>\n

Question 1.
\nConstruct the right angled \u2206 PQR? where m\u2220Q = 90\u00b0, QR = 8 cm and PR = 10 cm.
\nSolution:
\n\"KSEEB
\nSolution:
\nSteps of Construction<\/p>\n

    \n
  1. Draw a line segment of length 8 cm and named as QR. At Q draw QM \u22a5 QR.<\/li>\n
  2. With R as centre, draw an arc of radius 10 cm and cut the \u22a5le<\/sup> line at P.<\/li>\n
  3. Join PR. Now we get the required PQR \u2206<\/li>\n<\/ol>\n

    \"KSEEB<\/p>\n

    Question 2.
    \nConstruct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4
    \ncm long.
    \nSolution:
    \n\"KSEEB
    \nSteps of Construction<\/p>\n

      \n
    1. Draw a line segment of length 4 cm and named it AB. At A draw a \u22a5 line AM.<\/li>\n
    2. With B as centre, draw an arc of 6 cms cut the x line at \u2018C \u2019. Now we obtained the required triangle ABC.<\/li>\n<\/ol>\n

      \"KSEEB<\/p>\n

      Question 3.
      \nConstruct an isosceles right-angled triangle ABC, where m\u2220ACB = 90\u00b0 and AC = 6 cm.
      \nSolution:
      \n\"KSEEB
      \nSteps of Construction<\/p>\n

        \n
      1. Draw a line segment of 6 cm, ie., AC. At C draw CM \u22a5 CA.<\/li>\n
      2. With \u2018C\u2019 as the centre draw an arc of radius 6 cm to intersect CM at \u2018B’<\/li>\n
      3. Join AB. Now we get the required \u2206ACB.<\/li>\n<\/ol>\n","protected":false},"excerpt":{"rendered":"

        Students can Download Chapter 10 Practical Geometry Ex 10.5, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 Question 1. Construct the right angled …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[84],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/15569"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=15569"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/15569\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=15569"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=15569"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=15569"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}