{"id":15523,"date":"2020-09-10T15:46:32","date_gmt":"2020-09-10T10:16:32","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=15523"},"modified":"2021-07-02T15:01:53","modified_gmt":"2021-07-02T09:31:53","slug":"kseeb-solutions-for-class-7-maths-chapter-10-ex-10-2","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-7-maths-chapter-10-ex-10-2\/","title":{"rendered":"KSEEB Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2"},"content":{"rendered":"

Students can Download Chapter 10 Practical Geometry Ex 10.2, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths<\/a>, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 7 Maths Chapter 10 Practical Geometry Ex 10.2<\/h2>\n

Question 1.
\nConstruct \u2206 XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.
\nSolution:
\n\"KSEEB
\nSteps of Construction<\/p>\n

    \n
  1. Draw a line segment YZ of length 5 cm with Y as centre, draw an arc of radius 4.5 cm.<\/li>\n
  2. With Z as centre, draw an arc of radius 6cms which cuts the first arc. Mark the point of intersection of arcs as X.<\/li>\n
  3. Join XY and XZ. \u2206 XYZ is the required triangle.<\/li>\n<\/ol>\n

    \"KSEEB<\/p>\n

    Question 2.
    \nConstruct an equilateral triangle of side 5.5 cm.
    \nSolution:
    \nSteps of Constructions
    \n\"KSEEB<\/p>\n

      \n
    1. Draw a line segment BC of length 5.5 cms. with \u2018B\u2019 as centre draw an arc of radius 5.5 cm.<\/li>\n
    2. With \u2018C\u2019 as centre, Cut the first arc with radius 5.5 cms. Mark the point of intersection of arcs as \u2018A\u2019<\/li>\n
    3. Join AB and AC. \u2206 ABC is the required equilateral triangle.<\/li>\n<\/ol>\n

      Question 3.
      \nDraw \u2206 PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this ?
      \nSolution:
      \n\"KSEEB
      \nSteps of Construction<\/p>\n

        \n
      1. Draw a line segment QR of length 3.5 cm with Q as centre, draw an arc of radius 4 cm.<\/li>\n
      2. With R as centre, cut the first arc with a radius 4 cm. Mark the point of intersection of arcs as P.<\/li>\n
      3. Join PQ & PR A PQR is an isosceles triangle PQ = PR.<\/li>\n<\/ol>\n

        \"KSEEB<\/p>\n

        Question 4.
        \nConstruct \u2206 ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure <B.
        \nSolution:
        \nSteps of Construction<\/p>\n

          \n
        1. Draw a line segment BC of length 6 cm with \u2018B\u2019 as centre, draw an arc of radius 2.5 cm.<\/li>\n
        2. With \u2018C\u2019 as centre cut the first arc with a radius 6.5 cm.<\/li>\n
        3. Mark the point of intersection of arcs as A. Join AB & AC. \u2206 ABC is the required triangle.\"KSEEB<\/li>\n<\/ol>\n","protected":false},"excerpt":{"rendered":"

          Students can Download Chapter 10 Practical Geometry Ex 10.2, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 7 Maths Chapter 10 Practical Geometry Ex 10.2 Question 1. Construct \u2206 XYZ in …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[84],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/15523"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=15523"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/15523\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=15523"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=15523"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=15523"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}