{"id":15508,"date":"2020-09-10T15:39:23","date_gmt":"2020-09-10T10:09:23","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=15508"},"modified":"2021-07-02T15:01:53","modified_gmt":"2021-07-02T09:31:53","slug":"kseeb-solutions-for-class-7-maths-chapter-10-ex-10-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-7-maths-chapter-10-ex-10-1\/","title":{"rendered":"KSEEB Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1"},"content":{"rendered":"

Students can Download Chapter 10 Practical Geometry Ex 10.1, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths<\/a>, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 7 Maths Chapter 10 Practical Geometry Ex 10.1<\/h2>\n

Question 1.
\nDraw a line, say AB, take a point C out-side it. Through C, draw a line parallel to AB using ruler and compasses only.
\nSolution:
\n\"KSEEB
\nSteps of Construction<\/u><\/p>\n

    \n
  1. Draw a line AB. Take a point C outside it. Take any point D on AB and join C to D.<\/li>\n
  2. With D as centre and a convenient radius, draw an arc cutting AB at F and CD at E.<\/li>\n
  3. Now with C as centre and the same radius as in step 2, draw an arc GH cutting CD at I.<\/li>\n
  4. Place the pointed tip of the compasses at F and adjust the opening so that the pencil tip is at E.<\/li>\n
  5. With the same opening as in step 4 and with I as centre, draw an arc cutting the are GH at J.<\/li>\n
  6. Now Join CJ to draw a line \u2018KL\u2019<\/u>. KL<\/u> is the required parallel line.<\/li>\n<\/ol>\n

    \"KSEEB<\/p>\n

    Question 2.
    \nDraw a line l. Draw a perpendicular to l at any point on l. On this perpendicular choose a point X, 4 cm away from l. Through X, draw a line m parallel to l.
    \nSolution:
    \n\"KSEEB
    \nSteps of Construction<\/p>\n

      \n
    1. Draw a line l, take any point A on line l.<\/li>\n
    2. Construct an angle of 90\u00b0 at point A of line l and draw a line AL perpendicular to line l.<\/li>\n
    3. Mark a point X on AL such that AX = 4 cm<\/li>\n
    4. At X construct an angle of 90\u00b0 and draw a line XC perpendicular to line AL.<\/li>\n
    5. The line XC (line m) is the required line through X such that m || l.<\/li>\n<\/ol>\n

      \"KSEEB<\/p>\n

      Question 3.
      \nLet l be a line and P be a point on l. Through P, draw a line m parallel to l. Now join P to any point Q on l. Choose any other point R on m. Through R, draw a line parallel to PQ. Let this meet l at S. What shape do the two sets of parallel lines enclose?
      \nSolution:
      \n\"KSEEB
      \nSteps of constructions<\/p>\n

        \n
      1. Draw a line l and take a point P, not on it. Take any point Q on l. Join Q to P<\/li>\n
      2. Draw a line m parallel to the line l, as shown in the figure. line m || line l.<\/li>\n
      3. Join P to any point Q on l.<\/li>\n
      4. Choose any point R on m & Join R to Q.<\/li>\n
      5. Through R, draw a line n parallel to the line PQ. Let the line n meet the line l at S.<\/li>\n
      6. The shape enclosed by the two sets of parallel lines is a parallelogram.<\/li>\n<\/ol>\n","protected":false},"excerpt":{"rendered":"

        Students can Download Chapter 10 Practical Geometry Ex 10.1, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 7 Maths Chapter 10 Practical Geometry Ex 10.1 Question 1. Draw a line, say …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[84],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/15508"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=15508"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/15508\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=15508"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=15508"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=15508"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}