{"id":14842,"date":"2020-09-09T17:14:29","date_gmt":"2020-09-09T11:44:29","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=14842"},"modified":"2021-07-02T15:01:54","modified_gmt":"2021-07-02T09:31:54","slug":"kseeb-solutions-for-class-7-maths-chapter-4-ex-4-4","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-7-maths-chapter-4-ex-4-4\/","title":{"rendered":"KSEEB Solutions for Class 7 Maths Chapter 4 Simple Equations Ex 4.4"},"content":{"rendered":"

Students can Download Chapter 4 Simple Equations Ex 4.4, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths<\/a>, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 7 Maths Chapter 4 Simple Equations Ex 4.4<\/h2>\n

Question 1.
\nSet up equations and solve them to find the unknown numbers in the following cases :
\na) Add 4 to eight times a number; you get 60.
\nSolution:
\nLet the unknown number be’x’
\n8 times a number be 8x
\nAccording to the question
\n8x + 4 = 60
\n8x = 60 – 4
\n8x = 56
\n\"KSEEB
\n\u2234 The unknown number x be 7<\/p>\n

b) One-fifth of a number minus 4 gives 3.
\nSolution:
\nLet the unknown number be x
\nThen according to the question
\n\"KSEEB
\n\u2234 That unknown number be 35.<\/p>\n

c) If I take three-fourths of a number and add 3 to it, I get 21.
\nSolution:
\nLet the unknown number be x
\nAccording to the question
\n\"KSEEB
\n\u2234 That unknown number be 24.<\/p>\n

\"KSEEB<\/p>\n

d) When I subtracted 11 from twice a number, the result was 15.
\nSolution:
\nLet the unknown number be x According to the question
\n2x – 11 = 15
\n2x = 15 + 11
\n2x = 26
\n\"KSEEB
\n\u2234 That unknown number be 13.<\/p>\n

e) Munna subtracts thrice the number of notebooks he has from 50, he finds the result to be 8.
\nSolution:
\nLet the unknown number be x
\nAccording to the question
\n50 – 3x = 8
\n– 3x = 8 – 50
\n\"KSEEB
\nTherefore that unknown number be 14.<\/p>\n

f) Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.
\nSolution:
\nLet the unknown number be x
\nAccording to the question
\n\"KSEEB
\n\u2234 That unknown number be 21<\/p>\n

\"KSEEB<\/p>\n

g) Anwar thinks of a number. If he takes away 7 from \\(\\frac{5}{2}\\) of the number, the result is 23.
\nSolution:
\nLet the unknown number be x
\nAccording to the question
\n\"KSEEB
\nThat unknown number be 12<\/p>\n

Question 2.
\nSolve the following :
\na) The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest score is 87. What is the lowest score?
\nSolution:
\nLet the lowest score be x
\nAccording to the question
\n2x + 7 = 87
\n2x = 87 – 7 = 80
\nx = 80\/2 = 40 x = 40
\n\u2234 The lowest score be 40.<\/p>\n

\"KSEEB<\/p>\n

b) In an isosceles triangle, the base angles are equal. The vertex angle is 40\u00b0. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180\u00b0).
\nSolution:
\nLet the base angles of an isosceles triangle be x\u00b0
\nAccording to the question
\n2x\u00b0 + 40\u00b0 = 180\u00b0
\n2x\u00b0 = 180\u00b0 – 40\u00b0
\n2x\u00b0= 140
\n\"KSEEB
\nThe base angles are 70\u00b0 and 70\u00b0<\/p>\n

c) Sachin scored twice as many runs as Rahul. Together, their runs fell two short of a double century. How many runs did each one score?
\nSolution:
\nLet the score of Rahul be \u2018x\u2019 runs
\nAccording to the question
\nx + 2x = 198
\n3x = 198
\n\"KSEEB
\n\u2234 Rahul’s score = x = 66 runs
\nSachins score = 2x = 2 \u00d7 66 = 132 runs<\/p>\n

Question 3.
\nSolve the following :<\/p>\n

i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. How many marbles does Parmit have?
\nSolution:
\nLet Parmits marble be x
\nAccording to the question
\n5x + 7 = 37
\n5x = 37 – 7 = 30
\n\"KSEEB
\n\u2234 Parmits marble be = x = 6<\/p>\n

ii) Laxmi\u2019s father is 49 years old. He is 4 years older than three times Laxmi\u2019s age. What is Laxmi\u2019s age?
\nSolution:
\nLet the age of Laxmi be \u2018x\u2019 years
\nAccording to the question
\n3x + 4 = 49
\n3x = 49 \u2013 4 = 45
\n3x = 45
\nx = 45\/3 = 15
\n\u2234 Lakshmi\u2019s age is x = 15 years.<\/p>\n

\"KSEEB<\/p>\n

iii) People of Sundargram planted trees in the village garden. Some of the trees were fruit trees. The number of non-fruit trees were two more than three times the number of fruit trees. What was the number of fruit trees planted if the number of non-fruit trees planted was 77?
\nSolution:
\nLet the number of fruit trees be \u2018x\u2019
\nAccording to the question
\n3x + 2 = 77
\n3x = 77 – 2 = 75
\n\"KSEEB
\n\u2234 No. of fruit trees = x = 25<\/p>\n

Question 4.
\nSolve the following riddle :
\nI am a number, Tell my identity!
\nTake me seven times over And add a fifty!
\nTo reach a triple century You still need forty!
\nSolution:
\nLet the number be \u2018x\u2019
\nAccording to the question
\n7x + 50 = 300 – 40
\n7x + 50 = 260
\n7x = 260 – 50 = 210
\n\"KSEEB
\n\u2234 That number be x = 30<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Chapter 4 Simple Equations Ex 4.4, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 7 Maths Chapter 4 Simple Equations Ex 4.4 Question 1. Set up equations and …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[84],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/14842"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=14842"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/14842\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=14842"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=14842"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=14842"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}