{"id":13732,"date":"2020-09-09T11:25:47","date_gmt":"2020-09-09T05:55:47","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=13732"},"modified":"2021-07-02T15:03:35","modified_gmt":"2021-07-02T09:33:35","slug":"kseeb-solutions-for-class-7-maths-chapter-1-ex-1-2","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-solutions-for-class-7-maths-chapter-1-ex-1-2\/","title":{"rendered":"KSEEB Solutions for Class 7 Maths Chapter 1 Integers Ex 1.2"},"content":{"rendered":"

Students can Download Chapter 1 Integers Ex 1.2, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths<\/a>, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations.<\/p>\n

Karnataka State Syllabus Class 7 Maths Chapter 1 Integers Ex 1.2<\/h2>\n

Question 1.
\nWrite down a pair of integers whose:<\/p>\n

a) sum is – 7
\n– 2 + – 5 = – 7
\n\u2234 The two integers be – 2 and – 5.<\/p>\n

b) difference is – 7
\n– 20 – (- 10) = – 10 (\u2235 – 20 – (- 10))
\n– 20 + 10 = – 10
\n\u2234 The two integers be – 20 and – 10.<\/p>\n

c) sum is 0
\nAny two integers of same number but different sign.
\nFor eg : 10 + (- 10) = 0.<\/p>\n

\"KSEEB<\/p>\n

Question 2.
\na) Write a pair of negative integers whose difference gives 8.
\nSolution:
\nLet -4 and -12 are two negative integers.
\n\u2234 -4 – (-12)
\n-4 + 12 = 8<\/p>\n

b) Write a negative integer and a positive integer whose sum is -5.
\nSolution:
\nLet -10 and 5
\n\u2234\u00a0 -10 + 5 = -5<\/p>\n

c) Write a negative integer and a positive integer whose difference is -3.
\nSolution:
\nLet -2 and 1
\n-2 – (+1)
\n-2 – 1 = -3<\/p>\n

\"KSEEB<\/p>\n

Question 3.
\nIn a quiz, team A scored -40, 10, 0 and team B scored 10, 0, – 40 in three successive rounds. Which team scored more? Can we say that we can add integers in any order?
\nSolution:
\nTeam A scored = – 40 + 10 + 0 = – 30
\nTeamB scored = 10 + 0 – 40 = – 30
\nYes. We can add integers in any order.<\/p>\n

Question 4.
\nFill in the blanks to make the following statements true :
\ni) (-5) + (-8) = (-8) + (……..)
\n(-5) + (-8) = (-8) + (-5)<\/u><\/p>\n

ii) 53 + = – 53
\n-53 + 0<\/u> = -53<\/p>\n

\"KSEEB<\/p>\n

iii) 17 + …. 0
\n17 + -17<\/u> = 0<\/p>\n

iv) 113 + (-12) + (……) = 13 + [(-12) + (-7)]
\n[13 + (-12) + (-7)<\/u> = 13 + [(-12) + (-7)]<\/p>\n

v) (-4) + [15 + (-3)] = [-4 + 15] + -3<\/u>
\n(-4) + [15 + (-3)] = [-4 + 15] + -3.<\/u><\/p>\n","protected":false},"excerpt":{"rendered":"

Students can Download Chapter 1 Integers Ex 1.2, Question and Answers, Notes Pdf, KSEEB Solutions for Class 7 Maths, Karnataka State Board Solutions help you to revise complete Syllabus and score more marks in your examinations. Karnataka State Syllabus Class 7 Maths Chapter 1 Integers Ex 1.2 Question 1. Write down a pair of integers …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[84],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/13732"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=13732"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/13732\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=13732"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=13732"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=13732"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}