{"id":1268,"date":"2020-09-15T07:27:45","date_gmt":"2020-09-15T01:57:45","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=1268"},"modified":"2021-07-02T15:01:51","modified_gmt":"2021-07-02T09:31:51","slug":"kseeb-sslc-class-10-maths-solutions-chapter-9-ex-9-1","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-sslc-class-10-maths-solutions-chapter-9-ex-9-1\/","title":{"rendered":"KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1"},"content":{"rendered":"

KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1<\/strong> are part of KSEEB SSLC Class 10 Maths Solutions<\/a>. Here we have given Karnataka SSLC Class 10 Maths Solutions Chapter 9 Polynomials Exercise 9.1.<\/p>\n

Karnataka SSLC Class 10 Maths Solutions Chapter 9 Polynomials Exercise 9.1<\/h2>\n

Question 1.
\nThe graph of y = p(x) are given in the following figure, for some polynomials p(x). Find the number of zeros of p(x) in each case.
\n\"KSEEB
\nSolution:
\n(i) Graph of y = p(x) will not intersects x-axis.
\n\u2234 No zero for this polynomial.
\n\"KSEEB
\n<\/span><\/p>\n

(ii) Graph of y = p(x) intersects x-axis at only one point.
\n<\/span>\u2234<\/span> Only one zero is there for this polynomial.
\n\"KSEEB
\n<\/span><\/p>\n

(iii) y = p(x) intersects x-axis at 3 points.
\n\u2234 It has 3 zeroes.
\n<\/span>\"KSEEB<\/p>\n

\"KSEEB<\/p>\n

(iv) y = p(x) intersects x-axis at 2 points.
\n\u2234 Two zeroes for this polynomial.
\n<\/span>\"KSEEB<\/p>\n

(v) y = p(x) intersects x-axis at four (4) points.
\n\u2234 Four zeroes for this polynomial.
\n<\/span>\"KSEEB<\/p>\n

(vi) y = p(x) intersects x-axis at three (3) points.
\n\u2234 This polynomial has 3 zeroes.
\n<\/span>\"KSEEB<\/p>\n

We hope the given KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 will help you. If you have any query regarding Karnataka SSLC Class 10 Maths Solutions Chapter 9 Polynomials Exercise 9.1, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"

KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 are part of KSEEB SSLC Class 10 Maths Solutions. Here we have given Karnataka SSLC Class 10 Maths Solutions Chapter 9 Polynomials Exercise 9.1. Karnataka SSLC Class 10 Maths Solutions Chapter 9 Polynomials Exercise 9.1 Question 1. The graph of y = p(x) are …<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/1268"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=1268"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/1268\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=1268"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=1268"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=1268"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}