{"id":1013,"date":"2020-09-15T07:06:51","date_gmt":"2020-09-15T01:36:51","guid":{"rendered":"https:\/\/kseebsolutions.guru\/?p=1013"},"modified":"2021-07-02T15:01:51","modified_gmt":"2021-07-02T09:31:51","slug":"kseeb-sslc-class-10-maths-solutions-chapter-15-ex-15-4","status":"publish","type":"post","link":"https:\/\/kseebsolutions.guru\/kseeb-sslc-class-10-maths-solutions-chapter-15-ex-15-4\/","title":{"rendered":"KSEEB SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Ex 15.4"},"content":{"rendered":"

KSEEB SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Ex 15.4<\/strong>\u00a0are part of KSEEB SSLC Class 10 Maths Solutions<\/a>. Here we have given Karnataka SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Exercise 15.4.<\/p>\n

Karnataka SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Exercise 15.4<\/h2>\n

(Use \u03c0 = \\(\\frac{22}{7}\\) unless stated otherwise.)<\/p>\n

Question 1.
\nA drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass.
\nSolution:
\nHeight of drinking glass, h = 14 cm.
\nDiameter of circular ends
\nD = 4 cm \u2234 r = 2 cm.
\nd = 2 cm \u2234 r = 1 cm.
\nCapacity of glass = ?
\n\"KSEEB
\nVolume of glass = Radius with 2 cm + Volume of frustum with radius 1 cm.
\n\"KSEEB
\n\"KSEEB<\/p>\n

Question 2.
\nThe slant height of a frustum of a cone is 4 cm and the perimeters (circumference) of its ciruclar ends are 18 cm and 6 cm. Find the curved surface area of the frustum.
\nSolution:
\nSlant height of a i frustum of a cone, l = 4 cm.
\nCircumference of its circular ends = 18 cm. and 6 cm
\n\"KSEEB
\n2\u03c0r =18 cm.
\n\u2234 R = \\(\\frac{9}{\\pi}\\) cm.
\n2\u03c0r = 6
\n\u2234 r = \\(\\frac{3}{\\pi}\\) cm.
\n\u2234 Lateral surface area of a frustum of a Cone
\n\"KSEEB<\/p>\n

Question 3.
\nA fez, the cap used by the Turks, is shaped like the frustum of a cone (see the figure).
\n\"KSEEB
\nIf its radius on the open side is 10 cm, radius at the upper base is 4 cm, and its slant height is 15 cm, find the area of material used for making it.
\nSolution:
\nRadius on the open side of the cap, R = 10 cm.
\nRadius of upper end, r = 4 cm.
\nSlant height l = 15 cm
\n\"KSEEB
\nR = 10 cm, r = 4 cm, l = 15 cm
\n\u2234 Curved surface = \u03c0 \u00d7 l \u00d7 (R + r)
\n= \u03c0 \u00d7 15 \u00d7 (10 + 4)
\n= \\(\\frac{22}{7}\\) \u00d7 15 \u00d7 14
\n= 660 cm2<\/sup>
\n\u2234 Area of the cap at the end
\n\"KSEEB
\n\u2234 Area of material used for making it.
\n\"KSEEB<\/p>\n

Question 4.
\nA container, opened from the top and made up of a metal sheet, is in the form of a frustum of a cone of height 16 cm with radii of its lower and upper ends as 8 cm and 20 cm, respectively. Find the cost of the milk which can completely fill the container, at the rate of Rs. 20 per litre. Also find the cost of the metal sheet used to make the container, if it costs Rs. 8 per 100 cm2. (Take \u03c0 = 3.14).
\nSolution:
\n\"KSEEB
\nR = 20 cm
\nr = 8 cm
\nh = 20 cm
\n\u2234 Slant height,
\n\"KSEEB
\n\u2234 Volume of metallic sheet,
\n\"KSEEB
\nQuantity of milk in the container
\n= \\(\\frac{10449.82}{1000}\\)
\nCost of 1 litre of milk is Rs. 20,
\nCost of 10.45 litres of milk ……. ??
\n\u2234 20 \u00d7 10.45 = Rs. 209.
\nCost of metal sheet = \u03c0(R + r) + \u03c0r2<\/sup>
\n= \u03c0 {20 \u00d7 (20 + 8) + (8)2<\/sup>}
\n= 3.14 \u00d7 624
\n= 1959.36 cm2<\/sup>.
\n\u2234 Cost of preparing metallic container: For 100 cm2<\/sup> Rs. 8
\n\u2234 For 1959.36 cm2<\/sup> ……?
\n= 8 \u00d7 \\(\\frac{1159.36}{100}\\)
\n= Rs. 156.75.<\/p>\n

Question 5.
\nA metallic right circular cone 20 cm high and whose vertical angle is 60\u00b0 is cut into two parts at the middle of its height by a plane parallel to its base. If the frustum so obtained be drawn into a wire of diameter \\(\\frac{1}{16}\\) cm., find the length of the wire.
\nSolution:
\nHeight of a cone, h = 20 cm.
\nVertical angle = 60\u00b0
\n\"KSEEB
\nDiameter of frustum wire = \\(\\frac{1}{16}\\) cm.
\ni) In \u22a5\u2206AQC, \u2220Q = 90\u00b0
\n\"KSEEB
\nii) In \u22a5\u2206PRA, \u2220R = 90\u00b0
\n\"KSEEB
\nHeight of frustum, h = 10 cm.
\n\u2234 Volume of metallic frustum, ABCD,
\n\"KSEEB
\nLet the length of wire which has diameter \\(\\frac{1}{16}\\) cm be ‘x’ cm
\n\"KSEEB
\n\u2234 Length of wire = 7964.4 m<\/p>\n

We hope the given KSEEB SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Ex 15.4 will help you. If you have any query regarding Karnataka SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Exercise 15.4, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"

KSEEB SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Ex 15.4\u00a0are part of KSEEB SSLC Class 10 Maths Solutions. Here we have given Karnataka SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Exercise 15.4. Karnataka SSLC Class 10 Maths Solutions Chapter 15 Surface Areas and Volumes Exercise 15.4 (Use …<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/1013"}],"collection":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/comments?post=1013"}],"version-history":[{"count":0,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/posts\/1013\/revisions"}],"wp:attachment":[{"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/media?parent=1013"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/categories?post=1013"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kseebsolutions.guru\/wp-json\/wp\/v2\/tags?post=1013"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}