Students can Download Maths Chapter 2 Algebraic Expressions Ex 2.3 Questions and Answers, Notes Pdf, KSEEB Solutions for Class 8 Maths helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka Board Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3

Question 1.

Complete the following table of products of two monomials

First → Second ↓ |
3x | -6y | 4x^{2} |
– 8xy | 9x^{2}y |
-11 x^{3}y^{2} |

3x | 9x^{2} |
-18xy | 12x^{3} |
-24x^{:}y |
27x^{3}y |
-33x^{4}y^{2} |

-6y | -18xy | 36y^{2} |
-24x^{2}y |
48xy- | -54x^{2}y^{2} |
66x^{3}y^{3} |

4x- | I2x^{3} |
-24x^{2}y |
I6x^{4} |
-32x^{3}y^{2} |
36x^{4}y |
-44x^{3}y^{2} |

-8xy | -24x^{2}y |
48xy^{2} |
-32x^{3}y |
64x^{2}y^{2} |
-72x^{3}y^{2} |
88x^{4}y^{3} |

9x^{2}y |
27x^{3}y |
-54x^{2}y^{2} |
36x^{4}y |
-72xy | 81x^{4}y^{2} |
-99 x^{3}y^{3} |

-11 x^{3}y^{2} |
-33x^{4}y^{3} |
66 x^{2}y^{3} |
-44 x^{5}y^{2} |
88 x^{4}y^{3} |
-99 x^{5}y^{3} |
121 x^{6}y^{4} |

Question 2.

Find the products

i. (5x + 8) 3x

ii. (-3 pq)(-15 p^{3}q² – q^{3})

iii. \(\frac{2 x}{5}\left(3 a^{3}-3 b^{3}\right)\)

iv. -x²(x – 15)

Answer:

i. 5x . 3x + 8.3x = 15x² + 24x

ii. (- 3pq) (- 15p^{3}q² – q^{3})

= (- 3pq) (- 15p^{3}q²) – (- 3pq)(q^{3})

= 45 p^{4}q^{3} + 3 pq^{4}

iii. \(\frac{2 x}{5} \times 3 a^{3}-\frac{2 x}{5} \times 3 b^{3}=\frac{6 x a^{3}}{5}-\frac{6 x b^{3}}{3}\)

iv. (-x²)x – (-x²) 15

= -x^{3} + 15x²

Question 3.

Simplify the following :

i. (2xy -xy) (3xy – 5)

ii. (3xy² +1) (4xy – 6xy²)

iii. (3x² + 2x) (2x² + 3)

iv. (2m^{3} + 3m) (5m – 1)

Answer:

i. 2x y (3xy – 5) – 2xy(3xy – 5) = 6x²y² – 10xy – 6x²y² + 10xy

ii. 3xy² (4xy – 6xy²) +1 (4xy – 6xy²) = 12 x²y3 – 18x²y4 + 4xy – 6xy²

iii. 3x²(2x² + 3) + 2x(2x² + 3] = 6x^{4} + 9x² + 4x^{3} + 6x

iv. 2m^{3 }(5m – 1) + 3m(5m – 1) = 10m^{4} – 2m^{3 }+ 15m² – 3m