Students can Download Maths Chapter 4 Determinants Ex 4.6 Questions and Answers, Notes Pdf, 2nd PUC Maths Question Bank with Answers helps you to revise the complete Karnataka State Board Syllabus and score more marks in your examinations.

## Karnataka 2nd PUC Maths Question Bank Chapter 4 Determinants Ex 4.6

### 2nd PUC Maths Determinants NCERT Text Book Questions and Answers Ex 4.6

Examine the consistency of the system of equations.

Question 1.

x + 2y = 2

2x + 3y =2

Answer:

hence consistence and unique solution.

Question 2.

2x – y = 5

x + y = 4

Answer:

hence system is consistent and has unique solution

Question 3.

x + 3y = 5

2x + 6y = 8

Answer:

Question 4.

x + y + z = 1

2x + 3y + 22 = 2

ax + ay + 2az = 4

Answer:

case (i).

If a ≠ 0,

The system is consistent and unique solution

case ii. If a = 0 we can’t say any thing about

consistency

Now we find whether

(Adj A) B is zero or not

Question 5.

3x – y – 2z = 2

2y – z = -1

3x – 5y = 3

Answer:

Question 6.

5x – y + 4z = 5

2x + 3y + 5z = 2

5x – 2y + 6z = -1

Answer:

Solve the system of linear equations (7 – 14)

Question 7.

5x + 2y = 4

7x + 3y = 5

Answer:

Question 8.

2x – y = -2

3x + 4y = 3

Answer:

Question 9.

4x – 3y = 3

3x – 5y = 7

Answer:

Question 10.

5x + 2y = 3

3x + 2y = 5

Answer:

Question 11.

2x + y + z = 1

x – 2y – z = \(\frac{3}{2}\)

3v – 5z =9

Answer:

Question 12.

x – y + z = 4

2x + y – 3z = 0

x + y + z = 2

Answer:

Question 13.

2x + 3y + 3z = 5

x – 2y + z = -4

3x – y – 22 = 3

Answer:

Question 14.

x – y + 2z = 7

3x + 4y – 5z = -5

2x – y + 3z = 12

Answer:

Question 15.

\(A=\left[\begin{array}{ccc}{2} & {-3} & {5} \\{3} & {2} & {-4} \\{1} & {1} & {-2}\end{array}\right]\) find A^{-1 }using A^{-1 }solve

2x – 3y + 5z = 11

3x + 2y – 4z = -5

x + y – 2z = -3

Answer:

Question 16.

The cost of 4 kg onion, 3kg wheat and 2 kg rice is 60/-

The cost of 2 kg onion, 4 kg wheat and 6 kg rice is 90/-

The cost of 6 kg onion, 2kg wheat and 3kg rice is 70/-

Find the cost of each item per kg by matrix method.

Answer:

Let the cost of onion be ₹ y/-

Let the cost of wheat be ₹x/-

Let the cost of rice be ? ₹ z/-

4x + 3y + 2z = 60

2x + 4y + 6z = 90

6x + 2y + 3z = 70

AX = B ⇒ X = A^{-1}B